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663 Threads found on edaboard.com: Current Source Circuit
What are some good troubleshooting techniques on how to test circuit leakages, stage leakages and component leakages. Leakage current upsets bias circuits and upsets the next following stage bias. Mostly from what I read is how to measure leakage current is to insert a current meter in series and measure the (...)
Hi, I'm studying microelectronic circuits theory using sedra smith book. The question is, this book is saying that in IC design, for load resistance, tr is used as a constant current source for some reasons and PMOS is usually used for it (im studying cascode amplifier circuit now and, if this will be help to understand (...)
Thank you so much BigBoss could you tell me where it comes from( Gm=Idss/abs(Vp) )? and how can we find the source-Drain current with specific gate-source voltage or vise versa ? It's not coming from somewhere, I have given a rough expression for that.There isn't a handy consistant equation for HEMT devices therefore
Hey guys, the following circuit was attached to a boost convertor and is used to provide a 2 MHz frequency square waves to the Boost Convertor. My issue is when looking at the circuit, I realized I don't fundamentally understand how it achieves that. 1) So for example I understand that the second Op-amp is an integrator (since it has a capacitor i
You're right: this cascode circuit is not very temperature (nor supply voltage) stable. But at least Q1's Vc will stay 1*Vbe below Q2's Vb. The Figure 2.24 text just says the current stability referred to load changes is improved (compared to a simple constant current source). This is true, because the cascode (...)
A PV is essentially a lossy current source that has a zener like open circuit voltage, Voc that declines slightly with lower solar input. The maximum power point is approximately 80+/-5% of Voc when the VI product has a shallow peak in power about this centre. You can hunt for this peak using MPPT regulated current sinking (...)
Hi, I don't know what you mean... To drive a LEDfrom a voltage source you need a current limiting resistor. Because the bias voltage is high in relation to a LED forward voltage the output (light) will be about proportional to input voltage. Klaus
In a RC circuit, if the voltage source is a sinusoidal source, I found the given equation. C is constant. I tried to solve this problem in time domain. So, I use a source in an EDA tool. I found the current in time. I know the voltage. I use simple numerical derivaton df(x)=/(x2-x1). In this case, (...)
If you assume that the current source has an internal energy source (an ideal current source in a simulation of course has), you don't need Vdd. A technical current source, e.g. a transistor circuit will need an external energy source. - - (...)
This would be the final circuit. 115848 But I do not know what value must be R2. Because I do not know what value would have Ic2 (Q2). R2 is totally unnecessary. With the shown value it would just reduce your constant current to ≈75mA. And
Let the voltage across Rx = Vx and battery current , I. Then V1 = (4k7/4k7+2k) X Vx, re arranging gives Vx = V1/(4k7/6k7). So 3.3 V = (100 X I) +VX, { 100 X I = volt drop across 100R ), rearranging, (3.3 - Vx) = 100 X I, so I = (3.3-Vx)/100. So I is the current from the battery, some flows through the 1K (Vx/1K), some flows through the output
Hi All, if I want to play with the PSR of a circuit block(for exmaple, op-amp), an AC signal is injected into VCC, and I want to use an ideal ac gain block to amplifier this AC signal and convert it to a current source. Would anyone teach me what is the easiest way, to implement Vin(ac) to Iout(ac)? Thank you! 114937
You can put some back-up capacitors to increase the circuit working time out of external energy source. With the battery, supply a low power comparator (its current consumption actually depends of your need) with a battery supplied reference, say 3V, being the compared voltage one generated by the external power supply. The comparator will (...)
Transistor current in flyback is unipolar sawtooth waveform. Where do you see current through body diode?
You should first tey and find the threat source or info about it (if this is a field return). Then, what you mean by "burned out" along with what you know about the event, may lead you somewhere. Those zeners / TVSes have peak current and short term average current and short/medium term power limits. An ESD event of classical form (...)
You can safely forget about this approach. Don't expect to achieve ns pulses with closed loop feedback current source. Try something using transistor current sources respectively transistor as V/I converter. In a 10 ns range, GHz OP based current sources can be an option.
I think the input reference current changes the oscillator frequency.
If you just want to shut-down Vout -> 0V , it's enough to connect the power transistor's gate with its source - by a transistor switched via the enable/shut-down pin. Should you need a total 0-current shut down, you'll have to disable some control current, plus, possibly, inactivate some extra enable transistors. For more detailed info (...)
Other than Vref, this design has no input and the current sense has open loop gain so it doesn't matter what Vref does. What is the point?
In the circuit you have an independent current source (the left-most), a current source that generate a current of ampliteude depending from the current flowing in the 2 ohm resistor and two resistors in parallel. You need to apply Ohm's law, but also Kirchoff's law. The (...)
Almost all Mosfets are power Mosfets. You forgot to tell us the maximum current that you want in your Mosfet. Most Mosfets need a gate-source voltage of 10V to fully turn on (but 'logic-level" Mosfets need only 5V) so you need a gate driver circuit to boost the 3.3V from your microcontroller. The gate pulses to the Mosfet must be much higher (...)
Hello, Can anyone suggest a simple current reference circuit for a two stage op amp. I need to generate constant current in uA range to be injected in the diode connected transistor and mirrored at both the stages. Thanks, Hobbyiclearner
Left circuit is well known Widlar current mirror.. Right circuit is a voltage controlled current mirror/source..
AC has to be scaled and shifted and then measured. DC has to be scaled and measured. Same for current.
It's a simple cross-coupled LC Oscillator with Noise Filtering (by order to simulate such circuits, a start-up simulation trick should be used to excite the oscillator. For instance a step-up current may be injected into the circuit during a limited period or a step-up voltage source can be used to excite the (...)
To get a DC current as high as 1A and using a frequency of 200kHz then the coils will probably be fairly large and/or have a ferrite core. Since the coils probably must touch together then why not use a plug and jack?
For a LED driver you need constant current, not constant voltage. This is because the LED forward voltage drop changes with temperature, if driven from a truly stabilized voltage source would cause large changes of current through the LED. The total voltage drop might be around 30V, but what the 10W LED needs is a constant 333 mA. Frank (...)
In my IC i only want to use MOS for to design various component. In this how will i make current source?? Also describe in MOS, if source is connected to gate thn what is the significant of this type of circuit ??
555 is spec'd to +/-200mA output. With max rated at +/-225mA. Meanwhile, your R8=10 draws 1.2A spikes. Bad form. FET needs high gate current only to switch internal charge then low current. To improve you need to buffer the 555 such as complementary source or emitter followers, then R8 can be reduced to 5 Ohms or whatever max Gate (...)
I want to measure resistance and capacitance at Y port Connect a unit current source with ac magnitude=1 and any frequency between your output and gnd (separated by a large cap, e.g. 1F, in order not to short-circuit the DC output voltage). Then run an ac analysis, sweeping the frequency between your points of inte
Attached is a LTSpice circuit of a simple constant current source. A standard pnp / zener arrangement. I've used this circuit years ago , but I don't remember it being as good as the simulation suggests. Set for about 1mA output , it only varies by 25uA with a temperature change from 20 to 80 degrees and a load change (...)
Your schematic uses what look like current sources. A current source will generate any voltage necessary to push its specified ampere value. It will even generate a very high voltage. Could that be the cause of your odd readings?
Can you give the circuit that you are using for your experiment? At what voltage is the Gate and the Drain set at? It seems that when you enter the Cut-Off region, the Drain to Body diode turns On and you see a current gain. I'm just guessing.
Hello, Please need a suggestion on Plating thickness tester. currently working on the project. As you know there must be constant current source constant current source for the application. So how can built or Is any ready made available in the market. because i don't have luxury time to built my own (...)
the circuit works to keep the voltage at the base constant in that case I think its much more the emitter voltage that is beeing held constant by varying the base current!
What is defined as 'reset' condition for your circuit? What is the intention of the 'load' circuit? It looks like a variable heat source (RV2, Q3) with a fixed current. What is the MCU you are using?
To take a more accurate answer it is necessary to know the current waveform, or circuit topology.
The common mode setup isn't yet right. The current source must not be connected in series with the load but between ground and output. I suggested to use a load with center tap for symmetry.
Best intelligent charge monitor will pulse battery with light load and heavy load and compute C, capacity based on load voltage and ESR. For example using programmable current source ,pulse 1st 5 mA then 505 mA and use S&H to display ESR or delta V over delta I (0.5A) which is a function of C the Ah capacity of battery. Each battery chemistry has
I think that your circuit above is actually better described as a constant current load (or source) - the transistors in the bottom are setup to try to draw approximately 260mA through Q2 regardless of what the top connected power supply voltage is, with the only other limiting factor besides the output level of the power rail being the (...)
Here is a website (one of 100's) which has several constant current source circuits. Note that simultaneous control of output current AND voltage basically implies a very specific load. However, I assume the voltage range is the input voltage range, so no problem there.
CAN transceivers are also generally designed to be quite robust - they have substantial amount of current source/sink capability, and output short circuit protection. They are capable of handling the dominant/recessive bit battles on long cable lengths without incurring damage. Some of them have significant ESD and overvoltage protection (...)
Referring to post #6, you'll find a gain calculation in the text book from where you copied the amplifier circuit (Razavi or whatsoever). The transistor Id and respective gm is primarly set by the current source transistor M5 and only slightly depending on Vcm, as long as all transistors are in saturation.
hi, Its a 'current mirror' , look at this pdf for a description. E
Please specify purpose like switching speed, direction, current source and sink capabilities, etc. Analog Devices have a very good range of isolators. Link
Circumstances at your measuring place are of such nature that it is usuall to consider current measurement using current transformer instead of shunt.
Hi all, I'm building a circuit, wich I can't quite figure out, so any suggestions will be appreciated:) The circuit shall act as a constant current source for 3pcs Luxeon rebel leds (driven at 500mA as total for the 3, 166mA each) I need to be able to control the current downwards, by a analog (...)
One way of doing that would be to calculate the RMS. Another way, perhaps less time consuming would be to divide the energy dissipated by the time period. See the attachment below (Note that the definition of current in the attachment holds only for the first time period, but it is sufficient to calculate power from this, since current is a period
A Widlar OP current source circuit is a popular way to achieve what you want.
106337 The figure shows multimeter at the output is in Ammeter mode which i think it functions as short circuit for the system. Referring the picture, I attached. I have designed a series voltage regulator that can convert AC source to DC source (range from 0 - 20V). However, I could not achieve 5A maximum curr