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21 Threads found on edaboard.com: **Plot 3db Bandwidth**

vary the input frequency and calculate output voltage and **plot** graph between
frequency and voltage ratio in db and find **3db** **bandwidth**

Electronic Elementary Questions :: 13.03.2006 11:18 :: satyasri :: Replies: **1** :: Views: **706**

For a nonlinear Class E Power Amplifier, if I want to check its **3db** **bandwidth**,
do I just do a parametric sweep analysis of frequency of the input signal and see the frequency vs power gain **plot**?Use PSS Analysis with sweeping fundamental frequency which is a frequency of driving signal.

RF, Microwave, Antennas and Optics :: 26.05.2011 12:37 :: pancho_hideboo :: Replies: **1** :: Views: **685**

Hi,
How do I measure the -**3db** **bandwidth** of an antenna in HFSS?
Is it by **plot**ting the S11 and obtain the **bandwidth** from there? If yes, do I measure the **bandwidth** with reference to the -**3db** point on the S11 curve? Or is it some other reference point?
Also, in real-life measurements, how (...)

Electromagnetic Design and Simulation :: 25.10.2006 03:37 :: Kin :: Replies: **5** :: Views: **2968**

it depends, **3db** **bandwidth** is the point open loop where the gain of the opamp drops by **3db**. this is also the half power frequency and for most analog circuits **3db** is a good level of suppression, this frequency/gain will change with feedback however, this can be modeled/visualized using bode **plot**s.

Electronic Elementary Questions :: 11.04.2007 16:46 :: ender84567 :: Replies: **8** :: Views: **1495**

Hi Guys,
I have question here. I have designed a transimpedance amplifier (TIA) which works at 1.25Gbps. I have run the AC simulation at the package level (wire-bonding model). Attached are the 2 **plot**s of the gain fucntion. Bode1 is the gain function with the multiple ground pin and Bode2 is the gain function with single ground pin. If we look a

Analog Circuit Design :: 02.01.2008 00:11 :: suria3 :: Replies: **3** :: Views: **962**

I design a Transimpedence Amp in 0.25 with 7**3db**ohm(4200ohm) gain and 1G **bandwidth**
with input and output cap 2pF.
The **3db** **bandwidth** is about 1G in magnitude,but when Frequence more than 500M, phase become 180(inverse).Can I say the **bandwidth** of the Amp is more than 1G? And How to revise it.Thanks. (...)

Analog IC Design and Layout :: 19.01.2008 15:26 :: wangkes9 :: Replies: **2** :: Views: **832**

your **plot**ting the Nyquist **bandwidth**, they are not different. The **3db** **bandwidth** is the full range of frequencies over which the signal is present **3db** below the max.
When you **plot** depending on how you **plot**, the **plot** can soemtiems extend towards negative (...)

Digital communication :: 18.07.2011 20:33 :: kalyanasv :: Replies: **5** :: Views: **483**

Hum
remember what is the Laplace transforme of capacitor is something as 1/Cs with s=jw
Now if you use a logarithmique scale (as Bode **plot**) what do you get ?
-20 Log(w)-20Log(C) (So a draw in a X logarithmique scale).Nevertheless you need to polarize your PMOS Capacitor before to perform this AC simulation.
I hope it will help you on probl

Analog IC Design and Layout :: 11.02.2006 15:45 :: MLR67 :: Replies: **4** :: Views: **684**

I think
wn=sqrt(Kvco*Icp/N*C1)
wn is natural frequency, N is the divider ratio, Icp is charge pump current, Kvco is the gain of the VCO.
and wc=1.55wn
w-**3db**=2.06wn
wc is cross frequency in the bode **plot**
w-**3db** is the closed loop -**3db** bandwith
Approximately,BW=Kvco*R*Ip/(2pi*M)
now what is the M??? (...)

Analog Circuit Design :: 19.10.2006 03:59 :: Joestar :: Replies: **17** :: Views: **3285**

I would make a simple lumped element resonator as follows:
At port 1, a series coupling capacitor Cc.
In the middle three elements in parallel to ground, L,C,R
From the middle to port 2, another coupling capacitor Cc.
The circuit will resonate at approximately the frequency f0=1/(2Π√LC). Why not exactly that frequency

RF, Microwave, Antennas and Optics :: 18.02.2007 08:00 :: biff44 :: Replies: **2** :: Views: **761**

I am having a problem with op amp band width and the
bode **plot** how it is **plot**ed
what is the 3b point what is its significance in op map....:?:
can any one provide me any material regarding this or sugest any book..

Electronic Elementary Questions :: 01.04.2007 09:51 :: hussain_kiet :: Replies: **2** :: Views: **879**

Consider a single real zero in the left half of the s-plane. This will have the form (s/z+1) ==> (jw/z+1) in time constant form. At low frequencies (w near 0), the magnitude of this term is approximately 1 ==> 0 db. At high frequencies (w/z >> 1), the magnitude of this term is approximately |w/z| ==> 20*log_10(|w/z|) db. At frequency w=w1, t

Electronic Elementary Questions :: 25.05.2007 11:21 :: powersys :: Replies: **1** :: Views: **569**

I measured some parallel connected LC tanks and get one-port S parameters with 50 Ohm port impedance.
I want to extract Q value of LC tanks, but I think the one-port S-params I get is loaded S parameters. From the measurement data, the |Z11| is approximately 50Ohm(equals port impedance) and the 20log|S21| is not sharp.
Is there any ways to get

RF, Microwave, Antennas and Optics :: 07.10.2007 23:47 :: wizardz :: Replies: **2** :: Views: **705**

Hi
Could you please specify more clearly?
The PXF analysis is almost the same as XF analysis.
You can **plot** gain diagram (in dB) , and where the frequency of DCgain(max)-**3db** is your BW.

Analog Circuit Design :: 12.06.2008 04:56 :: chungming :: Replies: **2** :: Views: **442**

i guess what the stb simulation does is for the loop-gain, which will include the feedback factor. so the amplitude response in the bode **plot** will actually move up or down according the feedback factor, and the unity gain **bandwidth** changes..

Analog IC Design and Layout :: 01.07.2010 09:30 :: windknows :: Replies: **5** :: Views: **2009**

Connect a high L (10H) from output to neg input of opamp and a high C (10F) from neg input to ground. connect a AC source with AC-Mag=1V. add a cap at the output of the opamp to GND( depends on your load, typ 1p F). now run a AC analysis, sweep freq from 1Hz to 10Ghz. **plot** dB20(Vout_Opamp) and phase(Vout_Opamp) to get gain and phase response (wher

Analog IC Design and Layout :: 04.05.2012 11:10 :: findsriharsha :: Replies: **8** :: Views: **891**

In waveform window select "Axis" -> "X axis" menu. There is a "**plot** vs" button at the bottom of pop-up X axis window. Usualy it set to "Independent variable" but clicking on the button you can change X axis to any **plot**ted waveform.
BTW what kind of analysis you are talking about? For AC analysis Voltage vs frequency is a default setting.

ASIC Design Methodologies and Tools (Digital) :: 02.12.2004 20:14 :: Fom :: Replies: **16** :: Views: **2705**

Because the **3db** point is a convienent point to use. It represents the point at which the output power has dropped to 50%. It is also useful because the **3db** point represents a 45 degree phase shift which is a nice number to understand what is going in regards to the bode **plot**.
The **3db** point just works out to nice (...)

Analog Circuit Design :: 01.01.2009 15:08 :: haff99 :: Replies: **12** :: Views: **10683**

n=-10:1:10;
K=1;
f=5;
f0=697;
wc=2.*pi.*f;
w0=2.*pi.*f0;
hlp=(K./(pi.*n)).*sin(n.*wc);
hbp=(2.*cos(n.*w0)).*hlp;
here is my code, this code designs a digital FIR bandpass filter , I need to **plot** the frequency response of H'(w). Thank you.
Is hbp the impulse response of the filter, then you can find the freq. res

Digital Signal Processing :: 02.10.2010 15:02 :: Communications_Engineer :: Replies: **5** :: Views: **559**

hi,
if your gain is Vout/Iin than it is something like 1.296-1.205 / 200u = 5300. and for your **bandwidth** you have to check where your 20log(Av) **plot** decreases by 3, i.e. the -**3db** point. that is the upper limit of your **bandwidth**. but the graphs you have there are seperate graphs.

Analog IC Design and Layout :: 29.10.2010 05:33 :: keremcant :: Replies: **6** :: Views: **563**

The peak gain is the maximum gain of your antenna.
And the total gain is the gain in the given direction.
Your results indicate that Theta=360 and Phi=0 isn't the direction of your maximum gain.
You can **plot** a 3d diagram for one frequency and check the gain figure for the direction of the maximum gain.

RF, Microwave, Antennas and Optics :: 23.04.2012 07:32 :: flanello :: Replies: **1** :: Views: **353**

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