17 Threads found on edaboard.com: Current Shunt Feedback Amplifier
I couldn't find out what would be the gain for this given circuit given the open loop gain of
This is my guess
I can find that the loop gain Aβ is equal to gmRd which
Analog Circuit Design :: 07.01.2013 14:00 :: SherlockBenedict :: Replies: 2 :: Views: 296
for series...the current remains unchanged as tat of the input ...and voltage is added or subtracted...
for shunt ...the voltage remains unchaged as tat of the input ...and current gets added or subtracted..
same thing applies to the output
see some basic books...like..
Millman and halkais ,etc
Electronic Elementary Questions :: 18.09.2005 11:55 :: ysenthilece :: Replies: 7 :: Views: 1584
it is used to prevent the occurence of metastable state in the inverters by the usage of feedback... also it increases the current sourcing ability of the buffer and decreasing the output impedance...
Analog Circuit Design :: 03.04.2008 09:35 :: A.Anand Srinivasan :: Replies: 2 :: Views: 736
I don't like this terminology at all, because - for my opinion - it is confusing.
And according to my experience, it is used in different ways.
Some authors use these words based on the sequence input-output and some vice versa.
Based on the input-output sequence, the phrase series-shunt feedback means, that the feedback signal is
Analog Circuit Design :: 04.05.2010 16:18 :: LvW :: Replies: 1 :: Views: 1739
*When the feedback signal is derived from an output voltage (current) it is voltage- (current-) driven feedback.
*When the feedback signal is added to the input voltage (current) it is a voltage (current) feedback.
*Example 1: opamp as a non-inv. (...)
Electronic Elementary Questions :: 03.11.2010 09:22 :: LvW :: Replies: 1 :: Views: 3138
current-Sense amplifiers (CSAs)
Microcontrollers :: 28.04.2012 11:46 :: tpetar :: Replies: 4 :: Views: 368
First of all I am right in saying the network formed by R1, Rf and Cf is the feedback network and can you pls explain why its is a voltage feedback.
During formulation of an answer I have detected an error in my first response. Sorry - it is voltage-controlled current feedback (sometimes called (...)
Analog Circuit Design :: 12.11.2012 12:43 :: LvW :: Replies: 3 :: Views: 222
Hi - I'm in troble - i have to design a current sink which should load a resistor with a resistance of 0,1R.
the resistor is connected to gnd.
The current sink should be variable from 0A to 6A.
I try to design a circuit but if i test this in Pspice i get the result that this chircuit will swing.
As Variable Resistance i used a p-depletion
Analog Circuit Design :: 06.08.2006 14:36 :: El_Paco :: Replies: 2 :: Views: 3045
Does anyone have any comprehensive material for finding loop gain using breaking the loop method.
Actually I am trying to find the loop gain, phase and stability of a Transimpedance amplifier (input current - output voltage) using this method. It consist of only a single transistor with a feedback resistor from collector to base.
Analog Circuit Design :: 17.08.2006 03:35 :: currentmirror2000 :: Replies: 5 :: Views: 1948
feedback is the method of feeding part of the output to the input to increase the gain in the case of positive feedback and increase stability with reduced gain in the case of negative feedback.....
shunt mixing and sampling and series mixing and sampling depend on the type of output and the type of (...)
Electronic Elementary Questions :: 03.07.2007 03:51 :: A.Anand Srinivasan :: Replies: 4 :: Views: 2264
For a normal current source , we first have a current , then the current flows through a dioded connected mos and generates a voltage vx, so vx makes M0 generate a current.
But for a wilson current mirror, how does it generates vy and vz ? Only formula
forces these two nodes to be the correct voltage? (...)
Analog IC Design and Layout :: 03.06.2008 05:36 :: wwwww12345 :: Replies: 4 :: Views: 644
I have to design a circuit that employs negative feedback to achieve the design
specifications shown below:
Closed-Loop current Gain = 15 A/A up to 10 MHz with 60 degrees of Phase Margin
Closed-Loop Input Resistance < 1 Ohm
Closed-Loop Output Resistance > 10 MOhm
Supply voltages VDD = 2.5 V and VSS = -2.5 V
driving the load of 1K and c
Analog Circuit Design :: 16.03.2009 23:44 :: edaoj :: Replies: 1 :: Views: 834
Why have to divide by 200u ?
Transimpedance = voltage/current. Your voltage output is 91mV, the current input is 200uA.
Analog IC Design and Layout :: 29.10.2010 15:25 :: keith1200rs :: Replies: 6 :: Views: 545
Sir, I want designing circuits with component values for the following circuits
1. Common Emitter amplifier
2. Common Source amplifier
3. Two Stage RC Coupled amplifier
4. current shunt and voltage series feedback amplifier
5. Cascade amplifier
Electronic Elementary Questions :: 18.01.2011 09:41 :: jravi :: Replies: 1 :: Views: 402
now I can't work out how or why it works..
You didn't tell which point is unclear to you. I can imagine two possible issues:
- How does said "over-the-top" mode of LT6016 work. I fear the simplified internal circuit misses some details, we simply have to believe that the specified parameters are achieved. A pnp current mirror wit
Analog Circuit Design :: 29.05.2013 03:24 :: FvM :: Replies: 7 :: Views: 232
I'm not motivated to draw a circuit diagram now. I just give a few hints.
1. Consider a shunt resistor. It already is a full featured current-to-voltage converter. You didn't tell any requirements regarding input voltage drop or convertor output resistance. You can scale the resisistor to get any intended conversion factor.
2. You requested
Analog Circuit Design :: 24.06.2008 15:30 :: FvM :: Replies: 1 :: Views: 1080
I have an inverting amplifier and in the feedback path I have a series combination of inductor and capacitor and Resistor
Then the transfer function of the feedback part is sL + 1/sC +R.
Strictly spoken, both statements seem mutual exlusive. You would need an ideal current source to represent the said transfer (...)
Analog Circuit Design :: 16.04.2012 03:47 :: FvM :: Replies: 12 :: Views: 789