36 Threads found on edaboard.com: Shannon Channel Capacity
my professor told that there is no "shannon's channel capacity law" for the 'cooperative network'.
i m very much interested in it. is there any white papers or books relating this topic.
Digital communication :: 28.12.2005 13:16 :: rednewguy :: Replies: 2 :: Views: 1298
According to shannon's theorem the channel capacity in a AWGN channel is given by: C=B log(1+S/N).
I have a doubt : Is C given in Bit rate ( Bits/sec) or Bauds (Symbols/sec) , if it is given in bit rate, I am not able to understand how the modulation schemes can be related to this equation. Could anyone please give an (...)
Digital communication :: 21.04.2006 18:08 :: claudiocamera :: Replies: 1 :: Views: 1564
Bandwidth is the range of frequency that suffers an atenuation less than 3db when the signal pass throught the channel.
channel capacity is the maximum information rate that a channel is able to transmite/receive.
The channel capacity and the bandwidth of a channel is (...)
Electronic Elementary Questions :: 10.11.2006 18:35 :: claudiocamera :: Replies: 1 :: Views: 3810
What is the relations between shannon theorwm and channel coding?
Electronic Elementary Questions :: 03.06.2007 06:40 :: amiran2001 :: Replies: 4 :: Views: 1150
I'm in trouble to solve the channel capacity in the case of BPSK using by matlab.
I can figure it out as a function of SNR.
I think that I'm confused the SNR and Eb/No.
Does anyone tell me how to solve it? And does anyone have a matlab file which is about shannon limit?
Digital communication :: 17.07.2009 01:00 :: horizon982 :: Replies: 2 :: Views: 1232
I want to know that channel badwidth of 5MHz in case of WCDMA and data rate or chip rate of 3.84Mcps are somehow related ?
If yes then what is the relation ?
One relation I have come across is shannon's Relation but in that case we also need to know the SNR to calculate the data rate ?
Thanks in advance
RF, Microwave, Antennas and Optics :: 30.12.2012 10:15 :: nitink19 :: Replies: 4 :: Views: 445
what is meant by cooperative networks in mobile communication. I heard that there is no shannon channel capacity law for this network yet, is it so.
Electronic Elementary Questions :: 17.09.2005 11:36 :: rednewguy :: Replies: 0 :: Views: 696
I think answer of mkhan is not true.
capacity is the same in all of the mentioned method. capacity is just depend on SNR and BW.
capacity of the channel is the famous work of shannon.
capacity is not depent on modulation but it is different when transmitter have some knowledge about (...)
Digital communication :: 20.05.2007 07:13 :: m_llaa :: Replies: 7 :: Views: 2089
the shannon's law
in a PSSS system
Is R the symbol rate here?
and BW is still the channel bandwidth?
RF, Microwave, Antennas and Optics :: 09.08.2007 05:16 :: fanshuo :: Replies: 1 :: Views: 1063
Each parameter is defined separately,but all are related in one form or another.It's like this: S/N is defined as The ratio of Average Signal Power to Noise Power.Generally S/N is measured at the output of the receiver and as per ITU regulations, the S/N that should be acheived at the output of the telephone channel is 50dB.
Digital communication :: 05.09.2008 09:57 :: Bhanumurthy :: Replies: 5 :: Views: 1140
first Same MEAN POWER (1/2 of ones's and 1/2 of zeros'), Amplitude equal for all waveforms (ASK, FSK, PSK, etc)
then compare things:
ASK detector have one branch. Noise in only one branch. Mean Power
FSK detector have two branches. Noise in two branches. 2xMean Power
PSK detector only one branch. Noise in only one branch. 2xMean Po
RF, Microwave, Antennas and Optics :: 19.10.2008 14:42 :: teteamigo :: Replies: 2 :: Views: 2376
QPSK is only a modulation scheme. i.e. the Eb/No in shannons theorem becomes Es/No. i.e Eb/No= Es/No *1/R . for QPSK we transmit twoice the number of bits as BPSK i.e. M=2.
channel capacity theorem a.k.a. shannon's Theorem.
RF, Microwave, Antennas and Optics :: 13.07.2011 18:11 :: kalyanasv :: Replies: 2 :: Views: 589
In my project, I am trying to achieve near shannon performance for 4x4 MIMO using 16 QAM on rayleigh fading channel. For that i need to calculate the shannon capacity of rayleigh fading channel for 4x4 MIMO. Whats the formula/approach for that?
Is this code doing it right way?
Electromagnetic Design and Simulation :: 16.10.2012 12:11 :: varun_vkjain :: Replies: 1 :: Views: 279
We ca not use the shannon formula for a given modulation. This formula is a theoretical limit, which can be achieved only when the input signal is drawn from Gaussian distribution, which obviously not practical, since Gaussian distribution is a continuous function.
The formula in the link says that the number of bits must be less than or equal
Digital communication :: 12.04.2013 20:40 :: David83 :: Replies: 4 :: Views: 609
Ergosic and quasi-static are different. In the quasi-static case the shannon capacity does not exist. THey have to use the outage capacity instead while in the ergodic channel, the shannon capacity is well define since the shannon capacity is the average (...)
RF, Microwave, Antennas and Optics :: 14.11.2006 11:58 :: boy :: Replies: 7 :: Views: 5497
what is 0.188 dB? SNR or energy per bit(Eb/N0)?? What the text book do you read? The shannon limit is -1.6 dB (Eb/N0) regardless modulation schemes. Also the rate 1/2 is a rate for BSC channel whose the maxmimum capacity is one. This is in the different part of the system.
RF, Microwave, Antennas and Optics :: 25.10.2005 09:22 :: boy :: Replies: 4 :: Views: 1947
in the information theory u have the shannon's theorems.
C = BW. log(1+SNR) i.e; capacity of the channel is related to bandwidth and SNR of the signal and noise.
and capacity is related to Hs (Antrpy of the source ) and Rs (Symbol rate).
for more detailed discussion refer to "digital communication " books. (...)
Digital communication :: 10.12.2005 14:18 :: mro83 :: Replies: 5 :: Views: 2221
Hi,, man Q refers to the Quality factor or the selectivity of the Resonant circuit, Selectivity is the reciprocal of Bandwidth,, whereas the bit rate is the channel capacity, which refers to shannon's capacity formula such that:
C = B log base 2 (1+SNR)
C = channel (...)
Digital Signal Processing :: 12.03.2007 14:26 :: qureshi :: Replies: 1 :: Views: 778
your question is vague. try rephrasing it.
Are you looking for shannon's channel capacity theorem?
Digital Signal Processing :: 17.04.2007 10:21 :: hurrynarain :: Replies: 3 :: Views: 5748
use shannon-Hartly Theorem to find the channel capcity of a channel
Digital communication :: 30.04.2007 04:19 :: akumar1 :: Replies: 2 :: Views: 743
Just expanding on what Dimtrij said..
>>Does it mean that to gain error rate of 10^-5 you need 1.3 dB more power than required for shannon capacity ..does it mean like that ??
Yes. In other words, if you were to find out that ultimate code, you would be able to reduce your power by 1.3 db and still maintain your error rate to be 10^-5 (or lo
Digital communication :: 31.01.2008 01:09 :: bulx :: Replies: 3 :: Views: 1691
we use the shannon capacity and outage capacity in different case. can anyone talk about what decides the channel is ergodic or no-ergodic. is it the propagat environment or others?
As many people said above, ergodic channel has a long term constant bit rate. Actually, (...)
Digital communication :: 23.04.2009 23:34 :: yelvis :: Replies: 4 :: Views: 3518
shannon's limit does not depend on BER. shannon's limit tell us the minimum possible Eb/No required to achieve an arbitrarily small probability of error as M->∞.
(M is the number of signaling levels for the modulation technique, for BPSK M=2, QPSK M=4 , and so on..).
It gives the minimum possible Eb/No that satisfies
Digital communication :: 23.11.2008 22:28 :: mathuranathan :: Replies: 12 :: Views: 10893
Outage probability is related to the channel capacity which returns to the channel model assumed of course, differing from each relay to another makes a relay can contribute in cooperation or not which is mainly based on its Outage probability or in other terms outage "capacity" which is limited by Signal To Noise ratio (...)
Digital communication :: 09.11.2009 03:13 :: mohamed_bakr :: Replies: 5 :: Views: 2333
Dear Bulx, I appreciated your answer but it was not what I was asking for.
I am aware about the limit posed by the channel capacity theorem by shannon
C = B log2(1+SNR)
that for a 25 kHz channel and a target sensitivity of 10 dB gives us the theoretical capacity limit of 166455 bps that is in the (...)
Digital communication :: 27.02.2010 15:02 :: mowgli :: Replies: 5 :: Views: 794
does any body know the capacity of a communication link based on QPSK modulation;
how is it related to the shannon theorem?
Digital communication :: 13.07.2011 03:29 :: sharlotte :: Replies: 1 :: Views: 404
Th 3db BW is 2KHz.
shannon has a channel capacity theorem: C=B*(1+SNR) but that is only for capacity.
Here bandwidth measurement is a differential measurement i.e. it can be 2KHz centered at f=0Hz.
When you multiply 3db_BW *f you are effectively increasing the BW which is definitely not the signal BW as shown above. (...)
Digital communication :: 20.07.2011 07:40 :: kalyanasv :: Replies: 5 :: Views: 457
has a transfer characteristic |H(f) given in the link below. The transmission is at maximum error-free rate of 4,800 bps. Compute the SNR (signal-to-noise-ratio) at the channel output. Does the output signal suffer from any distortion?
ImageShack? - Online Photo and Video Hosting
Digital Signal Processing :: 18.07.2011 11:14 :: naspek :: Replies: 1 :: Views: 557
I have similar question.
How to simulate capacity of channel?
Using shannon's limit, I have obtained the capacity. I plotted capacity v/s SNR.
But my question is how to simulate? I want to simulate/show that above the maximum data rate, there is loss/error.
I want to simulate the way simulate BER.
I request (...)
Digital communication :: 27.03.2012 13:19 :: abhijithbg :: Replies: 8 :: Views: 284
There is no direct relation between data rate and SNR. If you mean a channel capacity (maximum throughput rate), google the shannon-Hartley theorem.
Digital communication :: 10.09.2012 02:49 :: Mityan :: Replies: 4 :: Views: 365
IDMA (Interleave-Division Multiple-Access ) is a new method of digital communication that is very powerful and can approach the shannon limit. The technique is very good for multiple user communication as is performed in a mobile phone connection from the phone to the basestation
Digital communication :: 23.03.2006 02:49 :: mro83 :: Replies: 9 :: Views: 5947
perhaps I am oversimplifying.
you just multiply the upstream (towards exchange) rate for ADSL users (1 Mbps, say) and that for SHDSL users (10 Mbps, say), you get total bitrate in upstream (11 *200,000).
Find out nominal downstream rates for both, and arrive at the same for downstream rates.
The bitrates stem from maximum capacity (bitrat
Network :: 16.05.2007 02:34 :: bulx :: Replies: 2 :: Views: 911
There are a lot of papers on this topic (with a bias to information-theoretical perspective here):
the work started by
S. Hanly and P. Whiting, ?Information-theoretic capacity of multi-receiver
networks,? Telecommun. Syst., vol. 1, pp. 1?42, 1993.
A. D. Wyner, ?shannon-theoretic approach to a Gaussian cellular
Digital communication :: 24.07.2007 20:10 :: changfa :: Replies: 2 :: Views: 1021
Bandwidth is the range of frequency that is used to transmit data..
Suppose if u are using 2KHz to 5KHz range of frequencies to transmit the data then the Bandwidth becomes 3KHz(5-2).
Bandwidth is related to capacity of a channel (optical fiber, coaxial cable, twisted pair wires are all channels) by shannon's Formula as (...)
Network :: 14.09.2007 06:16 :: mathuranathan :: Replies: 2 :: Views: 475
what is multiplexing gain and where it applies? Also please talk about diversity gain and diversity-multiplexing trade off? Thanks in advance
If you mean multiplexing gain in MIMO context...
When MIMO is proposed it is shown to achieve higher rate than SISO. How to measure the gain? Well, from shannon theorem we know th
Digital communication :: 19.11.2007 20:32 :: changfa :: Replies: 1 :: Views: 2496
In my opinion, the effect of noise is that we can not transmit information over any channel with an unbounded rate, that is every channel has a capacity, just as shannon's celebrated channel coding theorem states.
Digital communication :: 18.11.2007 09:48 :: toshine :: Replies: 2 :: Views: 448