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48 Threads found on Divider Operation
The question is incomplete. You should show the imported libraries and also tell about the used synthesis tool. Usage of operator suggests that you are using ieee.numeric_std. Some tools are able to infer a parallel divider for the modulo operation with ieee.numeric_std library, e.g. Altera Quartus. Apparently yours doesn't, so you need to imple
I hear a basic misunderstanding about microphone operation. There's absolutely no need for impedance matching, Rsource <= Rload should be sufficient. In practice a simple electret microphone circuit with 1 or 2k resistive output impedance can be expected too fit all applications, using an additional voltage divider if the output level is to high an
Hi, I think you misunderstood something. The limit to 100uA is for safety reasons only, not to destroy the chip. It is not meant for normal operation. Tell us about what you want to measure. Is it the power supply voltage in the eangd of 0....20V? Then just use a two resistor voltage divider (maybe with an additional C) to meet the ADC operating
There is a smart way to do that division operation when divider is constant - without a repeating process - but you have to pay a loss on accuracy. The trick is just to replace a division by a multiplication followed by a shift operation. Note that both these operations have already built in instructions at most (...)
Will that be synthesizable if modulo operator is used? modulo 2^n simpy synthesises as a shift operation, other numbers infer a divider core, if supported by the respective tool.
For 5v supply (5v and gnd) you should use single supply opamp like LM358, LM324 etc. You should not use 741. For LM311 issue, check the operation of LM311 in a bread board using a potentiometer and two resistors as voltage divider. You first need to make sure that LM311 is working properly. Upload schematic, otherwise it is difficult to understand.
The mod operation is synthesizable by most tools, but it infers a parallel divider to get the remainder which is often unwanted. A while loop in contrast isn't synthesizable. The best solution depends on your design requirements. The parallel divider may be suitable for small numbers like 8-bit, if you want to minimize the resource count, (...)
I have used resistive dividers with SIM900 with no issue as follow: MCU TX pin to SIM900 with divider. MCU RX pin to SIM900 direct connection. SIM900 Reset pin driven by open collector/drain. Also include 100nF bypass cap on reset pin. At a guess I think your SIM900 may be damaged. Cheers
I wonder to know is there any logarithmic voltage divider?
Hello i'm planning on build a dc electronic load and i want to make the constant power and constant resistance modes analog so i can just put that in a feedback loop rather than constantly sampling -> making floating point calculations -> outputting through the dac so i need your help with an analog multiplier/divider circuit/IC whichever possi
hi i want to implement a simple logic circuit in CPLD (XC9572) which does this operation (1/X + X * 4 ) . what is the efficient way of calculating 1/X. X is a 12 bit number. I already done the multiplication part but don't have any ideas about how to efficiently do the 1/x part. should I go for the divider module? tnx in advanced for helpful co
Hello, I'm designing a Fully-Differential low noise amplifier for neural signals like the one on the next links:
You need to reduce input voltage and shift by 1V to avoid negative values. Shift input voltage by adding a DC source of 1V, so new range will be 0 - 4V and then add a divider with factor 2, so new range will be 0 - 2V; with these range value can go to MAX1415; in software code need to take account these operation (shift and scaling). REF+ and REF-
So you are building an electronic gas divider. I presume you know how to make a 10% step voltage divider with 10 equal resistors.For the 5V - x operation, you need an opereational amplifier in a substractor circuit.
Not sure I understand how this circuit operates. The voltage divider is creating a negative voltage at the base of Q3 (-6.75 v), which from what I've been taught would not forward bias the transistor (+0.7 v ?), Transistor operation requires a voltage BETWEEN base and emitter of approx. 0.7 Volts. Look at the emi
As the input is from battery and decays over time Zener diode and Resistive Voltage divider are not feasible. Zener diode doesn't sound bad as a first approach. Besides maximum gate voltage, which seems quite easily to satisfy, you should think about minimum gate voltage according to the MOSFET characteristic and intended Rds,on.
Hi, Can any body explain how the positive and negative edge triggered flip-flop works in the following link I have made the same flip flop (as divider) in cadence in 130nm process for high speed operation but the simulation results show a voltage g
Right-click the voltmeter and select edit properties. In there is 'Load Resistance' - mine was set to 100M. Play with that setting. I get the correct reading with it as part of the potential divider formed.
Basically the whole operation of the 555 timer revolves around the three resistors that form a voltage divider across the power supply, each resistor ~5k (for the bipolar version of the IC) so the comparator reference voltages are 1/3 and 2/3 of the supply voltage. The pin 5 identified as ''Control Voltage Input'' can directly affect this relat
i need 1-4 wilkinson power divider. operation frequency can be between 2-10.6 ghz. i need to Ads 0r HFSS file. need as soon as possible,thnkx in anticipation
This device is based on Atmega8. The main operation which the chip does, is to count impulses. The maximum frequency of Atmega8 is 7MHz, therefore it should be equipped witch a frequency divider. 74LS90 was used with
Hello, We are doing an offline 330W half bridge smps which is to have an output voltage of 40V or be set with a pot at production. The lower feedback divider resistor will comprise two resistors in series, one of which is the pot. I ma aware that this can give noisy operation of the smps, as pot wipers slip and have poor contact.
Hi, everybody, Divide-by-2 static frequency divider based on CML circuit has a wide operation range. But if I want to study the locking range and to establish the behavior model of the divider, how to start up the work?
There are some points missing in your calculation: - The voltage gain would be reduced by the finite transistor transcondutance, you have to reduce Re to about 12 ohm to compensate for it. - You can try to get an exact value for Vbe at the respective operation point from the transistor datasheet, but it's not much help, because the actual value
It's a case of overload respectively unsuitable bias point. - Try to adjust the base voltage divider to achieve undistorted output. - If it's not possible, reduce the input AC voltage. It's apparently too high for the present circuit. You should also tap the collector voltage to check the correct amplifier operation.
you can use transformer or resister divider method if not need isolation
Hi, I need VHDL codes for the arithmetic operation (output) = 1/(input) there anybody who knows using VHDL.Can you send me the codes please...
To be more precise the Negative Resistance Oscillator (or negative-conductance whatever you want to be, gain or loss) could be seen as a Colpitts oscillator, with internal transistor base-to-emitter capacitance, and collector-to-emitter capacitance acting as a voltage divider. This is the reason in this kind of oscillators can be used only transi
hI GUYS Im having problems with my Wilkinson power divider. When I generate the gerber a part turns upside down. Does anybody know the solution?
need floating point block diagram and code for substractor
The gain is ΔVout/ΔVin, and it's -R/2R or -0.5, as said. But the bias voltage at +In has to be 1.67 rather than 2.5 V for intended operation, so the voltage divider must be 2R:R instead of R:R.
Study the datasheet of the FPGA you want to target. If it doesn't support altering divider settings during operation, you'll have a problem.
Ho to design a odd number clock divider?
I'm using the DDS function of AD9858. I wanna get the sinewave signal with my desired frequency from DAC output. I adopted parallel programming mode and single -tone operation mode. I'm sure the microcontroller port has communicated with AD9858 because when the register, eg, 2GHz divider disable, was set, the SYNCLK output is 125MHz. I
The 50 Ohm power divider pad may be blown
there are many techniques , like injection locked dividers , and miller dividers , but the main stream now are using flipflops with CML operation so the divider can work in very high frequencies khouly
Hi, One can apply even-odd mode analysis to understand the operation of Willkinson divider. Even mode: the middle point of resistor is open circuit and resistor is not contained in the circuit, so the even part is indeed losless. Odd mode: the middle point of resistor is short circuited so the resitor is contained in the circuit and contri
well, the threshold voltage is set by Vref times the resistor divider. Therefore, Threshold = Vref * R1 / (R1 + R2). For ideal operation, you want it exactly in the middle, at 1.25V. In a real amplifier, you could set the gain to be very high and have the amplifier rail. Therefore if Vin is slightly above 1.25, the output would go to 0. If
Hey Its primarily done to double the frequency of operation (by triggering some actions at falling edge and some on rising edge) Here it's worth noting that 8085 has an internal clock divider.Having two phase clock again in a way compensates for that.Teason for employing such configuration is to have a more symmetric clock distribution.Please Ref
but these modules will at least consume a few tens uA Why tens uA? For example, battery protection IC includes all these blocks and consume less than 3 uA in normal operation mode. in this case ,the following module are still on work: 1,main bias 2,bandgap 3,comparator 4,voltge divider from VDD to Gnd
I hav to design a 4:1 wilkinson unequal power divider. I am following the IEEE paper on tht n pozar. I hav calculated the impendences for the unequal power divider. My frequency of operation is 1.5Ghz, dielectric value is 1.5, h=1.57 ie he height of the substrate . Can u tel me how to calculate the width of the conductor as well as the (...)
Hi it seems simple, but you need basic knowledge about electronics, more presicely op-amps. You didn't mention the operation frequency, so yo need to care about it when selecting an op-amp. First you attenuate your signal by a factor of (3-(-3))/10= 0.6 -it can be done with a voltage divider- then using an op-amp substrac from the resulting
hi there generally div, mod and exponentation operators are not directly synthesizable. You will probably have to devise an integer-by-integer hardware divider producing what you want (the remainder as you referred to, as well as the quotient result). In microprocessors, div and mod are usually emulated in software. If needed in hardware the
Generally there is no difference in OP AMP operation as long they operate in middle of common mode input range. To ensure this a 1/2 voltage divider from supply voltage is used. This Vcc/2 voltage is sometimes called virtual ground.
Hi, everyone! I tested a CML divided by two circuit, but met some problem. The minimum input power of my circuit is around 0dBm, which is different from my simulation result of -10dBm. I think it is caused by oscillation. When it has no input power, the divider outputs a frequency around 20GHz with the power around -35dBm. The DC voltage of my ou
Hello cart , Please have a look at the variable Div_Out is it declared as real , beacuse if the registers are not declared as real then it becomes integer division . Please also relook into your library what you requrie is a floating point divider ... does your library support .. if there is no support then you might have to develop your own
The internal clock is a two stage operation. There is a crystal oscillator in the nx10 MHz range and then a phase locked loop with a divider in the feedback loop locked to the nx10 MHz crystal oscillator output. This is how they get the GHz internal clocks.
Hi to all, how I can build in VHDL an integer divider with both quotient and remainder outputs? I would like to divide the dividend by the divisor to produce the quotient and remainder. Regards gnomix