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Plot 3db Bandwidth

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21 Threads found on edaboard.com: Plot 3db Bandwidth
vary the input frequency and calculate output voltage and plot graph between frequency and voltage ratio in db and find 3db bandwidth
For a nonlinear Class E Power Amplifier, if I want to check its 3db bandwidth, do I just do a parametric sweep analysis of frequency of the input signal and see the frequency vs power gain plot?Use PSS Analysis with sweeping fundamental frequency which is a frequency of driving signal.
Hi, How do I measure the -3db bandwidth of an antenna in HFSS? Is it by plotting the S11 and obtain the bandwidth from there? If yes, do I measure the bandwidth with reference to the -3db point on the S11 curve? Or is it some other reference point? Also, in real-life measurements, how (...)
it depends, 3db bandwidth is the point open loop where the gain of the opamp drops by 3db. this is also the half power frequency and for most analog circuits 3db is a good level of suppression, this frequency/gain will change with feedback however, this can be modeled/visualized using bode plots.
Hi Guys, I have question here. I have designed a transimpedance amplifier (TIA) which works at 1.25Gbps. I have run the AC simulation at the package level (wire-bonding model). Attached are the 2 plots of the gain fucntion. Bode1 is the gain function with the multiple ground pin and Bode2 is the gain function with single ground pin. If we look a
I design a Transimpedence Amp in 0.25 with 73dbohm(4200ohm) gain and 1G bandwidth with input and output cap 2pF. The 3db bandwidth is about 1G in magnitude,but when Frequence more than 500M, phase become 180(inverse).Can I say the bandwidth of the Amp is more than 1G? And How to revise it.Thanks. (...)
your plotting the Nyquist bandwidth, they are not different. The 3db bandwidth is the full range of frequencies over which the signal is present 3db below the max. When you plot depending on how you plot, the plot can soemtiems extend towards negative (...)
Hum remember what is the Laplace transforme of capacitor is something as 1/Cs with s=jw Now if you use a logarithmique scale (as Bode plot) what do you get ? -20 Log(w)-20Log(C) (So a draw in a X logarithmique scale).Nevertheless you need to polarize your PMOS Capacitor before to perform this AC simulation. I hope it will help you on probl
I think wn=sqrt(Kvco*Icp/N*C1) wn is natural frequency, N is the divider ratio, Icp is charge pump current, Kvco is the gain of the VCO. and wc=1.55wn w-3db=2.06wn wc is cross frequency in the bode plot w-3db is the closed loop -3db bandwith Approximately,BW=Kvco*R*Ip/(2pi*M) now what is the M??? (...)
I would make a simple lumped element resonator as follows: At port 1, a series coupling capacitor Cc. In the middle three elements in parallel to ground, L,C,R From the middle to port 2, another coupling capacitor Cc. The circuit will resonate at approximately the frequency f0=1/(2Π√LC). Why not exactly that frequency
I am having a problem with op amp band width and the bode plot how it is ploted what is the 3b point what is its significance in op map....:?: can any one provide me any material regarding this or sugest any book..
I think the transition point corresponds to the 3db point of the log magnitude. This is where the gain drops to 1/\sqrt{2} of the flat band value. This is also known as the half-power bandwidth. Take for example a lowpass filter with transfer function \frac{1}{1+s/z} with the transition point is at \omega=z[/
I measured some parallel connected LC tanks and get one-port S parameters with 50 Ohm port impedance. I want to extract Q value of LC tanks, but I think the one-port S-params I get is loaded S parameters. From the measurement data, the |Z11| is approximately 50Ohm(equals port impedance) and the 20log|S21| is not sharp. Is there any ways to get
Hi Could you please specify more clearly? The PXF analysis is almost the same as XF analysis. You can plot gain diagram (in dB) , and where the frequency of DCgain(max)-3db is your BW.
i guess what the stb simulation does is for the loop-gain, which will include the feedback factor. so the amplitude response in the bode plot will actually move up or down according the feedback factor, and the unity gain bandwidth changes..
Connect a high L (10H) from output to neg input of opamp and a high C (10F) from neg input to ground. connect a AC source with AC-Mag=1V. add a cap at the output of the opamp to GND( depends on your load, typ 1p F). now run a AC analysis, sweep freq from 1Hz to 10Ghz. plot dB20(Vout_Opamp) and phase(Vout_Opamp) to get gain and phase response (wher
In waveform window select "Axis" -> "X axis" menu. There is a "plot vs" button at the bottom of pop-up X axis window. Usualy it set to "Independent variable" but clicking on the button you can change X axis to any plotted waveform. BTW what kind of analysis you are talking about? For AC analysis Voltage vs frequency is a default setting.
Because the 3db point is a convienent point to use. It represents the point at which the output power has dropped to 50%. It is also useful because the 3db point represents a 45 degree phase shift which is a nice number to understand what is going in regards to the bode plot. The 3db point just works out to nice (...)
n=-10:1:10; K=1; f=5; f0=697; wc=2.*pi.*f; w0=2.*pi.*f0; hlp=(K./(pi.*n)).*sin(n.*wc); hbp=(2.*cos(n.*w0)).*hlp; here is my code, this code designs a digital FIR bandpass filter , I need to plot the frequency response of H'(w). Thank you.
hi, if your gain is Vout/Iin than it is something like 1.296-1.205 / 200u = 5300. and for your bandwidth you have to check where your 20log(Av) plot decreases by 3, i.e. the -3db point. that is the upper limit of your bandwidth. but the graphs you have there are seperate graphs.
The peak gain is the maximum gain of your antenna. And the total gain is the gain in the given direction. Your results indicate that Theta=360 and Phi=0 isn't the direction of your maximum gain. You can plot a 3d diagram for one frequency and check the gain figure for the direction of the maximum gain.