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33 Threads found on Balanced Modulator
A balanced diode mixer is the usual solution to modulate a RF input signal with +/- 1. Or a balanced active modulator. "Modulating LNA" sounds counter-intuitive, because an amplifier is expected to have a defined gain sign, either positive or negative which doesn't depend on the power supply.
The SSB modulator from the left is from the issue April 1973 of Ham Radio Magazine. It has very poor side band rejection (< 20dB) and because is using single balanced mixers also the carrier rejection is not impressive. Even the author of the article mention that the side band rejection is not great, and the audio balance adjustment is very diffic
Hi can you please tell me if this circuit will work as a very simple SSB generator? What are the pros and cons? I consider a very simple poor performance ssb generator.
Hi i am trying to learn about amplitude modulators. Can anyone pls explain the difference between ring and balanced modulators. I understand that a ring modulator can also be a balanced modulator too but a balanced modulator cannot be a ring (...)
The following simple balanced modulator may help you to understand. We have a 10MHz carrier input on N1 of the transformer. We apply a modulation signal at the center-tap on the primary. In the first plot, we have a10kHz pure sine-wave modulation with the balancing pot P1 just of the 50% mark. You can see the carrier, and the two side-bands 10k
go to mini circuits, buy a $1 double balanced mixer with a DC coupled IF port, put a 100 ohm resistor in series with the IF port, and put +/- 1 volt on the IF port thru the resistor. You will get almost perfect 0/180 degree phase shift
O.K., MC1496 balanced modulator, originally Motorola/Onsemi made. A rather old component, still popular in the amateur radio scene I guess.
a balanced diode bridge can be used to modulate or demodulate AC. Your understanding is correct for demodulation.
If you are looking only to shift the frequency, any RF mixer would follow at its IF output the RF input level, if the mixer is not in compression (RF input level is below P1dB of the mixer). So, you can use any standard DBM (double-balanced mixer) which will preserve your modulation and levels.
Another attempt to explain the balanced modulator or ring modulator
There are some old mixers can be found on the market, some has outputs: IF1, IF2, inputs: LO, RF. Construction is basically microstrip with two pair-series diodes (4 diodes total). Is it possible to use IF outputs as inputs? For example, put some low-frequency AC waveform, provide some LO and use RF input as output?
Overall the the step-by-step explanation confuse me, an I do not have a general view what you inted to do. To make a DSB modulator you need at least two diodes mixer (single-balanced), otherwise cannot suppress the carrier. In the most of the mixer types, higher the LO level, higher the conversion gain is (or lower conversion loss for passive mixer
MC1496 is designed for carrier suppression (DSB double side band modulators) but in the same time can be used as product detector, or standard double balanced mixer. SA602 can be used as DSB modulator, but cannot provide the same carrier rejection as MC1496.
This circuit is a (balanced) modulator but not AM modulator. AM modulator is very similar but have 750 resistors around the 50k potentiometer. Check the MC1496 datasheet.
I know that balanced modulator removes the carrier frequency from the Amplitude modulated input signal. Here's the circuit that I saw but I couldn't understand its working. I know the working of ring modulator so you need not explain me
Any balanced mixer is in principle the "product" modulator, or, a multiplier. The important point is that one of the signals to be multiplied can fully open and close mixer diodes (called a local or pump signal). For diode mixers, the nominal LO level is +7...+13 dBm, or, around 10 mW. The other signal should be lower in magnitude than the first. A
Single balanced modulation allows full amplitude of carrier frequency through it, but not modulating signal. Double balanced modulator only allows the modulation components through (no Fm or Fc). Frank
All of these are suppressed carrier AM. There are several ways of removing the carrier but the most common is to use a balanced modulator or a double balanced modulator. These will produce two sidebands (DSB) but you can then fully remove one of then (SSB) or partially remove one (VSB) using filtering techniques. Brian.
Hi, I'm looking at the AD630 for a demodulation application @ ~1MHz carrier, 1kHz signal. However, its very expensive and pretty large: Does anyone know of any other similar synchronous demodulation chips which might be suitable, and can give a DC output?
Hello, I am trying to make a vacuum tube ssb modulator and I need to know if my consideration below is ok. LOSC: 454KHz AUDIO: 1KHz RF FILTER: 455KHz After the balanced modulator 3 frequencies occur: 454KHz (suppressed carrier), 453KHz (LSB) and 455KHz (USB). The 455KHZ filter keeps only the 455KHz USB one and rejects by an ammount (...)
By definition MC1496 is a balanced modulator and the main application is DSB modulation (Double Side Band – suppressed carrier). If is used as an AM modulator to don’t get carrier suppression (and getting instead, a DSB) you need a shift from suppressed carrier, which your circuit already have it (R5, R6, R10, R11, R9, R12). (...)
Hello Everyone! This is my first post so, first a quick intro: I am shoe, Im from edinburgh, 23 years old. So, I'm using a MC149CP balanced modulator chip to build myself a ring modulator on breadboard. Since I am an ultimate noobie and haven't done any electronics since technology in 4th year at school I'd appreciate the help with (...)
A balanced modulator or multiplier can be used to double the frequency. Another way is generate a lot of harmonics, and use resonant circuit (or filter) to obtain desired frequency which is integer multiple of the input. S. H.
hiya~ I hav a question on this topic regarding the balanced modulator in AM. If the output of the balanced modulator is fed to the input of the second balanced modulator and the carrier is fed to the carrier input of the second modulator, what will the output of the (...)
The two diode type is singly balanced and the four type is double balanced. This means that either one or both of the drive signals (such as audio and carrier) does not appear in the output at significant amplitudes. In the singly balanced design it is best to allow the baseband through and suppress the carrier due to the baseband (...)
hi it is stated here that in a QPSK system the highest fundamental frequency present at the data input to the I or the Q balanced modulator is equal to one-fourth of the input data rate how could this be true? although it is stated also that "the bit rate in either the I or the Q
Model from CM2000 is here: ******************* *MC1496 MCE 1-31-96 *balanced modulator/Demodulator *Nodes: GainAdj Vc Vc Vs Vs Vee Bias Out Out GainAdj *Motorola/MCE balanced modulator/Demod pkg:DIP14 pkg:SO-14 .SUBCKT XMC1496 3 11 10 9 8 7 6 4 5 2 Q1 3 6 14 QNPN Q2 15 9 3 QNPN Q3 4 11 15 QNPN Q4 5 (...)
Hi there, Currently, i have build the modulator and demodulator as shown in Fig.5 and Fig. 29. The frequency for modulating signal input = 1kHz Carrier frequency = 100kHz. (for both modulator and demodulator) The modulator output (either V+ or V-) is able to get the modulated AM output. (However, i (...)
Hi! Please help me with these questions: 1/With an AM DSB modulation system using balanced modulator,what is suppressed-carrier figure?And how to measure it? 2/With SSB demodulation system using Product Detector,if LO frequency increases,how is the output frequency at USB and at LSB? Thanks!
can anyone give me gilbertcell calculation spesified V(o) for bjt transistor and double balanced form with thanks
why it is called so...what are the componenets that get eliminated or balanced by means of it.....i found its presence in almost in modualtion sytems....what is its supermacy....
A DSB-SC sinal is: φ(t) = f(t) cos ω1t where ω1 is carrier. We want change the frequency of the carrier from ω1 to ω2 (which is known as frequency conversion). Show that the balanced modulator circuit of the picture is needed to do this conversion, injecting f(t).cos ( ω1t ) and A.cos ( ω2 ? ω1 )t a
"I and Q are used to modulate a 3.58MHz color subcarrier using two balanced modulator operating in phase quadrature : one modulator is driven by the subcarrier at sine phase ,the other modulator is driven by the subcarrier at cosine phase " My question is how to undertand "balaned modulatro operating in phase (...)