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## Shannon Channel Capacity |

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shannon capacity , channel capacity , capacity awgn channel , mimo channel capacity

36 Threads found on edaboard.com: **Shannon Channel Capacity**

my professor told that there is no "**shannon**'s **channel** **capacity** law" for the 'cooperative network'.
i m very much interested in it. is there any white papers or books relating this topic.

Digital communication :: 28.12.2005 13:16 :: rednewguy :: Replies: **2** :: Views: **1433**

According to **shannon**'s theorem the **channel** **capacity** in a AWGN **channel** is given by: C=B log(1+S/N).
I have a doubt : Is C given in Bit rate ( Bits/sec) or Bauds (Symbols/sec) , if it is given in bit rate, I am not able to understand how the modulation schemes can be related to this equation. Could anyone please give an ex

Digital communication :: 21.04.2006 18:25 :: ahmad_abdulghany :: Replies: **1** :: Views: **1902**

Bandwidth is the range of frequency that suffers an atenuation less than 3db when the signal pass throught the **channel**.
**channel** **capacity** is the maximum information rate that a **channel** is able to transmite/receive.
The **channel** **capacity** and the bandwidth of a **channel** is (...)

Electronic Elementary Questions :: 10.11.2006 18:35 :: claudiocamera :: Replies: **1** :: Views: **4811**

What is the relations between **shannon** theorwm and **channel** coding?

Electronic Elementary Questions :: 03.06.2007 06:40 :: amiran2001 :: Replies: **4** :: Views: **1271**

Hi!
I'm in trouble to solve the **channel** **capacity** in the case of BPSK using by matlab.
I can figure it out as a function of SNR.
I think that I'm confused the SNR and Eb/No.
Does anyone tell me how to solve it? And does anyone have a matlab file which is about **shannon** limit?

Digital communication :: 17.07.2009 01:00 :: horizon982 :: Replies: **2** :: Views: **1479**

I suggest you find a telecomm textbook to check the answers.
I alomst forgot it because I studied it 16 years ago and didn't use it until now.
The **shannon** equation describe the maximum **capacity** limit in theory, but in fact for CDMA, say 5MHz and 3.84Mcps, it is far below the **shannon** **capacity**.
So in fact the (...)

RF, Microwave, Antennas and Optics :: 03.01.2013 21:28 :: tony_lth :: Replies: **4** :: Views: **734**

what is meant by cooperative networks in mobile communication. I heard that there is no **shannon** **channel** **capacity** law for this network yet, is it so.

Electronic Elementary Questions :: 17.09.2005 11:36 :: rednewguy :: Replies: **0** :: Views: **853**

Hi
I think answer of mkhan is not true.
**capacity** is the same in all of the mentioned method. **capacity** is just depend on SNR and BW.
**capacity** of the **channel** is the famous work of **shannon**.
**capacity** is not depent on modulation but it is different when transmitter have some knowledge about (...)

Digital communication :: 20.05.2007 07:13 :: m_llaa :: Replies: **7** :: Views: **2686**

the **shannon**'s law
R=BWlog2(1+C/N)
in a PSSS system
Is R the symbol rate here?
and BW is still the **channel** bandwidth?
Thanks!

RF, Microwave, Antennas and Optics :: 09.08.2007 05:16 :: fanshuo :: Replies: **1** :: Views: **1258**

Hi,
Each parameter is defined separately,but all are related in one form or another.It's like this: S/N is defined as The ratio of Average Signal Power to Noise Power.Generally S/N is measured at the output of the receiver and as per ITU regulations, the S/N that should be acheived at the output of the telephone **channel** is 50dB.
Now,Spect

Digital communication :: 05.09.2008 09:57 :: Bhanumurthy :: Replies: **5** :: Views: **1451**

In an excel spreadsheet I am comparing the **channel** **capacity** performance of FSK and QPSK.
I know from my studies that QPSK transmit 2 bits per symbol wheras FSK can transmit 1 bit per symbol. This means that QPSK can send the same amount of bits as FSK using half as much bandwidth that FSK uses or QPSK can send twice as many bits as FSK using the

RF, Microwave, Antennas and Optics :: 07.10.2008 15:24 :: robismyname :: Replies: **2** :: Views: **2766**

QPSK is only a modulation scheme. i.e. the Eb/No in **shannon**s theorem becomes Es/No. i.e Eb/No= Es/No *1/R . for QPSK we transmit twoice the number of bits as BPSK i.e. M=2.
**channel** **capacity** theorem a.k.a. **shannon**'s Theorem.

RF, Microwave, Antennas and Optics :: 13.07.2011 18:11 :: kalyanasv :: Replies: **2** :: Views: **692**

Hello all,
In my project, I am trying to achieve near **shannon** performance for 4x4 MIMO using 16 QAM on rayleigh fading **channel**. For that i need to calculate the **shannon** **capacity** of rayleigh fading **channel** for 4x4 MIMO. Whats the formula/approach for that?
Is this code doing it right way?

Electromagnetic Design and Simulation :: 16.10.2012 12:11 :: varun_vkjain :: Replies: **1** :: Views: **385**

We ca not use the **shannon** formula for a given modulation. This formula is a theoretical limit, which can be achieved only when the input signal is drawn from Gaussian distribution, which obviously not practical, since Gaussian distribution is a continuous function.
The formula in the link says that the number of bits must be less than or equal

Digital communication :: 12.04.2013 20:40 :: David83 :: Replies: **4** :: Views: **837**

Ergosic and quasi-static are different. In the quasi-static case the **shannon** **capacity** does not exist. THey have to use the outage **capacity** instead while in the ergodic **channel**, the **shannon** **capacity** is well define since the **shannon** **capacity** is the average (...)

RF, Microwave, Antennas and Optics :: 14.11.2006 11:58 :: boy :: Replies: **7** :: Views: **6430**

what is 0.188 dB? SNR or energy per bit(Eb/N0)?? What the text book do you read? The **shannon** limit is -1.6 dB (Eb/N0) regardless modulation schemes. Also the rate 1/2 is a rate for BSC **channel** whose the maxmimum **capacity** is one. This is in the different part of the system.

RF, Microwave, Antennas and Optics :: 25.10.2005 09:22 :: boy :: Replies: **4** :: Views: **2193**

in the information theory u have the **shannon**'s theorems.
it states:
C = BW. log(1+SNR) i.e; **capacity** of the **channel** is related to bandwidth and SNR of the signal and noise.
and **capacity** is related to Hs (Antrpy of the source ) and Rs (Symbol rate).
for more detailed discussion refer to "digital communication " books. (...)

Digital communication :: 10.12.2005 14:18 :: mro83 :: Replies: **5** :: Views: **2563**

Hi,, man Q refers to the Quality factor or the selectivity of the Resonant circuit, Selectivity is the reciprocal of Bandwidth,, whereas the bit rate is the **channel** **capacity**, which refers to **shannon**'s **capacity** formula such that:
C = B log base 2 (1+SNR)
Where,
C = **channel** (...)

Digital Signal Processing :: 12.03.2007 14:26 :: qureshi :: Replies: **1** :: Views: **898**

your question is vague. try rephrasing it.
P.S:
Are you looking for **shannon**'s **channel** **capacity** theorem?

Digital Signal Processing :: 17.04.2007 10:21 :: hurrynarain :: Replies: **3** :: Views: **6926**

use **shannon**-Hartly Theorem to find the **channel** capcity of a **channel**

Digital communication :: 30.04.2007 04:19 :: akumar1 :: Replies: **2** :: Views: **899**

I dont understand **shannon** limit.
For example I see that "single-link code is approximately 1.3dB away from the **shannon** limit at an error rate of 10^-5.
so how this comparison is made .
if you could help please ...
Thankyou very much for this..

Digital communication :: 26.01.2008 17:17 :: asha19800 :: Replies: **3** :: Views: **1951**

hi, all
we use the **shannon** **capacity** and outage **capacity** in different case. can anyone talk about what decides the **channel** is ergodic or no-ergodic. is it the propagat environment or others?
thanks:D

Digital communication :: 23.04.2009 02:02 :: insatiable :: Replies: **4** :: Views: **3765**

Dear Bratija,
**shannon**'s limit does not depend on BER. **shannon**'s limit tell us the minimum possible Eb/No required to achieve an arbitrarily small probability of error as M->∞.
(M is the number of signaling levels for the modulation technique, for BPSK M=2, QPSK M=4 , and so on..).
It gives the minimum possible Eb/No that satisfies

Digital communication :: 23.11.2008 22:28 :: mathuranathan :: Replies: **12** :: Views: **11785**

Outage probability is related to the **channel** **capacity** which returns to the **channel** model assumed of course, differing from each relay to another makes a relay can contribute in cooperation or not which is mainly based on its Outage probability or in other terms outage "**capacity**" which is limited by Signal To Noise ratio (...)

Digital communication :: 09.11.2009 03:13 :: mohamed_bakr :: Replies: **5** :: Views: **2747**

Dear Bulx, I appreciated your answer but it was not what I was asking for.
I am aware about the limit posed by the **channel** **capacity** theorem by **shannon**
C = B log2(1+SNR)
that for a 25 kHz **channel** and a target sensitivity of 10 dB gives us the theoretical **capacity** limit of 166455 bps that is in the (...)

Digital communication :: 27.02.2010 15:02 :: mowgli :: Replies: **5** :: Views: **920**

does any body know the **capacity** of a communication link based on QPSK modulation;
how is it related to the **shannon** theorem?
When a modulation scheme is used, we call the "**capacity**" the achievable rate. In the case of QPSK, the maximum achievable rate is 2 bit/**channel** use. On the other hand, when the (...)

Digital communication :: 13.07.2011 11:31 :: David83 :: Replies: **1** :: Views: **546**

Th 3db BW is 2KHz.
**shannon** has a **channel** **capacity** theorem: C=B*(1+SNR) but that is only for **capacity**.
Here bandwidth measurement is a differential measurement i.e. it can be 2KHz centered at f=0Hz.
When you multiply 3db_BW *f you are effectively increasing the BW which is definitely not the signal BW as shown above. (...)

Digital communication :: 20.07.2011 07:40 :: kalyanasv :: Replies: **5** :: Views: **543**

has a transfer characteristic |H(f) given in the link below. The transmission is at maximum error-free rate of 4,800 bps. Compute the SNR (signal-to-noise-ratio) at the **channel** output. Does the output signal suffer from any distortion?
ImageShack? - Online Photo and Video Hosting

Digital Signal Processing :: 18.07.2011 11:14 :: naspek :: Replies: **1** :: Views: **633**

I have similar question.
How to simulate **capacity** of **channel**?
Using **shannon**'s limit, I have obtained the **capacity**. I plotted **capacity** v/s SNR.
But my question is how to simulate? I want to simulate/show that above the maximum data rate, there is loss/error.
I want to simulate the way simulate BER.
I request (...)

Digital communication :: 27.03.2012 13:19 :: abhijithbg :: Replies: **8** :: Views: **374**

There is no direct relation between data rate and SNR. If you mean a **channel** **capacity** (maximum throughput rate), google the **shannon**-Hartley theorem.

Digital communication :: 10.09.2012 02:49 :: Mityan :: Replies: **4** :: Views: **462**

IDMA (Interleave-Division Multiple-Access ) is a new method of digital communication that is very powerful and can approach the **shannon** limit. The technique is very good for multiple user communication as is performed in a mobile phone connection from the phone to the basestation

Digital communication :: 23.03.2006 02:49 :: mro83 :: Replies: **9** :: Views: **6522**

perhaps I am oversimplifying.
you just multiply the upstream (towards exchange) rate for ADSL users (1 Mbps, say) and that for SHDSL users (10 Mbps, say), you get total bitrate in upstream (11 *200,000).
Find out nominal downstream rates for both, and arrive at the same for downstream rates.
The bitrates stem from maximum **capacity** (bitrat

Network :: 16.05.2007 02:34 :: bulx :: Replies: **2** :: Views: **992**

There are a lot of papers on this topic (with a bias to information-theoretical perspective here):
the work started by
S. Hanly and P. Whiting, ?Information-theoretic **capacity** of multi-receiver
networks,? Telecommun. Syst., vol. 1, pp. 1?42, 1993.
A. D. Wyner, ?**shannon**-theoretic approach to a Gaussian cellular
multiple-access c

Digital communication :: 24.07.2007 20:10 :: changfa :: Replies: **2** :: Views: **1242**

Bandwidth is the range of frequency that is used to transmit data..
Suppose if u are using 2KHz to 5KHz range of frequencies to transmit the data then the Bandwidth becomes 3KHz(5-2).
Bandwidth is related to **capacity** of a **channel** (optical fiber, coaxial cable, twisted pair wires are all **channel**s) by **shannon**'s Formula as (...)

Network :: 14.09.2007 06:16 :: mathuranathan :: Replies: **2** :: Views: **546**

what is multiplexing gain and where it applies? Also please talk about diversity gain and diversity-multiplexing trade off? Thanks in advance
If you mean multiplexing gain in MIMO context...
When MIMO is proposed it is shown to achieve higher rate than SISO. How to measure the gain? Well, from **shannon** theorem we know th

Digital communication :: 19.11.2007 20:32 :: changfa :: Replies: **1** :: Views: **2924**

In my opinion, the effect of noise is that we can not transmit information over any **channel** with an unbounded rate, that is every **channel** has a **capacity**, just as **shannon**'s celebrated **channel** coding theorem states.

Digital communication :: 18.11.2007 09:48 :: toshine :: Replies: **2** :: Views: **527**

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