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36 Threads found on Shannon Channel Capacity
my professor told that there is no "shannon's channel capacity law" for the 'cooperative network'. i m very much interested in it. is there any white papers or books relating this topic.
According to shannon's theorem the channel capacity in a AWGN channel is given by: C=B log(1+S/N). I have a doubt : Is C given in Bit rate ( Bits/sec) or Bauds (Symbols/sec) , if it is given in bit rate, I am not able to understand how the modulation schemes can be related to this equation. Could anyone please give an ex
Bandwidth is the range of frequency that suffers an atenuation less than 3db when the signal pass throught the channel. channel capacity is the maximum information rate that a channel is able to transmite/receive. The channel capacity and the bandwidth of a channel is (...)
What is the relations between shannon theorwm and channel coding?
Hi! I'm in trouble to solve the channel capacity in the case of BPSK using by matlab. I can figure it out as a function of SNR. I think that I'm confused the SNR and Eb/No. Does anyone tell me how to solve it? And does anyone have a matlab file which is about shannon limit?
I suggest you find a telecomm textbook to check the answers. I alomst forgot it because I studied it 16 years ago and didn't use it until now. The shannon equation describe the maximum capacity limit in theory, but in fact for CDMA, say 5MHz and 3.84Mcps, it is far below the shannon capacity. So in fact the (...)
what is meant by cooperative networks in mobile communication. I heard that there is no shannon channel capacity law for this network yet, is it so.
Hi I think answer of mkhan is not true. capacity is the same in all of the mentioned method. capacity is just depend on SNR and BW. capacity of the channel is the famous work of shannon. capacity is not depent on modulation but it is different when transmitter have some knowledge about (...)
the shannon's law R=BWlog2(1+C/N) in a PSSS system Is R the symbol rate here? and BW is still the channel bandwidth? Thanks!
Hi, Each parameter is defined separately,but all are related in one form or another.It's like this: S/N is defined as The ratio of Average Signal Power to Noise Power.Generally S/N is measured at the output of the receiver and as per ITU regulations, the S/N that should be acheived at the output of the telephone channel is 50dB. Now,Spect
In an excel spreadsheet I am comparing the channel capacity performance of FSK and QPSK. I know from my studies that QPSK transmit 2 bits per symbol wheras FSK can transmit 1 bit per symbol. This means that QPSK can send the same amount of bits as FSK using half as much bandwidth that FSK uses or QPSK can send twice as many bits as FSK using the
QPSK is only a modulation scheme. i.e. the Eb/No in shannons theorem becomes Es/No. i.e Eb/No= Es/No *1/R . for QPSK we transmit twoice the number of bits as BPSK i.e. M=2. channel capacity theorem a.k.a. shannon's Theorem.
Hello all, In my project, I am trying to achieve near shannon performance for 4x4 MIMO using 16 QAM on rayleigh fading channel. For that i need to calculate the shannon capacity of rayleigh fading channel for 4x4 MIMO. Whats the formula/approach for that? Is this code doing it right way?
We ca not use the shannon formula for a given modulation. This formula is a theoretical limit, which can be achieved only when the input signal is drawn from Gaussian distribution, which obviously not practical, since Gaussian distribution is a continuous function. The formula in the link says that the number of bits must be less than or equal
Ergosic and quasi-static are different. In the quasi-static case the shannon capacity does not exist. THey have to use the outage capacity instead while in the ergodic channel, the shannon capacity is well define since the shannon capacity is the average (...)
what is 0.188 dB? SNR or energy per bit(Eb/N0)?? What the text book do you read? The shannon limit is -1.6 dB (Eb/N0) regardless modulation schemes. Also the rate 1/2 is a rate for BSC channel whose the maxmimum capacity is one. This is in the different part of the system.
in the information theory u have the shannon's theorems. it states: C = BW. log(1+SNR) i.e; capacity of the channel is related to bandwidth and SNR of the signal and noise. and capacity is related to Hs (Antrpy of the source ) and Rs (Symbol rate). for more detailed discussion refer to "digital communication " books. (...)
Hi,, man Q refers to the Quality factor or the selectivity of the Resonant circuit, Selectivity is the reciprocal of Bandwidth,, whereas the bit rate is the channel capacity, which refers to shannon's capacity formula such that: C = B log base 2 (1+SNR) Where, C = channel (...)
your question is vague. try rephrasing it. P.S: Are you looking for shannon's channel capacity theorem?
use shannon-Hartly Theorem to find the channel capcity of a channel
I dont understand shannon limit. For example I see that "single-link code is approximately 1.3dB away from the shannon limit at an error rate of 10^-5. so how this comparison is made . if you could help please ... Thankyou very much for this..
hi, all we use the shannon capacity and outage capacity in different case. can anyone talk about what decides the channel is ergodic or no-ergodic. is it the propagat environment or others? thanks:D
Dear Bratija, shannon's limit does not depend on BER. shannon's limit tell us the minimum possible Eb/No required to achieve an arbitrarily small probability of error as M->∞. (M is the number of signaling levels for the modulation technique, for BPSK M=2, QPSK M=4 , and so on..). It gives the minimum possible Eb/No that satisfies
Outage probability is related to the channel capacity which returns to the channel model assumed of course, differing from each relay to another makes a relay can contribute in cooperation or not which is mainly based on its Outage probability or in other terms outage "capacity" which is limited by Signal To Noise ratio (...)
Dear Bulx, I appreciated your answer but it was not what I was asking for. I am aware about the limit posed by the channel capacity theorem by shannon C = B log2(1+SNR) that for a 25 kHz channel and a target sensitivity of 10 dB gives us the theoretical capacity limit of 166455 bps that is in the (...)
does any body know the capacity of a communication link based on QPSK modulation; how is it related to the shannon theorem? When a modulation scheme is used, we call the "capacity" the achievable rate. In the case of QPSK, the maximum achievable rate is 2 bit/channel use. On the other hand, when the (...)
Th 3db BW is 2KHz. shannon has a channel capacity theorem: C=B*(1+SNR) but that is only for capacity. Here bandwidth measurement is a differential measurement i.e. it can be 2KHz centered at f=0Hz. When you multiply 3db_BW *f you are effectively increasing the BW which is definitely not the signal BW as shown above. (...)
has a transfer characteristic |H(f) given in the link below. The transmission is at maximum error-free rate of 4,800 bps. Compute the SNR (signal-to-noise-ratio) at the channel output. Does the output signal suffer from any distortion? ImageShack? - Online Photo and Video Hosting
I have similar question. How to simulate capacity of channel? Using shannon's limit, I have obtained the capacity. I plotted capacity v/s SNR. But my question is how to simulate? I want to simulate/show that above the maximum data rate, there is loss/error. I want to simulate the way simulate BER. I request (...)
There is no direct relation between data rate and SNR. If you mean a channel capacity (maximum throughput rate), google the shannon-Hartley theorem.
IDMA (Interleave-Division Multiple-Access ) is a new method of digital communication that is very powerful and can approach the shannon limit. The technique is very good for multiple user communication as is performed in a mobile phone connection from the phone to the basestation
perhaps I am oversimplifying. you just multiply the upstream (towards exchange) rate for ADSL users (1 Mbps, say) and that for SHDSL users (10 Mbps, say), you get total bitrate in upstream (11 *200,000). Find out nominal downstream rates for both, and arrive at the same for downstream rates. The bitrates stem from maximum capacity (bitrat
There are a lot of papers on this topic (with a bias to information-theoretical perspective here): the work started by S. Hanly and P. Whiting, ?Information-theoretic capacity of multi-receiver networks,? Telecommun. Syst., vol. 1, pp. 1?42, 1993. A. D. Wyner, ?shannon-theoretic approach to a Gaussian cellular multiple-access c
Bandwidth is the range of frequency that is used to transmit data.. Suppose if u are using 2KHz to 5KHz range of frequencies to transmit the data then the Bandwidth becomes 3KHz(5-2). Bandwidth is related to capacity of a channel (optical fiber, coaxial cable, twisted pair wires are all channels) by shannon's Formula as (...)
what is multiplexing gain and where it applies? Also please talk about diversity gain and diversity-multiplexing trade off? Thanks in advance If you mean multiplexing gain in MIMO context... When MIMO is proposed it is shown to achieve higher rate than SISO. How to measure the gain? Well, from shannon theorem we know th
In my opinion, the effect of noise is that we can not transmit information over any channel with an unbounded rate, that is every channel has a capacity, just as shannon's celebrated channel coding theorem states.