10 Threads found on edaboard.com: Exponential Distribution
Rayleigh channels are almost worst case scenario. In Nakagami-m channel modeling the worst channel has a parameter m = 0.5, while Rayleigh has a parameter m = 1. Also, Rayleigh channel is mathematically more convenient; the SNR distribution is exponential.
Digital communication :: 10-19-2016 19:15 :: David83 :: Replies: 3 :: Views: 328
if we create a sequence and call these w1...wN with exponential distribution with parameter lambda then we create:
what's name of this distribution?
Mathematics and Physics :: 06-14-2015 10:15 :: panda1234 :: Replies: 7 :: Views: 974
I want to generate random signal with exponential distribution (exp(T/tau) tau is my constant) in verilog. Could you please advice me how I should do it?
Microcontrollers :: 08-16-2013 03:12 :: albert_new :: Replies: 2 :: Views: 584
Basically, if the underlying fading channels are Rayleigh, then SNR follows exponential distribution. That is y0, y1, and y2 are all exponentials, where y0, y1, and y2 are the instantaneous SNR of the direct path, the first hop of the relay path, and the second hop of the relay path, respectively. After generating them, calculate the (...)
Digital communication :: 10-19-2011 18:38 :: David83 :: Replies: 5 :: Views: 7207
Here is the source file of exprnd function
function r = exprnd(mu,varargin)
%EXPRND Random arrays from exponential distribution.
% R = EXPRND(MU) returns an array of random numbers chosen from the
% exponential distribution with mean parameter MU. The size of R is
% the size of MU.
% R = (...)
Digital communication :: 09-20-2011 16:00 :: samir67 :: Replies: 1 :: Views: 3082
IF X and Y are statistically independent (or orthogonal) then the RMS of the combined signal (sum) will be sqrt(X^2 + Y^2) and the distribution will be exponential
Digital communication :: 02-28-2011 00:10 :: klystron :: Replies: 1 :: Views: 705
Hi all! I would like to ask if there's any advantage in doing OFDM in a flat fading Rayleigh environment?
Also can anyone tell me if there would be any difference in the BERvsSNR results , when we simulate a flat Rayleigh channel and a frequency selctive exponential channel, where each tap follows Rayleigh distribution...
Any answer will be he
Digital communication :: 08-24-2010 19:32 :: anta :: Replies: 6 :: Views: 1714
I want to find out the cdf
Fx(x)=Pr(X ≤ k)
where "X" is a Rayleigh distribution and "k" is some other Rayleigh distribution with may be different mean and variance.
How can I find it out, somebody help me please.
Digital communication :: 06-16-2009 04:16 :: aliazmat :: Replies: 2 :: Views: 1059
If you look in the book of David Tse, Fundamentals of wireless communications.
instantaneous SNR is defined as, |h|^2 SNR, therefore if we take square of Rayleigh it becomes exponential distribution therefore the overal instantaneous recieved SNR becomes exp. with mean SNR.
hope this helps.
Digital communication :: 11-13-2008 04:04 :: urwelcome :: Replies: 2 :: Views: 2071
please give me the charecteristic functions of
Digital communication :: 04-02-2007 09:30 :: vamsi charan :: Replies: 0 :: Views: 1198