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107 Threads found on Opamp Output Impedance
Hi everybody, I am trying to design opamp circuits, but I couldn't fully understand how to find input and output impedance of an opamp circuit. When the configuration is Non-Inverting, input impedance of the circuit is High-impedance and for impedance matching I may (...)
An opamp has such a high open-loop gain that when it is a voltage follower it has a lot of negative feedback causing its output impedance to be extremely low when it is not overloaded.
The results with the single supply voltage depend on the output impedance of the power supply. The circuit you show feeds half of any hum and noise on the positive supply to the reference input of the opamp. Do it liked this:
The open loop output impedance of an opamp is shown on its datasheet and is usually around 75 ohms. The negative feedback from the resistors in the circuit reduces the output impedance a lot at DC and low frequencies IF(!) the output is not clipping. If the open loop gain of the (...)
hi guys I want to know how to measure output impedance of opamp in cadence. Regards Arunkumar
hello everyone I found this schematic and I want to understand how to calculate resistors for another opamp (TL074C) I can see that the amp is setup as an inverter (and a non inverter at the same time) but I dont understand the use of R7 and R8 ... if I consider R5 and R7 as a V divider the - input is up to 0V so how to calc these fo
Hello, I have to design opamp based Hartley oscilator which oscilates at 35 khz(sine wave).Ive spent my 2 days to design this but I was huge challange.I checked online but no luck and also I use Pspice and Proteus for my must be opamp based. :-| Thanks.
Your schematic has nothing to supply the input bias current to the opamp. If it is the signal generator then its resistance will cause the offset voltage. Add a same value resistor in series with the (-) input so that the bias currents cancel.
The output resistance of a typical opamp is maybe 100 ohms. The gain at DC and low frequencies (below 10Hz) is extremely high which reduces the output impedance when negative feedback is used so the output impedance could be much less than 1 ohms at DC and low frequencies.
Hi, it seems you are talking about ASIC design. If so, then please post in the ASIC design section. *** Generally a unity gain buffer is an amplifier with gain of +1. With an opamp you can IN+ use as input and connect IN- to the output. Maybe with a resistor. Then you have high impedance input and low impedance (...)
The voltage follower does two things: 1) It isolates the 1st order RC circuit at trhe input from the second order part. 2) It provides an important extremely low output impedance to drive the second order part. If you put the input RC stage in the feedback of the opamp then the (inverting) opamp inverts the phase shift of (...)
please explain me whether the opamp(two stage) i have used can drive the resistors as shown You can answer the question yourself if you calculate open loop voltage gain and output impedance of your opamp. Of course the answer also depends on the resistor values. But in case of a wideband amplifier, the resistors need to (...)
If you've got the output of one opamp driving the EXTREMELY HIGH INPUT impedance of the next op amp, how much current does that output need to supply? Just about nothing, dynamic or otherwise. If you've got feedback resistors, those will also draw some current, as will capacitors (dynamically!). Without seeing a schematic (...)
Dear all, I am using cadence to simulate an opamp's input referred current noise. However, i have no idea how to build the test circuit for it; since I cannot use a current source as a input noise source in the noise analysis. If i do, the bias condition will be disturbed. can anyone help me? You can use a c
However the bandwidth of the opamp is limited to about 70MHz and also the output impedance increases from there on. A more appropriate description would say, the output impedance is continuously rising beyond 1 MHz. And not explicitely specified in the datasheet, but obvious by circuit analysis basics, (...)
Dear forum, just a simple (?) beginner question: An answer to your question was given above. However, as you are a beginner: Are you aware that using only one single supply voltage (s shown in your diagrams) imposes some severe operational restrictions? The classical opamp application requires dual supply (+/- voltages
I show an opamp but it could be an audio power amplifier. On the left side there are circuits with a positive and negative dual polarity supply. You are trying to make this from a single supply by using brute force to feed the power supply for the amplifiers. On the right side I show amplifiers that have a single supply and are biased at half the
Negative feedback reduces the output impedance of an opamp. It does not increase it. When negative feedback reduces the gain of an opamp to 100 then the output resistance of 75 ohms is reduced to an impedance of much less than 1 ohm at DC and low frequencies.
hi veeru you need make the circhuit with opamp to measure the PH output along with voltage offeset thanks
The opamp has negative feedback that produces an output level exactly the same as the input level. Cf feeds the output level to the junction of R1 and R2. Then R1 has the same signal level at both ends then has no current in it so the input impedance is extremely high.
I think a rail-to-rail opamp should be used because a transistor has a low input impedance especially if it has negative feedback from its output to its input to reduce its voltage gain to be "inverting one".
Hey guys, I was just wondering how i would make a voltage buffer/follower without using an opamp. I have used some class A (emitter follower) and AB amplifiers, but when my output is very low impedance, my output starts to saturate with an offset. I was wondering if you guys had any designs in mind with very high (...)
Hello, Is R14 going to be OK for use as a loop injection resistor for feedback loop measurement? (attached schematic & LTspice simulation). Also, the opamp, U2 , is included purely for ensuring that the feedback loop measurement can be successful. (low impedance of opamp output is needed) That is, R14 and U2 (...)
opamps DO NOT HAVE a single-ended collector output in class-A. Their output is produced by very low output impedance complementary emitter-followers in class-AB.
The most important differences between both circuits are * the gain (opamp: 1E5...1E6; diff. stage: 10...100), and * the output impedance (opamp: 50...100 ohms; diff.stage: kohm range). * input impedance (opamp: Megohm range; diff. stage: kOhm range) (The differential (...)
Hi All, when I study feedback effect, one of its effect is to reduce the output impedance. Then I am curious, if we have an OTA with high output impedance, is it possible to use feedback to reduce this impedance to a very low level, then this OTA will be a opamp? Since we always need (...)
The signal source of the Sallen-Key lowpass filter must be much lower than the input impedance of the circuit. Frequently the very low output impedance of an opamp drives it.
I agree that the (+) input of the opamp must be properly biased at about half the supply voltage. Your existing unbiased opamp is a rectifier. Your opamp is inverting with an input impedance of only 100 ohms that loads down the high impedance output of the photo-transistor. The gain of the (...)
impedance is AC resistance. The input impedance and input resistance of an opamp is 1M ohms to billions of ohms. The output impedance of an opamp is 0.01 ohms at DC and low frequencies to 75 ohms at higher frequencies. Its output resistance is 75 ohms.
I am experiencing strange behaviour of AD8607. It should be pA biass current and uV offset voltage opamp, but simple voltage follower configuration shows this results: 95124 Error seems to be related to source impedance as it dissapears if I connect opamp input directly to voltage reference output (no potentiometer). But
Hello, I am a newbie of IC. And these days, I really confuse about the "input impedance". According to TWO-PORT, for a VCVS, we should open the output to calculate the input impedance, and for a VCCS, we should short the output to calculate the input impedance. But for a opamp or OTA, (...)
why opamp has infinite input impedance, infinite bandwidth, infinite slew rate, infinite CMRR, Zero output impedance, infinite voltage gain. please its urgent. suchita As mentioned in post#2, you have listed IDEAL conditions that never can be met. However, to answer your questions: All opamp manufacturers try to
if you are talking about the standard opamp circuit. Input via a resistor (Ri) to the negative input with a resistor also from this point to the output (Rf). The input impedance is Ri, the output impedance is the actual output impedance of the opamp (100 (...)
Like any opamp, a comparator exhibits a bandwidth limitation characterized by its dominant pole, which in most cases is its output pole. Hence its "built in" 3db bandwidth is approximately 1/2πRC , R being its output impedance, C its load capacitance.
Hi When analyzing an opamp circuit using KVL/KCL/Nodal, how do the + and - signs designating non-inverting and inverting opamp inputs affect the analysis? How do we apply them? Thanks.
I am trying to measure the output impedance of an opamp in the attached configuration. Results are attached. Basically, Zo = Vo/Io = 10mV/40mA = 0.25 Ohms. Without the capacitor in the circuit, I get mostly a large dc current. Is there a better method to measure output impedance? I would like to (...)
Hi all, what we have learnt is that the output impedance of an opamp is very small. I cannot seem the find this information in the datasheet of the opamp I am looking at. May I know how can I measure the output impedance of an opamp using only spice?
This is not mtaching/unmatching issue... Your board can not drive 50 Ohm because of it's high output impedance.You should use a simple buffer amplifier for instance an opamp buffer etc..
- If I have 3.3 in the source - I have 12V on the engine - If I have 0V in the source - I have -12V on the engine(reverse) - If I have 1,65 in the source - I have 0 V on the engine (off) If you want +-12V on the motor then the supply must be more than +-12V. +-15V or +-18V would be good. +-24V is too high; it
Hi dino, two additional remarks: What do you mean * with "ideal amp"? Transistor, opamp, OTA? * with Rout? (The term Rout in your formula primarily consists of the load resistance and - in most cases - is not the output resistance of the amplifier itself).
The possibly misleading point with this thread is that the existence of oscillations hasn't been yet verified. OPA549 isn't particularly wide bandwidth, not more than 1 MHz. There may be an oscillation problem though, but many others as well. hshah89770, please excuse me for my silly question: Are you sure the dc
what is the input and output impedance of an ideal opamp? How can you use an opamp as buffer? which transistor configuration is used for power amplication? How power amplification occurs in such a configuration?
Why is that the output impedance of the OTA is ideally very high? I thought we need a high output current but why is it that the ideal output impedance is very high? Can you please explain it to me? In contrast to the well known opamp (which is a voltage source) the OTA shall act as a (...)
It is a lowpass of 2nd order with unity gain. Advantage: Offset-free (no opamp output) Disadvantage: No low-impedance output (load impedance influences transfer function).
The output of the opamp log converter is buffered, i.e. has a much lower output impedance.
When you set the output pot to a low resistance you are putting the large capacitor directly on the opamp output. Most opamps don't like that and will become unstable and oscillate. Put your filter on the input, not the output. Keith
Jon, what is the purpose of the voltage divider R2,R10? Can you reduce the gain of the first opamp instead? The output of the first opamp has low impedance, so you can connect it directly to the ADC. - Nick
An amplifier could be an attenuator when it has a voltage gain less than 1. On the other hand, using an opamp allows to improve drive capability because its output impedance.
HI friends i am designing the Folded cascode opamp. i am getting maximum gain of opamp as 46 dB..! @L=900nm and VDD=1.8....if this is the only gain can be obtained then what is good to implement for increasing gain upto 70 dB 1) gain boosting 2)adding one more stage my GBW requirement is 50MHz and SR is 30v/usec.....what do i do please sug
can you give me some papers about simulation of input/output impedance of opamp both open loop and closed loop. thanks To measure output impedance, regardless closed loop or open loop, u just put ideal current source Idc with ac=1 at the output, then measure the voltage at the (...)