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Exponential Distribution

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17 Threads found on edaboard.com: Exponential Distribution
Hi all, I want to generate random signal with exponential distribution (exp(T/tau) tau is my constant) in verilog. Could you please advice me how I should do it? Sincerely, Albert
thanks very muchxulfee, but i think i'm looking for a random sequence with exponential pdf...And the problem is, such a sequence with zero mean returns all zeros as i already mentioned.
This has been a while, so check my work ... I presume you have a Gaussian RV with mean ?, and variance σ?. The integral with |x| is awkward to think of - break it into two pieces. With a little thought, the integral from 0 to ∞ is always positive - no need for |x|. Similarly, the integral from -∞ to 0 is always negative,
In order to find the inverse cdf of the exponential distribution I have solved Y=1-exp(-X) for X. This is the point. You have to find algebric inverse. Also if you jenerate the data using the line you have here, I think you can see that the drived data are not exponentially distributed. Yours, dspman.
The built-in potential is generated because of the diffusion of the mobile charges across the junction which leaves back the uncompensated immobile charges near the junction. The number of charges diffusing across the junction is equal to the number of immobile charges left back. The mobile charges diffuse in the p or n type material and follow a n
please somebody explain me that if the channel is Rayleigh faded than Instantaneous receives SNR is exponential distributed wit some mean. please elaborate it in bit detail.
I want to find out the cdf Fx(x)=Pr(X ≤ k) where "X" is a Rayleigh distribution and "k" is some other Rayleigh distribution with may be different mean and variance. How can I find it out, somebody help me please.
Hi, I want to solve this problem for my friend.But I have some questions to ask you. "Paris Wholesale fruit distributors employ one worker whose job is to load fruit on outgoing company trucks. Trucks arrive at the loading gate at an average of 24 per day , or 3 per hour, according to a Poisson distribution. The worker loads them at a rate of 4
Basically, if the underlying fading channels are Rayleigh, then SNR follows exponential distribution. That is y0, y1, and y2 are all exponentials, where y0, y1, and y2 are the instantaneous SNR of the direct path, the first hop of the relay path, and the second hop of the relay path, respectively. After generating them, calculate the (...)
Here is the source file of exprnd function function r = exprnd(mu,varargin) %EXPRND Random arrays from exponential distribution. % R = EXPRND(MU) returns an array of random numbers chosen from the % exponential distribution with mean parameter MU. The size of R is % the size of MU. % % R = (...)
There are many trends exhibited by some research groups: 1. multiple or variable voltage supplies (transistor-level) 2. application transformations that infer differentiations at the system level e.g. the memory subsystem organization and the update rules for these memories. (RTL and system level) 3. adiabatic switching (transistor level)
Random distribution is normally characterized by its probability distribution function (pdf). The area covered by the pdf is always one. Uniform is one where the probability of any value occuring within a specified range (say from a to b) is the same, ie p(x)=1/(b-a). Normal, or gaussian distributions follow a symmetrical bell-shape curve. (...)
Hi, you have many elements, but exactly ? it is instable if you use a direct approach (till 40 elements in double precison it works). This is beacuse the close formula has products of exponential and factorial number that becames quckly very intractable. You need a factorization scheme to make this stable (tenth of thousands of elements !!
Hi all! I have simulated a rayleigh flat fading channel (ofdm) and a frequency selective exponential channel in which every tap follows rayleigh distribution,thus every tap 'sees' a flat rayleigh channel (due to this right? However i wonder what the plot would be? The plot (BER vs SNR) is almost the same for both cases? This is right,i
Hi all! I would like to ask if there's any advantage in doing OFDM in a flat fading Rayleigh environment? Also can anyone tell me if there would be any difference in the BERvsSNR results , when we simulate a flat Rayleigh channel and a frequency selctive exponential channel, where each tap follows Rayleigh distribution... Any answe
IF X and Y are statistically independent (or orthogonal) then the RMS of the combined signal (sum) will be sqrt(X^2 + Y^2) and the distribution will be exponential