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32 Threads found on edaboard.com: **Cos Cos Theta**

Dear fellows.
I have to make M points in a circle with radius
0.1Rd 0.5R.
I have the code for circle but not getting the meaning of 0.1d and 0.5d
I have code for circle as follows.
% Data
n = 10;
radius = rand;
xc = randn;
yc = randn;
% Engine
**theta** = rand(1,n)*(2*pi);
r = sqrt(rand(1,n))*radius;
x = xc + (...)

Digital communication :: 07-28-2015 03:47 :: rohit543 :: Replies: **0** :: Views: **233**

Hi,
I'm trying to plot the far-field radiation pattern of a thin wire dipole antenna using the equation I found on balanis book(antenna theory, 3rd edition, section 4.5.2):
E_{\**theta**} = j{\eta}\frac{ke^{-jkr}}{4{\pi}r}sin({\**theta**}){\int}_{-l/2}^{l/2}I_{e}(x',y',z')e^{jkz'**cos**({\**theta**})dz'}
When the (...)

RF, Microwave, Antennas and Optics :: 07-08-2015 20:40 :: hbb2 :: Replies: **0** :: Views: **238**

hi everybody,
can anybody expalin how to make 3D polar radiation pattern in matlab?
I am using UV plot where with mesh(x,y,z) command
x=sin(**theta**)**cos**(phi)
y=sin(**theta**)sin(phi)
ans
z=calculated gain
all are NxN square matrix
But I want to plot in polar form
Thanks
Hi, mns. This is my m-file for 3D radiation patt

Electromagnetic Design and Simulation :: 09-24-2014 22:42 :: doooo :: Replies: **0** :: Views: **1562**

For Polar coordinates, r^2=x^2+y^2 and x=r\**cos** \**theta**, y=r\sin\**theta**
r^2=x^2+y^2\Rightarrow\; r\frac{\partial {r}}{\partial {x}}=x+y\frac{\partial {y}}{\partial {x}}
\Rightarrow\; \frac{\partial {r}}{\partial {x}}=\frac{x}{r}+\frac{y}{r}\frac{\partial {y}}{\partial {x}}
\frac{\parti

Mathematics and Physics :: 10-30-2013 12:56 :: Alan0354 :: Replies: **10** :: Views: **664**

If you see at the unit circle:
1. rotating by 90 degrees means swapping x and y axis (that is sin and **cos**), then sin(90+θ)=**cos**(θ)
2. rotating 180 degrees the waveform repeats with reversed sign, that means sin(180-θ)=-sin(-θ)=sin(θ)
then the ratio sin(90+θ)/sin(180-θ) = (...)

Mathematics and Physics :: 06-18-2013 06:53 :: albbg :: Replies: **13** :: Views: **2790**

88856
Hello,every one
I am trying to plot radiation intensity of antenna using the following code but it is giving me an error. please, help me
PI = 4.0*atan(1.0);
E = 120.0*PI;
L=1;
Io = 1;
r=2;
k=2*pi;
**theta**=0:1:359; (...)

RF, Microwave, Antennas and Optics :: 04-04-2013 17:23 :: kakar133 :: Replies: **10** :: Views: **918**

Hi TomJohn,
Inphase and Quadrature components of a passband signal, s(t)=A***cos** is
I(t)+jQ(t)=A***cos**(**theta**(t))+j*A*sin(**theta**(t))
as
s(t)=I(t)**cos**(2*pi*fc*t)-Q(t)sin(2*pi*fc*t).

Digital Signal Processing :: 11-10-2012 07:01 :: MHanif :: Replies: **1** :: Views: **532**

........
Is it possible to separate this function in a+ib form. Either through MATLAB or manually.
M = sqrt(sqrt((16+2.23*sin(x)^2)^2 + 0.6^2)) ;
**theta** = atan2( 0.6 , -(16+2.23*sin(x)^2))/2 ;
a = M***cos**(**theta**)
b = M*sin(**theta**)

Mathematics and Physics :: 07-12-2012 17:06 :: _Eduardo_ :: Replies: **4** :: Views: **1544**

I changed the progressive phase excitation angle (beta) to 45 degrees on my dipole array, and I got huge gain (better than the endfire 32-degree phase at 0-degree scan angle). I am not sure what the 45-degree phase excitation angle corresponds to in scan angle (**theta**) as when I plug it in the equation beta = -kd **cos**(**theta**), (...)

RF, Microwave, Antennas and Optics :: 07-18-2012 13:42 :: kae_jolie :: Replies: **0** :: Views: **700**

You havnt calculated your power facctor? **cos**(**theta**)

Elementary Electronic Questions :: 07-03-2012 22:14 :: james05 :: Replies: **1** :: Views: **618**

Hi,
I'm trying to generate waves of the form, p = a***cos**(**theta**)*exp(i*w*t), where t is the time, w is the frequency and **theta** is just an angle. In my VI (attached),
I used exp(i*w*t) = **cos**(w*t)+i*sin(w*t) and formed this using the Re/Im to Complex Function. And I used four different (...)

Microcontrollers :: 06-19-2012 16:01 :: abr_pr90 :: Replies: **0** :: Views: **483**

cn we able 2 find out the directivity in 2d plot of half wave dipole,....i got 8 shaped radiation pattern hw 2 obseve its directivity?? i hve given **theta** range from 0:pi*0.01:2*pi,.and electric field formula e=(**cos**((pi/2)***cos**(**theta**)))/sin(**theta**) ,.i am doing in matlab

Electromagnetic Design and Simulation :: 03-06-2012 12:25 :: rosey :: Replies: **1** :: Views: **1505**

The power factor (**cos**(**theta**) where **theta** is the angle between the voltage and the load current)

Electromagnetic Design and Simulation :: 02-27-2012 07:01 :: klystron :: Replies: **3** :: Views: **969**

simple imaginary to polar co ordinates
a+jb=(sqrt(a^2+b^2))phase(b/a)
tan(**theta**)=b/a, a=r***cos**(**theta**), b= r*sin(**theta**)
Hope that helps
Regards
Elchiquito

RF, Microwave, Antennas and Optics :: 02-24-2012 09:43 :: elchiquito :: Replies: **15** :: Views: **3059**

Hello
I have a project to simulate radiation pattern of circular loop antenna. I have D=fn(**theta**,phi), and I do transform from **theta**,phi to x,y,z by these equations:
x=D.*sin(**theta**).***cos**(phi)
y=D.*sin(**theta**).*sin(phi)
z=D.***cos**(**theta**) (...)

Electromagnetic Design and Simulation :: 11-27-2011 14:24 :: engcu90 :: Replies: **1** :: Views: **5642**

how i can plot an azimuth and elevation planes for E= sin(**theta**).***cos**(phi) or E= **cos**(**theta**).***cos**(phi) or E= sin(**theta**).*sin(phi) etc {matlab code } ??

RF, Microwave, Antennas and Optics :: 10-27-2011 17:18 :: barcawi23 :: Replies: **0** :: Views: **774**

In reflector antenna, usually we use horn as the feed. It has been checked that the radiation patterns of the horn can be simulated as a function: \**cos**^q (\**theta**) .
The power q has been chosen at each frequency to fit the horn patterns.
I already have the radiation gain pattern of one horn, I am wondering how to approx i

RF, Microwave, Antennas and Optics :: 10-19-2011 16:59 :: panou :: Replies: **0** :: Views: **1197**

I am new here, I tried writing equation in Latex and it does not work, I compare to the "Latex Commands Quick Menu and it looks the same but mine don't work. Can anyone tell me what did I do wrong? Below is the equation I wrote.
Thanks
Alan
\sin\**theta**=1
\int_0^\infty
\psi=\frac{\beta d \**cos**\phi_m}{4\pi}

About EDAboard.com :: 09-05-2011 23:02 :: Alan0354 :: Replies: **4** :: Views: **841**

i need a vhdl program to solve the given expression.
here is the expression:
PG1 = ((2*pi)/λ)*dh*sin θ * **cos** θ
the values are
2*pi = 2*3.14
λ = 7.5cm
dh = 4.28cm
sin θ = sin 45 degree
**cos** θ = **cos** 30 degree
and the result shoould be PG 1= 125.76 degree

PLD, SPLD, GAL, CPLD, FPGA Design :: 09-02-2011 02:40 :: pavithra.s015 :: Replies: **1** :: Views: **596**

This is a real function.
Only three terms: m= -1,0,1 ==> Σ(...) = 1 + 2***cos**(pi***cos**(θ))

Mathematics and Physics :: 07-09-2011 22:19 :: _Eduardo_ :: Replies: **8** :: Views: **1139**

hi it possible plotting far field in function of sin(**theta**)**cos**(phi) and sin(**theta**)sin(phi) instead of **theta** and phi?

Electromagnetic Design and Simulation :: 03-15-2011 11:33 :: pizzotta :: Replies: **0** :: Views: **941**

hi it possible plotting far field in function of sin(**theta**)**cos**(phi) and sin(**theta**)sin(phi) instead of **theta** and phi?

Elementary Electronic Questions :: 03-15-2011 10:41 :: pizzotta :: Replies: **0** :: Views: **580**

Well, first you just need to define the array factor for circular array. LMS and RLS basically give weights that wil help in removing interference, noise or whatever.
The array factor for a Uniform circular array is
AF(**theta**, phi) = exp(j*(2*pi/lambda)*radius*sin(**theta**)***cos**(phi-phi_n))
**theta** is elevation, (...)

Digital Signal Processing :: 11-24-2010 03:28 :: anmol :: Replies: **3** :: Views: **1707**

1/120*pi^2 integration 0 to pie [(sin(1.2420*10^7)***cos****theta**)/**cos**^2
J0(k0L sin θ)sin3 d**theta**
Jo is bessel function for zero order
plz plz plz find the answer of this for me i will be very thank ful to you

RF, Microwave, Antennas and Optics :: 10-02-2010 12:43 :: sachin_ccs11 :: Replies: **6** :: Views: **2548**

Hello,
I am having a major issue with the far field excitation source file formatting. I cannot seem to generate a simple **cos**^q(**theta**) pattern file and need to get support from CST for this to see if they can supply someone with a **cos**^q(**theta**) pattern file. So, does anyone have (...)

Electromagnetic Design and Simulation :: 03-26-2010 17:02 :: hookups1534 :: Replies: **0** :: Views: **924**

Hello everyone,
I would like to know if there's a software/matlab code I could use in order to convert the pattern of an antenna element to a formula that can be plotted in Matlab. For example :
% element pattern of dipole antenna
g(**theta**) = (...)

Electromagnetic Design and Simulation :: 03-07-2010 11:03 :: narfcois :: Replies: **0** :: Views: **1752**

plz find the attachment of a cordic verilog code......someone can understand that code and tell me how i can use that code in finding sin and **cos**.....actually i have to use below loop in verilog
for(**theta**=0;**theta**<100;**theta**++)
{ (...)

PLD, SPLD, GAL, CPLD, FPGA Design :: 02-25-2010 23:40 :: alangs :: Replies: **1** :: Views: **2156**

This will make final equation shorter
**cos**(180-x) = - **cos** x

Mathematics and Physics :: 04-05-2009 19:30 :: elektryk :: Replies: **3** :: Views: **3256**

hi,
how to write a program forcalculating **cos** angle(**cos** **theta**) in 8051
assembly language
thank you

Miscellaneous Engineering :: 04-03-2008 07:08 :: achuthkumar :: Replies: **0** :: Views: **925**

epilot,
Adding to comments by Mansour_M: Measure the phase shift between the voltage and the current. Let Za = the value as obtained by Mansour_Ms method. Let **theta** = the phase shift. Then Z = Za **cos**(**theta**) + jZa Sin(**theta**).
Regards,
Kral

Elementary Electronic Questions :: 01-23-2007 10:19 :: Kral :: Replies: **2** :: Views: **1325**

hi can anyone help me solve this equation please
I= ∫sin×(sin Θ)(sinΘ)(sinΘ)dΘ/**cos**Φ with the limits between 0 and Π
thanks

Elementary Electronic Questions :: 11-25-2006 04:09 :: ekipyegon :: Replies: **2** :: Views: **901**

Hi,
i generated a model using the sine/**cos** lut ip core.
went with the same way u mentioned.
intially giving a **theta** width of 4 and then regenerating it with 6. but i have not met with any error.
now... have u generated the model by calling coregen from the ISE environment using " create new source".
or did u activated coregen intially (...)

PLD, SPLD, GAL, CPLD, FPGA Design :: 06-14-2005 03:40 :: Renjith :: Replies: **4** :: Views: **2615**

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