132 Threads found on edaboard.com: Peak Rms
If this ripple is not periodic, you can use a modern oscilloscope that has a recording capability.The oscilloscope will record this nonperiodic waveform in a long term time slot and you will able to measure peaktopeak ( or avarage,rms etc).
Analog Circuit Design :: 12142014 10:11 :: BigBoss :: Replies: 3 :: Views: 179
My motor rated current is 3a found in name plate it is rms current are peak current
regards
kalyan
This is thermally rated for rms, whereas peak current will depend on load, acceleration and Coil resistance, Rs.
*Added 5x .. Depends on winding resistance
Often this is 5x8x steady rated current
Microcontrollers :: 12132014 12:08 :: SunnySkyguy :: Replies: 1 :: Views: 162
Its a bandwidth thing, with CW you have a DC level, with a pulse, you have not, so if its a proper rms detector then the output is down by the mark/space ratio. If its peak measuring (rms calibrated) then it should be OK, providing the circuits have a wide enough bandwidth to handle the narrow pulse width.
Frank
RF, Microwave, Antennas and Optics :: 11022014 06:52 :: chuckey :: Replies: 1 :: Views: 238
A phase angle meter has a Total button and a InPhase Button
The Total Button measures in rms and is the same AC measurement as a DVM meter in AC mode?
The InPhase measures in rms or peak?
The InPhase measures the input voltage in phase with a reference input voltage of the same frequency
The Polarity and Magnitude is (...)
Electronic Elementary Questions :: 10142014 19:15 :: ParkerMike :: Replies: 9 :: Views: 549
hi,
Most AC meters are scaled in rms, which is 0.707 * Vpeak.
E
Robotics and Automation Forum :: 09202014 11:02 :: esp1 :: Replies: 3 :: Views: 673
2A peak into 8 ohms is 1.414A rms which produces an output of 16W into 8 ohms. The voltage swing is 11.3V rms or 16V peak.
Phase delay might be a problem at 20kHz if the frequency of the LC lowpass filter at the output has a cutoff close to 20kHz and you use negative feedback from the speaker to the input.
Analog Circuit Design :: 09032014 16:57 :: Audioguru :: Replies: 10 :: Views: 404
The voltage rating for a capacitor is its maximum allowed peak DC, which is 1.414 times higher than its sinewave rms maximum voltage rating.
So if the voltage to a capacitor is 25VAC then the capacitor must have a voltage rating of at least 35V and a 100V capacitor can be used for good reliability.
Note that some types of capacitors are polarized a
Analog Circuit Design :: 08052014 11:40 :: Audioguru :: Replies: 2 :: Views: 231
Since the input signal is a sinewave then you can use a simple peak detector circuit and reduce the gain by 0.707 times for the rms reading.
Analog Circuit Design :: 07012014 13:02 :: Audioguru :: Replies: 11 :: Views: 664
If crest factor depends by modulation (peak and removed modulation) how can people spent time defining crest factor for unmodulated signals as: sine, square, triangle?
Above is mentioned that: Crest factor is the peak amplitude of the waveform divided by the rms value of the waveform.
You mentioned 6d
RF, Microwave, Antennas and Optics :: 06212014 10:10 :: vfone :: Replies: 9 :: Views: 706
To deliver 100mA into 100Kohm you need 10000volts and an output power of 1000 watts.
That is rms so for a sinusoidal signal you need 14000volts peak, positive and negative.
Even 100mA into 1Kohm needs 100volts rms, 140v peak
Give a realistic specification for output current and load impedance.
Lower maximum current, (...)
Analog Circuit Design :: 06162014 06:45 :: throwaway18 :: Replies: 23 :: Views: 1254
If you connect one leg of the transformer secondary to ground, then you can apply the other leg to the ADC input; BUT you will need to drop the voltage, since the peak voltage will be over 14 volts (5 volts rms is about 14 volts peaktopeak).
You can determine what the peak value of the signal is, and (...)
PC Programming and Interfacing :: 06102014 15:28 :: barry :: Replies: 2 :: Views: 600
Hello,
I'm building a Fan Control Circuit for controlling the speed of a 380V Fan.(380V rms, ~540V peakmax 150W) using a microcontroller.
My main circuit is something similar to this FreeScale Application note :
In my circuit, I have a different microcontroller, Op
Power Electronics :: 05312014 03:06 :: memarian :: Replies: 1 :: Views: 334
peak ripple would of course be (Maxmin)/2 which is closer to rms noise, but depends on if your interest is thermal noise, clock feedthru or some other noise in the signal. Normally if it is fundamental f or 2f , we call it ripple, otherwise just "noise pp" covers all types including transient noise.
Analog Circuit Design :: 05132014 20:32 :: SunnySkyguy :: Replies: 5 :: Views: 397
. It depends on your sampling rate. ADC is linear but your detector is not.
Do you want to only track changes in Vac over long term or short term interruptions or do statistics Avearage & deviations ?
Choices:
quasi rms with peak, Pp or rectified average
I would use LPF Noise filter and rectified average with another LPF.
200Hz LPF before br
Electronic Elementary Questions :: 05112014 23:37 :: SunnySkyguy :: Replies: 3 :: Views: 310
It doesn't increase  it decreases by the voltage dropped across two of the bridge diodes.
The reason you get the apparent increase is because if you fit a reservoir capacitor after the bridge it charges to the peak of the rectified half cycles.
If you are using a capacitor, the voltage across it will rise to the rms voltage multiplied by sqrt(2) t
Electronic Elementary Questions :: 04212014 04:45 :: betwixt :: Replies: 3 :: Views: 225
As you know that 220V is basically rms voltage , so in order to get the peak voltage , you have to rectify it (bridge rectifier) followed by a filter stage , which incorporates a inductor and capacitor , or simply a capacitor the output voltage would be 220*root2 = 311v, if you use a large capacitor , the DC waveform would be more smoothen.
Power Electronics :: 04092014 15:05 :: BawA :: Replies: 3 :: Views: 279
Hi folks,
I designed a signal amplifier and need to measure the amplitude of the output accurately (less that %5 error) to be independent of oscilloscopes. Since output signal has some sort of distortion, especially at high frequencies, the idea of using rms converters is useless. Furthermore, I tried to simulate other ideas based on fast ECL co
Analog Circuit Design :: 01222014 01:53 :: vahid_ff :: Replies: 2 :: Views: 169
The 200W total is probably the power supply power to the amplifier that causes the output plus heat.
44V peaktopeak is 15.6V rms. Then the output power is 15.6V squared/8= 30.4 Watts.
Amplifier power is measured with a sinewave. If a squarewave is used then the output power is doubled (60.8W for this amplifier) because an additional (...)
Electronic Elementary Questions :: 12072013 23:14 :: Audioguru :: Replies: 20 :: Views: 672
105dB is almost 0.0005% and that is just the peak. The rms value of the distortion will be less.
Some very good audio opamps have harmonic distortion at 1kHz of 0.00008% but with a 2k ohm load, a gain of 1 and an output level of 1vpp.
You might be able to hear 0.1% distortion at 1kHz.
Analog Circuit Design :: 11302013 18:57 :: Audioguru :: Replies: 3 :: Views: 278
A good speaker has a continuous rms power rating and a much higher momentary peak power rating.
Cheap speakers have lies instead of true power ratings.
Analog Circuit Design :: 11212013 12:17 :: Audioguru :: Replies: 12 :: Views: 345
Hi guys,
I've found an amplifier design online and built it, and it produces a nice sound quality from my laptop line out! I'm a newbie in transistor amplifiers however, and now I'm trying to understand how the circuit works. I've figured out the following so far:
 R1, R2 and C3 make a low pass RC filter to supply a clean base bias for T1

Analog Circuit Design :: 11052013 12:05 :: ArticCynda :: Replies: 16 :: Views: 595
I see what u mean, the data sheet is sparse on output power info. it does say that full scale current output is 20.48 ma, and the output impedance is 50 ohms. That leads me to think that the peak output power would be at +/ 10.24 mA into 50 ohms. Poutpk=I^2*R=7.688 milliwatts peak, or 5.4 milliwatts rms.
So practically, I would expect (...)
RF, Microwave, Antennas and Optics :: 09302013 12:14 :: biff44 :: Replies: 1 :: Views: 223
rms is the voltage that has power. A peak may be of a high voltage with a high instantaneous power but a low power in the real sense of the word. Any meter that claims to read power must detect the rms voltage and current. otherwise the meter should be a peak power meter.
Frank
Electronic Elementary Questions :: 08122013 14:41 :: chuckey :: Replies: 5 :: Views: 380
Hi,
Crest Factor = peak Current / rms Current. In a linear load, the Crest Factor is 1.414. However, in a general purpose SMPS, due to its non linear nature, this factor will be much higher  in the region of up to 4.
See if you can measure the current using a CRO/DSO by putting a small resistor but having higher wattage in line. Then measure vol
Analog Circuit Design :: 07172013 04:52 :: ArNvC :: Replies: 3 :: Views: 368
There is real power and 'market hype' power. What you are trying to measure is continuous rms Watts but the specification may be for "peak music power" or similar. For example, my desktop speakers here each have a single 10cm loudspeakers in them, the back of the speaker is marked 8 Ohms 5W but the outside (...)
Power Electronics :: 07112013 12:52 :: betwixt :: Replies: 8 :: Views: 388
Obviously, an active "precision" rectifier will be required. Different AC quantities are available, averaged rectified value, peak value, rms value. Averaged rectified value is giving best results if no true rms circuit is required.
Analog Circuit Design :: 05302013 11:07 :: FvM :: Replies: 93 :: Views: 3966
Just some basic estimating..
50v peakto peak is 25V base to peak, and staying with 50 Ohms for now..
Then, for sine waves, the rms voltage is 25/SQRT(2) = 17.67 Volts, and Power = V^2/50 = 6.25 Watts
For the other extreme, a squarewave of (say) 90% on, 10% off comes to 11.25 Watts.
peak power is (...)
RF, Microwave, Antennas and Optics :: 05142013 19:16 :: Darktrax :: Replies: 6 :: Views: 1501
In NXP datasheets, it specifies test signals as CW, 2tone or WCDMA.
For the CW test signal, is this an absolute peak power, or an rms power?
RF, Microwave, Antennas and Optics :: 05072013 11:55 :: RFegg :: Replies: 4 :: Views: 454
I want to stepdown 300Vac 50hz to 5v(peak)ac but i have only 220v to 12vrms transformer available can someone suggest how can i use this 220v transformer with 300v. I tried using a potential divider to first divide the voltage but it doesn't works since the primary winding of transformer comes in parallel with the resistance of potential divider ci
Electronic Elementary Questions :: 04102013 14:02 :: asad1234 :: Replies: 6 :: Views: 366
What are some basic power supply electronic math formulas that a test technician should know?
120AC input  1.141 = 118 VDC
The 1.141 is the full wave bridge rectifier
One of my managers use to use these other formulas but I'm not sure if they are correct or have to get them
How to get the DC power supply output voltage
He would
Electronic Elementary Questions :: 03282013 01:09 :: danny davis :: Replies: 3 :: Views: 331
I used TINATI to model a circuit and it predicted a Total Noise that is negligible below 300 KHz and flattens out at 300 mV above 60 MHz.
I built the circuit and want to correlate what I see on my scope with what the model predicted.
My analog scope has a 250 MHz bandwidth so I believe it should have negligible effect on the readings.
Wit
RF, Microwave, Antennas and Optics :: 01202013 13:03 :: PeteC :: Replies: 1 :: Views: 238
Use an A/D converter or a peak detector.
Analog Circuit Design :: 12162012 13:14 :: crutschow :: Replies: 3 :: Views: 403
I am designing an inverter for a diy project. This inverter should be transformerless and microprocessor based. I am planning to use a DCDC converter, but should i used a the peak voltage or the rms for the DCDC output, and how do i configure the circuit to handle the power i have in mind? How could I limit the device to....say 250W , with a 24v
Power Electronics :: 10102012 00:26 :: fadapow :: Replies: 17 :: Views: 2023
36V is the rms voltage of the transformer. Not the DC voltage you get after rectification.
For a sinusoidal waveform, rms can be converted to its peak value by multiplying by 1.41, so 50V is about right. It will likely be higher even than 50V because the transformer will be rated to give 36Vrms at its maximum current. (...)
Analog Circuit Design :: 10112012 06:08 :: FoxyRick :: Replies: 8 :: Views: 952
Hi to everyone,
I'm working on a three phase sinewave converter project for a 3 kW squirrel cage motor (230/400 V AC). The converter's topology I have to realize is shown in the simplified scheme in the attachment. I've some doubts about the right selection of IGBT's current ratings.
Assuming for the motor a power factor cosφ = 0.8, I determ
Power Electronics :: 09092012 09:55 :: andrew87 :: Replies: 2 :: Views: 689
If it is a peak value, P = V^2/2R = 1^2/100 = 0.01W = 10mW
10mW = 10*mW As we have powers, convert "10" to dB via 10*log10 = 10*1 = "10dB"
10 mW = 10dB*mW. As we are lazy sometimes, we write this mostly as 10 dBm.
When it is an rms value, the power V^2/R = 0.02W = 20mW, converting "20" to dBs gives "13dB", so together with the mW:
Electronic Elementary Questions :: 09042012 06:28 :: WimRFP :: Replies: 1 :: Views: 367
But what's with the 36V?
The wall plug gives 24V rms, so the peak voltage should be 24 * sqrt(2) = 34V. There's a bit of voltage lost across the diodes, so you should get about +33.4V DC unregulated.
So it's only 6% higher than expected. Two possible reasons:
With light loads, a transformer's output
Analog Circuit Design :: 08262012 10:45 :: godfreyl :: Replies: 3 :: Views: 547
Hi Sir, Can u please give me the circuit diagram of SIDAC testing..... I am giving the following details of SIDAC
Its name is SIDAC K300 Silicon Bilateral Voltage Triggered Switch
Breakover Voltage minimum 270V and maximum 330V
Blocking Voltage 215V
peak offstate current at VDRM 10uA
Continuous Onstate DC or rms Current 1A
Holding cu
Electronic Elementary Questions :: 08092012 09:48 :: kalamkarvivek :: Replies: 0 :: Views: 323
I know Current Transformers have been discussed here before but i have a slightly different angle that i cant find the answer too,
I am currently desiging a circuit to measure current from say 030A, I have the current transformer, load resistor etc and that is all ok, I intend to feed the variable DC output into a Micro and use AD converters in
Analog Circuit Design :: 05272012 15:15 :: ste2006 :: Replies: 17 :: Views: 1538
Hi all!
I know voltage gain is given as Vout/Vin...I want to know that whether the values of voltages used for this calculation are rms or peak to peak?
Thanks in advance!
Electronic Elementary Questions :: 05192012 23:34 :: dlock :: Replies: 1 :: Views: 315
Hello guys
I'm doing some signal processing/data analysis. Hope to get some advice on something.
I collected some vibration data just the other day while metal cutting and I'm wondering what is the correct (or better) way to do this.
These are what the signals look like. Sampling rate of the data is 10000 hz.
Digital Signal Processing :: 05192012 04:37 :: Luppy :: Replies: 4 :: Views: 643
First convert voltage from peakpeak to rms, then calculate power. Impedance is usually 50 ohm for RF.
Vrms = Vpp/(2*sqrt(2))
Power = Vrms^2/impedance
RF, Microwave, Antennas and Optics :: 04232012 10:23 :: pstuckey :: Replies: 3 :: Views: 314
Measure the voltage with a truerms meter and a nontruerms meter. If they are the same then the voltage is sinusoidal. If you don't have a true rms meter, but the voltage reads right (what it is supposed to be) then you have a sinusoidal output. Non truerms meters read the average voltage which is (...)
Power Electronics :: 04102012 06:49 :: steveelliott :: Replies: 5 :: Views: 1473
Welll, first of all, you are going to need a 53 Watt resistor there; that'll get warm!.
Your output voltage is going to be 0.75 V (not sure how you got 660mV). And that .75V is rms, which means you've got a little more than 1 volt peak, which exceeds the range of the MCP3909(+/ 1) by a little bit ; you probably want to have a little headroom.
Analog Circuit Design :: 03212012 15:55 :: barry :: Replies: 19 :: Views: 1021
Your digital multimeter is showing rms value and on your oscilloscope you r measuring peak to peak voltage.
for more detail What is the conversion for rms voltage to peak to peak voltage
Electronic Elementary Questions :: 02022012 05:41 :: ibrar :: Replies: 4 :: Views: 457
Firstly, I am no expert at this. but it looks like you have coherent Tx/Rx communication system.
Do you when the light pulse occurs exactly? (if you do: then it would be a determined system and there is no need for any likelihood detection)
i) Integration, is possibly better consider threshold detection is like peak detection. An rms detection wou
Digital communication :: 01292012 23:54 :: kalyanasv :: Replies: 7 :: Views: 1071
1) dB = 20*log_10(Vpp/0.707)
2) dB = 20*LOG10(Volts_peak_to_peak/SQRT(0.008*Z))
3) db = (20log10) (rms ) & rms= 0.707*PP
4) dB = 20 log10 (Voltage 1 / Voltage 2)
1) Maybe there is a mistype? If you substitute Vpp/0.707 by Vpk*0.707, it is the expression of a voltage in dBV (dB realtive to 1V) assuming it is sinusoi
Mathematics and Physics :: 12292011 14:43 :: zorro :: Replies: 8 :: Views: 11002
Vsec should be Vpeak not rms ( because after rectification, filter capacitor holds peak voltage) and according to Vmin input (Minimum input mains voltage, transformer should work and output to be regulated).
Electronic Elementary Questions :: 12152011 12:34 :: ALERTLINKS :: Replies: 4 :: Views: 496
i want to convert 240v ac to 12v dc f=60z
i have transformer, bridge rectifier,load
given, load=100ohms, load current=0.12a
peak voltage of secondary=16.970v
rms voltage of secondary=12v
output of bridge rectifier=16.9701.4=15.57v dc
how can calculate capacitor for circuit plz explain with formula and ripple voltage of capacitor thanks...
Electronic Elementary Questions :: 12152011 11:56 :: vead :: Replies: 2 :: Views: 450
your optocoupler diode had a forward current of 60mA, the typical Vf is 1.25 for 50mA
with 230V rms the peak will be 230*1.414=325v /1000=32.5mA
So yes you can use it but if you are driving a low current logical input from the opto transistor then there is no need to use that high current.
If you use 1K then the you ween need a resistor about 219
Electronic Elementary Questions :: 11142011 02:45 :: alexan_e :: Replies: 9 :: Views: 8846