1000 Threads found on edaboard.com: Perfect Conductor
I have a question
Is there a magnetic field inside a perfect conductor (I know from basic courses and pozar's book that inside aperfect condcutor there are no fields)
but if there is no field inside the condcuotr , how does the current flow inside the conductor incase of DC
Mathematics and Physics :: 09-02-2005 08:08 :: mkassem :: Replies: 2 :: Views: 2192
If there is a tangential electric field just outside the metal, according to boundary conditions, the equal tangential electric field should exist just inside the metal too.
Now if there is a tangential electric field inside the metal, the line integral of this between any two points on the surface of the metal should give the
Electronic Elementary Questions :: 10-31-2008 07:28 :: subharpe :: Replies: 1 :: Views: 4270
Because EM radiation is nothing without the E. perfect
conductor allows no E-field.
Electronic Elementary Questions :: 04-07-2014 16:46 :: dick_freebird :: Replies: 1 :: Views: 274
With a perfect conductor at DC, the angle between the conductor and the field is 90 degrees.
By "at DC", do you mean a direct current flowing through the wire? If your talking about the E field (electric field) that causes this DC current, then the angle between the perfect conductor differential length (...)
Electromagnetic Design and Simulation :: 07-19-2006 13:42 :: nikremt :: Replies: 5 :: Views: 975
why does my simulation work with coax excitation even without any outer conductor? And will the use of a pec-outer-conductor influence my results in comparison to these without any outer conductor?
If you define your radiation boundary where your coaxial is outside the boundary, you don't need to define the outer conductor.
RF, Microwave, Antennas and Optics :: 02-05-2009 05:29 :: shameemkabir :: Replies: 11 :: Views: 3378
I am designing a mixer and implementation is in microstrip. the substrate parameters are: εr=2.2, H=10 mil and T(cond. thickness) = 18 ?m.
I've drawn the layout for co-simulation in momentum and am setting up thick conductor port definitions. after drawing on cond layer, set port definitions to single and internal as req.. then copied to cond
Electromagnetic Design and Simulation :: 06-11-2009 11:26 :: rfndmw :: Replies: 1 :: Views: 1525
I would like to simulate spiral inductor with different materials using ADS (other software is also welcome)
typically the conductor is perfect conductor. So how can I change the conductor property? Particularly I want to change the permeability of the conductor.
Shall I add one more layer and define (...)
Electromagnetic Design and Simulation :: 09-10-2010 04:37 :: charlyking :: Replies: 0 :: Views: 817
Hello every body
It?s the first time that I use HFSS. So may be my question will be very easy for you.
When I send the plane wave to my structure, I want after the propagation in this structure until the end, the wave turns back as if there is a perfect mirror. I was thinking in perfect conductor.
Electromagnetic Design and Simulation :: 02-02-2012 09:15 :: soft001 :: Replies: 3 :: Views: 644
when I use the MWS to simulate a simple example that two differential microstrip are on the plane, I define fore discreate port between the end of the strips and the plane. But when I simulate the model tell me that the port are not on the perfect conductor.
another question about the wave port. When I defined wav
Electromagnetic Design and Simulation :: 06-19-2003 06:42 :: eirp :: Replies: 8 :: Views: 8365
I'm not finding the equivalent electric conductivity of air anywhere! I know that for a perfect conductor, the conductivity goes to infinity, but what about for air???
You can consider air to be a very good insulator (imagine high voltage transmission!!), thus conductivity ~ 0 S/m
Electromagnetic Design and Simulation :: 03-25-2004 19:13 :: eirp :: Replies: 4 :: Views: 8871
I am a newer to study HFSS, so I cannot catch your teaching post of the above. can you explain it more detailedly?
in my HFSS project, driven modal was used, the 3D model was a unit cell(single wire) cut from an infinite periodic array by parallel perfect conductor wires. I adopted an cubic airbox to contain the single wires. and the
Electromagnetic Design and Simulation :: 05-18-2004 23:31 :: jackle :: Replies: 2 :: Views: 1397
perfect E means simply that the E-Field is normal to the surface -> it simulates a perfect conductor.
To assign a surface to gnd you have to use for example a lumped port and connect the line (you will be asked for) from the conductor to gnd.
If you use wave ports you don't have to do anything.
Electromagnetic Design and Simulation :: 08-10-2004 03:31 :: Mr. D. :: Replies: 8 :: Views: 3046
when you draw an object you can assign
perfect conductor to it.
HFSS will consider it a s perfect conductor not as a ground since perfect ground does'not exisit in reality....
and in any case you do not need a perfect ground to create a CPW
If you have a legal copy (...)
Electromagnetic Design and Simulation :: 11-24-2004 06:39 :: rugbyfun :: Replies: 2 :: Views: 2599
I did a lot of training and had many totorials:) And I found what the problem was:) It was the strip lines who were imported from AutoCad *.sat format. The ends where lines touch the port was not perfectly fited:) With a lot of zoom I saw it.
Electromagnetic Design and Simulation :: 12-02-2004 01:57 :: Mantas :: Replies: 4 :: Views: 1661
I am trying to use CST MWS 5.0 to simulate a spiral inductor with lossy substrate and non-perfect conductor. I got a fatal error with a message that "Calculation is aborted due to port memory exception. please reduce number of ports or simulation duration." Anybody knows what it means?
Added after 5 minutes:
Electromagnetic Design and Simulation :: 01-19-2005 17:06 :: loucy :: Replies: 1 :: Views: 1251
In HFSS tutorial, it is written:
"It is recommended that only surfaces that are exposed to the background be degined as Wave Ports."
"If you want to apply waveports to the interior of a structure, you must create an inner void or select the surface of an interior object thet is assign a perfect conductor material property...."
When my wa
Electromagnetic Design and Simulation :: 02-11-2005 10:53 :: haydar :: Replies: 13 :: Views: 9652
Yes, between the conductors. I would connect the centers of the connectors if the metal in not perfect conductor, if it is PEC then it can be between some edge points.
The direction only changes the phase of the S21 that is calculated. Better if you keep the same direction, then at the limit of 0 length you will have same phase, as normal, (...)
Electromagnetic Design and Simulation :: 03-18-2005 13:01 :: fekete :: Replies: 20 :: Views: 1876
In momentum, How to define a sheet resistor in a transmission line. I need this structure: a cpw with a gap, and there is a 20 Ohm sheet resistor in the gap, the cpw is a perfect conductor.
Can I draw a pad in the gap, as R between C| |C , and define its value is 20Ohm in momentum?
Electromagnetic Design and Simulation :: 05-02-2005 12:48 :: yzriver :: Replies: 0 :: Views: 671
the problem was sorted out. it was in the heavy meshing at the edges as i was using copper instead of the perfect conductor. so i changed to pec and the meshes worked out properly and gave me results
Electromagnetic Design and Simulation :: 09-21-2005 05:41 :: sunyvel :: Replies: 5 :: Views: 1111
Yes, the waveport in HFSS can have lossy dielectric and/or good (non-perfect) conductor.
my guess for your problem:
1. 2xTsub is hardly "large" enough, check convergence w.r.t. all the sizes that you set to be around 2xTsub.
2. make sure you understand the unit of the HFSS answer correctly.
Electromagnetic Design and Simulation :: 09-07-2005 13:10 :: loucy :: Replies: 3 :: Views: 1381
Good morning to all. I am new to this forum and in HFSS (first design for me) and I have encountered a problem in my design. I am trying to draw a polyedron inside another polyedron (outside-->vacuum, inside-->perfect conductor) but I get the error message that the 3D model is incorrect because these two intersect. I have the design (I do not know
Electromagnetic Design and Simulation :: 02-02-2006 03:38 :: Athina :: Replies: 1 :: Views: 1353
Why does the quality factor of the on-chip spiral inductor have a peak? I mean what dominate the loss at low freq. and what at high freq.?
Of course it has a peak since it's not a perfect inductor, instead it has many parasitic effects. At low freq, substrate loss and ohmic loss dominate, while at
Electromagnetic Design and Simulation :: 03-08-2006 05:20 :: wlcsp :: Replies: 38 :: Views: 3750
MEEP is a free finite-difference time-domain (FDTD) simulation software package developed at MIT to model electromagnetic systems, along with MPB eigenmode package. Its features include:
Free software under the GNU GPL.
Simulation in 1d, 2d, 3d, and cylindrical coordinates.
Distributed memory parallelism on any system supporting the MPI sta
Software Links :: 04-03-2006 03:39 :: crystal503 :: Replies: 0 :: Views: 841
Hello, everyone. In present, I meet aproblem about the discrete port in CST MWS.
The object is perfect conductor. When I set the discrete port on my model. I use the tool on the toolbar to select the middle points of two edge and then set the port on this two points. The discrete port will be set on the line which link the two points automatically
Electromagnetic Design and Simulation :: 05-03-2006 08:38 :: yuanzy97 :: Replies: 9 :: Views: 2777
I am trying to design a monopole PCB antenna using HFSS. However, I am not familiar with the software as well as concepts of monopole.
1. regarding the HFSS, any friends knows how to create a right structure? I use a thinkless rectangle to simulate the monopole, a box to simulate FR4 PCB, and another sheet to simulate the ground. Both gro
RF, Microwave, Antennas and Optics :: 07-25-2006 02:43 :: RedMage :: Replies: 3 :: Views: 1325
I have this exercise which I cannot solve. Can anyone help or point out a site or an ebook? This is the exercise.
We must design an antenna (operation frequency f=30MHz) implemented with an array of horizontal dipoles k/2 that presents one single lobe in the radiation chart and in 30 degrees line with the ground. We want to find the ga
RF, Microwave, Antennas and Optics :: 09-17-2006 12:40 :: kostbill :: Replies: 1 :: Views: 607
that is a nice question, but you can think of it this way
For perfect dielectric (no losses) tand = 0
For perfect conductor (no losses, if you like to call it this way) tand = inf.
The losses of the medium depends on where the current will flow. For lossy dielectrics, the current (if you consider it conduction current) flows in (...)
Electromagnetic Design and Simulation :: 11-01-2006 08:30 :: adel_48 :: Replies: 5 :: Views: 1692
I'm trying to simulate a log-periodic antenna in CST 2006. I've placed the port in the center at the feed point.
Transient solver keeps reporting error "port is inside of a perfect conductor" (not the exact words) and terminates.
Since I'm a beginner with CST, please help me solve this problem. Check my structure for errors...
Electromagnetic Design and Simulation :: 03-14-2007 20:12 :: rfmw :: Replies: 9 :: Views: 983
This is discussed in 2 pages in Microwave Enginnering 2nd ed book by David Pozar.
It's related to plane wave reflection from a media interface where is a media is no longer a perfect conductor.
Then the surface impedance is the same as "intrinsic impedance", which is also expressed as Zc=(1-i)/(co
RF, Microwave, Antennas and Optics :: 06-25-2007 04:21 :: DrunkBear :: Replies: 5 :: Views: 4624
In a simulation model you have to define everything. There is no such thing as "undefinded". rrumpf's explanation is very theoretical, so I want to add two easy examples:
1) When you simulate a hollow waveguide (hwg), you create the inside as a vacuum box. Then you define the boundaries as perfect condutor (and the waveports of course) and you hav
Electromagnetic Design and Simulation :: 07-30-2007 05:00 :: cd79 :: Replies: 4 :: Views: 999
I think you can just use a perfect conductor as material. This represents a material with no losses, hence infinite conductivity. For the ground you can use a perfect electric boundary condition.
Electromagnetic Design and Simulation :: 12-16-2007 21:17 :: Yayray :: Replies: 6 :: Views: 1715
Place a thin box with of perfect conductor
with the face coincident with the rectangle to which you want
assign the waveport
then assign the waveport to the rectangle
Hope this helps
Electromagnetic Design and Simulation :: 03-06-2008 07:39 :: secondalinea :: Replies: 1 :: Views: 787
I already used open ad space in the direction of propagation, and perfect conductor at the top and bottom of the structure as a boundary condition. and I don't have metal in my design.
Electromagnetic Design and Simulation :: 04-03-2008 07:57 :: yshelsaid :: Replies: 5 :: Views: 1535
If you want to apply wave ports to the interior of a structure, you must create an inner void or select the surface of an interior object that is assign a perfect conductor material property. Inner voids are automatically assigned the boundary outer.You can create an inner void by sorrounding one object entirely with another object, then subtractin
Electromagnetic Design and Simulation :: 04-30-2008 05:24 :: pamela81 :: Replies: 4 :: Views: 988
First of all, don't use any kind of slang in this group (it may be normal in your society but not here).
Secondly, the problem you are talking about is simple to solve. Before solving this please bear in mind the following points:
1. Use names for different solids/sheets: in your design you use box1, box1_1 .... circle_1 etc (that are automat
Electromagnetic Design and Simulation :: 07-23-2008 04:01 :: shameemkabir :: Replies: 2 :: Views: 1152
Since the semiconductor material is not a perfect conductor, some resistance is in series with this constant voltage load, see Figure 2.4. This means that the voltage drop will increase with current. The ESR (equivalent series resistance) of a low power 20mA LED is about 20 ohms, but a 1W350mA LED has an ESR of about 1?2 ohm (depending on (...)
Analog Circuit Design :: 07-26-2008 11:17 :: mesutyeni :: Replies: 4 :: Views: 1158
i want to know waht is different between cross product and dot product???
and fields at adielectric interface and fields at the interface with a perfect conductor
and what n(the normal unit vector mean????and from where it come
thank u for helping
Electronic Elementary Questions :: 10-17-2008 12:18 :: goodtime :: Replies: 4 :: Views: 2027
I was having the same problem, when I used two lumped ports in my structure. I never figured out why the Z results were wrong. Which lumped port of the two was used as an excitation port, what is the property of the other one was difficult to say. To solve the problem, I used only one lumped port and the other one was substituted by a resistor. I t
Electromagnetic Design and Simulation :: 11-04-2008 04:12 :: rfmw :: Replies: 6 :: Views: 4802
Hmm, yeah, not sure what I was smoking.
Anyway, it was confusing to me that your structure is *below* the ground plane not above it. Since the copper forms a nearly perfect conductor, there is no need for an air box above it. You can delete all that air and instead put it below the microstrip, where there is only a little bit of air now and more
Electromagnetic Design and Simulation :: 11-18-2008 10:38 :: shlomo22 :: Replies: 7 :: Views: 2341
I have the following question. Suppose I take an antenna with air substrate. Therefore there are no dielectric losses. The only source of loss is conductor loss, but I can made an antenna from silver and minimize the losses.
Now, there is a theorem that states that I can match any impedance to any other impedance at a single frequency point w
RF, Microwave, Antennas and Optics :: 01-22-2009 13:53 :: fencer32 :: Replies: 3 :: Views: 1010
the metal at optical frequency (especially visible wavelengths) is different from a microwave property, where metal can be considered as a perfect conductor. metals at optical frequency are dominated by the Drude dispertion. so, I suggest not to simulate your optical resonance cavity simply scaling the dimensions, as mentioned above.
RF, Microwave, Antennas and Optics :: 09-12-2009 22:21 :: jackle :: Replies: 3 :: Views: 1354
You're the man. Thanks for your help. No need for the project file because I can handle it from here.
I've a question for you. I've changed the perfect conductor to 0 mil and Trace1 to 0.7 mils in material to fit my work. I also changed EM Layer Mapping of Via & Copper to Trace 1. Why after simulating, the enclosure property of Via & C
RF, Microwave, Antennas and Optics :: 06-01-2009 15:02 :: UKnowWhat :: Replies: 3 :: Views: 1298
help will be very appreciated guys :cry:
You should be more careful or learn more about HFSS! :)
The surface of the cavity in the WG is perfect conductor! Use the HFSS->Boundary display in the menu to see it.
Fill the cavity by vacuum and do the microstrip line longer!
Electromagnetic Design and Simulation :: 06-23-2009 17:17 :: romka-04 :: Replies: 2 :: Views: 1845
i believe you need to see there example. go to the help! i learn there through analyzing there examples. maybe you need to increase the mesh so that your port is not in the perfect conductor line. then use subgridding to make the simulation faster. and maybe instead of using discrete port, if thats the one you use, use the waveguide port to make it
Electromagnetic Design and Simulation :: 08-05-2009 02:24 :: jongjong :: Replies: 1 :: Views: 1754
I am completely new at HFSS (v10) and I need to model a vertical monopole antenna. I want it to work at 434 MHz and therefore made it 17 cm long (in stainless steel). I also added a infinite ground plane (in perfect conductor), a wave port and an air box.
The radiation pattern looks alright but somehow the antenna doesn't resonat
Electromagnetic Design and Simulation :: 08-05-2009 06:55 :: 100drine :: Replies: 2 :: Views: 1611
Is it possible to implement closed shield in Agilent Momentum?
For ex. Momentum gives non zero coupling between two small dipoles
when one of them is in the perfect conductor box. Box is vias between two closed boundary.!(?)
it looks via mesh is coarse to currents induced on vias cancell field of inner dipole.
Electromagnetic Design and Simulation :: 09-24-2009 09:47 :: Grig :: Replies: 2 :: Views: 1045
I saw an article talking about the permittivity of a highly conductive material is very large and infinite for the perfect conductor.
The following is from efunda.com
"In general, good conductors such as metals have an essentially infinite permittivity. Finite permittivities are normally associated with dielectric materials that have (...)
Electromagnetic Design and Simulation :: 12-16-2009 22:42 :: jay799 :: Replies: 3 :: Views: 4722
I am trying to duplicate the results in "Absorbing Frequency-Selective-Surface for the mm-Wave Range" by Sakran et al. for the coupling between two FSS antennas. I have recreated the structure in the attached HFSS file. But my results are incorrect. I get exactly zero coupling between antennas (it should be -30dB, low but not zero). Looking at the
Electromagnetic Design and Simulation :: 05-04-2010 07:18 :: shlomo22 :: Replies: 2 :: Views: 1177
I see it is very easy to setup this just create em structure with tw dielectric layers
stack up & define FR4 & Air then bottom boundary condition as perfect conductor (Ground) Then Draw the Microstrip Antenna structure....
It is very similar to suspended Microstrip structure setup...
Attach your MWO file (*.emp) with di
RF, Microwave, Antennas and Optics :: 07-07-2010 01:12 :: Manjunatha_hv :: Replies: 1 :: Views: 902
All FDTD software that I know supports lossless metal (perfect conductor). No problem.
Electromagnetic Design and Simulation :: 08-28-2010 14:02 :: volker_muehlhaus :: Replies: 3 :: Views: 1200