759 Threads found on edaboard.com: Current Source Circuit
I understand that we use an NMOS to form a constant current source. My question is, can we create a constant current sink using a similar approach with PMOS? Is constant current sink even a thing?
Elementary Electronic Questions :: 01-17-2017 08:07 :: dzafar :: Replies: 7 :: Views: 723
Are you certain that you wired the actual circuit correctly?
You may have the MOSFET body diode voltage drops to account for (2) when current is flowing in RL, e.g. the pin "2" of RL is not actually at ground (potential of the negative plate of the DC source) but diode drop above it).
Take a DMM and measure voltage drops around the loop.
Analog Circuit Design :: 03-24-2017 02:28 :: ftsolutions :: Replies: 5 :: Views: 671
Are you saying that through this spiral does an electric current pass (ie the wiring is part of some circuit consuming power), or is it just a helical-like antenna ? If you want a 'stable' 50Hz noise source, I would recommend to make some circuit that you could predict the electromagnetic flow and even tune it. An open (...)
RF, Microwave, Antennas and Optics :: 03-16-2017 18:26 :: andre_teprom :: Replies: 6 :: Views: 544
It depends on the loudspeaker and how much power you want. Some NE555 manufacturers specify as much as 200mA sink/source current which is enough to drive a medium to high impedance loudspeaker directly. The mass of the loudspeaker cone will be enough to average the PWM back to an analog level.
For higher power all you need to do is ensure enough '
Hobby Circuits and Small Projects Problems :: 03-12-2017 21:44 :: betwixt :: Replies: 3 :: Views: 656
Hi! I am designing a PFC circuit(in boost configuration, inductor is CCM, switching frequency is 100kHz), and it has a high current spike during on and off of the MOSFET switch. I used a bulb as its load. I am not sure if these high spikes are results of the MOSFET parasitic noise or a common mode noise injected at the input of the PFC (...)
Power Electronics :: 03-02-2017 10:26 :: dann11 :: Replies: 6 :: Views: 1030
Because you are looking to run two equal currents
through devices at two unequal current densities.
So you need unequal areas.
1:N ratioing is the IC designer's best way to get
a maximally consistent ratio. Drawing two different
device geometries (like a single 1X emitter, and
a single 16X-area emitter) puts you at the mercy
of various lithogr
Analog Circuit Design :: 02-16-2017 19:26 :: dick_freebird :: Replies: 3 :: Views: 498
Hello, I build some project which use a constant power supply of 30V 30A, and i want to limit the current because i'm not use such a huge current and i want to promise that my project will never get 30A in 100%.
I want to limit my project circuit current to 1A, what is the easiest way to do it?
Analog Circuit Design :: 02-10-2017 10:48 :: omerysmi :: Replies: 2 :: Views: 591
Hi, I am currently design an rail-to-rail op amp and i found a circuit for the input stage with rail-to-rail input using complementary differential amplifier but unfortunately there are additional transistor in the circuit (those transistors that i circle in red). I know the additional transistors are for maintaini
Analog Circuit Design :: 02-01-2017 16:31 :: dra66ard :: Replies: 5 :: Views: 596
I have a simple low side switch using a mosfet for an Inductive load. All works quite fine. Now I need to add over current protection, and for this I need to add current sensing which will notify the driver or any other IC to switch off the mosfet if current is, for example, above 1A.
I read many articles about it
Elementary Electronic Questions :: 01-22-2017 06:08 :: xmen_xwk :: Replies: 22 :: Views: 1500
We are current working on testing of different benchmark circuit using Tessent , DFT Advisor, Fastscan (Mentor Graphics) tool to calculate Test coverage, Fault coverage and ATPG effectiveness, We have calculated above parameters using default ATPG , but we unable to apply external test patterns to improve TC and FC. Whether
Software Problems, Hints and Reviews :: 01-21-2017 04:11 :: mushtaqahmed601 :: Replies: 1 :: Views: 719
Since you seem to have a semi-infinite series of the
most basic questions I think a textbook is right for
But the textbook isn't going to teach you to
recognize, for example, that "Vb" in the lower is the
exact same thing as M3:M4 common gate node in
the upper, only difference being whether or not the
biasing is shown and how complicated i
Analog Circuit Design :: 01-07-2017 23:21 :: dick_freebird :: Replies: 3 :: Views: 578
Recently I faced a problem in calculating the output current in a circuit which is similar to current mirror circuit. I wanted to ask for your ideas on how to solve this circuit problem . In this circuit we supposed Vdd as Vreference.
the schematic is as below :
Analog Circuit Design :: 12-31-2016 08:14 :: omidrey :: Replies: 9 :: Views: 797
can any one help me out for Vf=7 volt I=10 to 20mA (variable) constant current control circuit for UV LED 134762
Analog Circuit Design :: 12-24-2016 09:07 :: 4tuty :: Replies: 4 :: Views: 614
currently have a relay thats rated for 15 amps for a 5amp AC PSU power source (high capacitive inrush current). I have it wired so that its in the NC state, and when the relay is powered it cuts power to the PSU (reason I want it like this is if the relay control logic fails on boot/power on, the AC circuit will still be (...)
Analog Circuit Design :: 12-22-2016 19:47 :: jstefanop :: Replies: 2 :: Views: 584
One way is to use a programmable current source to vary the slew rates as shown below. A lot will depend on required frequency, level, etc.
Analog Circuit Design :: 12-16-2016 23:01 :: E-design :: Replies: 8 :: Views: 785
If you overload your voltage source and it does not have current limiting then the circuit will smoke and burn or blow a fuse.
Elementary Electronic Questions :: 12-06-2016 21:22 :: Audioguru :: Replies: 4 :: Views: 503
The "problem" is that even if the FET turns off instantly, the rise time of VDS will be determined by its drain source capacitance (Coss) and the load current. If your load is just a 1K resistor, this will result in a fairly slow rise time of VDS.
You need to increase the load current greatly to see the true switching times of the FET. (...)
Power Electronics :: 11-30-2016 15:08 :: mtwieg :: Replies: 2 :: Views: 476
Even if both currents would be exactly equal, the circuit doesn't generate a "voltage window" rather than a voltage difference V1-V2 with unknown & floating absolute voltage somewhere between 0 and 5 V.
I'm not aware of ready made controllable current source ICs in the ?A range. I designed similar (...)
Analog Circuit Design :: 11-05-2016 09:54 :: FvM :: Replies: 8 :: Views: 637
A P MOSFET requires negative voltages on the Gate and Drain with respect to the source in order to control source to Drain current conduction.
Microcontrollers :: 10-30-2016 08:49 :: esp1 :: Replies: 19 :: Views: 852
Just a first hint for you.
A thermocouple does not deliver a voltage but a current.
You should search for a current/voltage conversion circuit.
Microcontrollers :: 10-18-2016 11:30 :: doraemon :: Replies: 17 :: Views: 733
With a series capacitor between the (current source?)
and the upper RX terminal, it doesn't look much like a
resistor to me.
The mentioned photoFET optoisolator is only linear for
maybe +/-100mV and then rolls over. Not a good general
purpose "resistor" for anything but true small signal (as
the datasheet itself makes plain).
I wonder about some
Elementary Electronic Questions :: 10-31-2016 00:19 :: dick_freebird :: Replies: 6 :: Views: 746
Finding shorts by measuring voltage drops works quite well with PCBs, except for shorts between continuous overall power and ground planes.
You need a constant current respectively current limited voltage supply to source a short circuit current that doesn't damage the board or components. A few 100 mA to (...)
Analog Circuit Design :: 09-29-2016 06:53 :: FvM :: Replies: 5 :: Views: 901
I presume the TLP cathodes are directly connecting to STM32 IO pins?
STM32 GPIOs can basically source or sink the required TLP drive current. But the circuit is completely wrong.
- individual series resistors for each optocoupler required, power supply must be 3.3V
- high side drivers can't use common power supply, need either three (...)
Power Electronics :: 09-25-2016 06:39 :: FvM :: Replies: 7 :: Views: 1223
I think the circuit may be from "Op Amp circuit Collection", AN-31, attached is the schematic which uses LM102 and LM107 for a "Bilateral current source."
Analog Circuit Design :: 09-10-2016 18:31 :: d123 :: Replies: 4 :: Views: 1310
It is a differential circuit. The voltage across the shunt tells you the current across the shunt. That's a differential measurement.
Common mode refers to the absolute voltage of the shunt with respect to ground. The diagram captures it well. The + and the - are the differential measurements. The voltage source shown is common to both (...)
Analog Circuit Design :: 08-27-2016 01:48 :: asdf44 :: Replies: 3 :: Views: 326
I now see the reason for the arrow in the current source. It is negative conventional current produced by a current source that must have a negative supply voltage since the base of the NPN transistor is at ground.
If the gate of an enhancement N-channel Mosfet is also at ground then the (...)
Elementary Electronic Questions :: 08-23-2016 18:24 :: Audioguru :: Replies: 20 :: Views: 1866
Yeah, I forgot the negative sign, because the current k*V1 enters in the negative polarity of the R3.
Elementary Electronic Questions :: 08-14-2016 19:28 :: AMSA84 :: Replies: 2 :: Views: 427
It could be measurement error. Your scope probe needs to be using tip and barrel only across Vcc and Gnd .... ~ 1cm or less apart without gnd clip.
since ESR rises with C, the RC time constant is 10us for LOW ESR and about >>100us for standard. So when cable capacitance is switched current pulse causes a voltage spike at source due to ESR.
Hobby Circuits and Small Projects Problems :: 08-06-2016 23:16 :: SunnySkyguy :: Replies: 5 :: Views: 849
No AC source is actually floating, and most likely you don't want to operate your circuit directly connected to the mains.
A suitable solution for most applications is a high impedance (e.g. 1 Mohm to 10 MOhm) differential voltage divider. It involves some leakage current, but low enough not to trip any RCD protection or to expose (...)
Microcontrollers :: 08-06-2016 11:54 :: FvM :: Replies: 21 :: Views: 1728
Substrate diodes and dedicated protection diodes are forward biased with inverted power supply. If the supply source is able to exceed the maximum diode current, the device is destroyed.
Analog Circuit Design :: 07-14-2016 09:53 :: FvM :: Replies: 4 :: Views: 381
Check the input high threshold of the micro, the NPN circuit will lose Vbe between input voltage and the output so it may not reach logic 1 anyway.
With the top circuit, you might be able to replace it all with a Schottky diode, cathode to the signal source side.
For the bottom circuit, consider removing the transistor and (...)
Hobby Circuits and Small Projects Problems :: 07-08-2016 21:48 :: betwixt :: Replies: 8 :: Views: 636
In the circuit you showed the current source is set to generate a current from 10 uA to 100 uA in 10 uA steps. The setting is given directly in the I source where you have written "IBB uA", so any number you set IBB is in uA.
If you prefere, you could also delete uA from the I source (...)
Electromagnetic Design and Simulation :: 07-03-2016 21:33 :: albbg :: Replies: 1 :: Views: 341
i want to make a digitally(FPGA) controlled negative current source. C1 capacitor is the load.
- i want that current change equally for every single bit , for istance
1110 = Ix
1101 = 2Ix
1100 = 3Ix...
but in my circuit current doesnt change propartional. i arrange resistor values to make it 2Ix (...)
Analog Circuit Design :: 06-29-2016 07:58 :: deniz88 :: Replies: 2 :: Views: 396
Some external circuit will be needed - current source loaded to capacitor.
Microcontrollers :: 06-22-2016 16:33 :: Easyrider83 :: Replies: 9 :: Views: 498
Attached is a current mirror design I am a little bit confused about. I do not know what this kind of topology is called and thus cannot find any external information.
I do understand that this is a cascade current mirror, but I don't know what are the two external transistors doing and what is the benefit of having them in design.
Analog Circuit Design :: 06-03-2016 02:12 :: BoneMonkey :: Replies: 3 :: Views: 591
In first place I thought that this would't work, because you're forcing the current and by definition gm = did / dvgs. If id is constant gm is equal to zero. The same goes for the gds = did / dvds.
Even though I tried to simulate that circuit and I get a completly different plot:
The devices I am using are 1.
Analog Integrated Circuit (IC) Design, Layout and Fabrication :: 05-29-2016 22:41 :: AMSA84 :: Replies: 6 :: Views: 981
I have 6 LEDs in my board connected to the GPIO pins of the MCU.
I want to design a circuit for constant current control with supply current in uA(when all LEDs are OFF)
The question appears to be incorrect, or perhaps unclear. Are you meaning you want to control the driven current of 6 LEDs in steps of uA's
Microcontrollers :: 05-24-2016 16:59 :: andre_teprom :: Replies: 4 :: Views: 617
assume there is a simple connection of an ideal voltage source with a resistor. on the other hand, there is a current source connection with a resistor. I want to measure the resistance in each circuit. now,
1- for measuring resistance of a 10k or higher, it is preferred to use voltage source or (...)
Analog Circuit Design :: 05-07-2016 15:27 :: nanock :: Replies: 1 :: Views: 458
I use LTS 25-NP current sensor to measure ac current grid. I just built it. I tried to calibrate it using simple circuit consists of a single phase source and high power resistor. The current is flowing when I change the source voltage as appearing in the Ammeter but the output voltage from (...)
Power Electronics :: 05-06-2016 13:57 :: anoman :: Replies: 4 :: Views: 1329
Yes, you cam make your own A/D converter, and it's not too dificult to understand. With a constant current source and a small capacitor, you can generate a saw teeth waveform, which can be used to compare with measured signal. The time elapsed to reach the same value is proportional to the voltage.
Microcontrollers :: 05-04-2016 16:02 :: andre_teprom :: Replies: 2 :: Views: 644
There's no Vin, gain (transimpedance in this case) is measured with current source I1.
Seriously I have no idea how the circuit is intended to work as oscillator, respectively don't know which transimpedance value you want to achieve.
Analog Circuit Design :: 04-30-2016 12:40 :: FvM :: Replies: 13 :: Views: 1470
What is I1? Are you really supplying the DC bus with a current source? That's weird.
Power Electronics :: 04-29-2016 05:45 :: FvM :: Replies: 2 :: Views: 502
Hi i want to add noise to the input current source of my multiplier circuit and i want to run the DC analysis. Can anyone tell me can is there any noise file already written that i can obtain from cadence or do it have to write a file of my own and include the txt file. Also once obtained can anyone pls tell me how to include it. In the (...)
Analog Circuit Design :: 04-04-2016 16:22 :: preethi19 :: Replies: 1 :: Views: 1051
All this depends on your circuit. You should give at least your example circuit.
* Supply voltage?
* output current? source only? or sink too?
gain: How much gain do you need? What is the input voltage? I estimate it should be a unity gain buffer, am I right?
BW: For me a reference voltage could be considered to be (...)
Analog Integrated Circuit (IC) Design, Layout and Fabrication :: 03-31-2016 09:40 :: KlausST :: Replies: 3 :: Views: 462
Ideally, SW3 should not be open, otherwise I current source would generate an "infinite" voltage accross its terminals.
Elementary Electronic Questions :: 03-10-2016 15:45 :: andre_teprom :: Replies: 7 :: Views: 886
To know the inverter power (magnitude and direction), you'll multiply and voltage and current (instantaneous power) and average the product. Under circumstances, it's sufficient to form sign(P) = sign(V) xor sign (I), needs only two comparators.
The inverter can also "source" or "sink" reactive power, in this case sign (P) will flicker with doub
Professional Hardware and Electronics Design :: 03-06-2016 08:32 :: FvM :: Replies: 9 :: Views: 863
"Pulse" refers to the square wave current waveform in case b, I presume.
It has been already explained that the waveform is cause by connecting a current source as load, which is more a theoretical model than a real load case. You can however come quite near to it by using a large inductor with series resistance as load.
Elementary Electronic Questions :: 02-21-2016 09:31 :: FvM :: Replies: 20 :: Views: 2087
for these super low frequencies, use a current source/capacitor ramp generator circuit. Start the ramp at the positive going zero crossing of the input sine wave, and reset the capacitor to 0 Volts at the negative going zero crossing. Save the peak ramp voltage value in a simple diode/hold capacitor and read off the voltage from that hold (...)
Analog Circuit Design :: 02-17-2016 02:55 :: biff44 :: Replies: 22 :: Views: 2277
I presume you are referring to the circuit linked in post #1
I would suggest some modifications. If no FET is available, you should at least use a Darlington (e.g. BC517 for the NPN configuration) to keep the base current error negligible.
Secondly, the output transistor involves a voltage gain for Rsens < 5
Analog Circuit Design :: 02-15-2016 10:33 :: FvM :: Replies: 18 :: Views: 2269
Yes the internal resistance will limit the current in addition to any external resistance.
Elementary Electronic Questions :: 02-12-2016 09:48 :: chuckey :: Replies: 6 :: Views: 510