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31 Threads found on Clock Testbench Vhdl
You don't show your testbench. What's the relationship between readReq and the clock? Is it synchronous? If readReq is coincident with the clock edge, what do think will happen?
How about using a counter with a 10 Hz clock (1 ms period) or use whatever system clock you have, e.g. 100 MHz clock and create a counter that counts from 0-9,999,999-0 and increment a second counter when you reach 9,999,999 (or at 0,000,001 for a starting increment). Instead of giving the simulator lots of work to do
LIBRARY IEEE; USE ieee.std_logic_1164.all; --USE ieee.std_logic_arith.all; USE ieee.numeric_std.all; library ieee_proposed; use ieee_proposed.fixed_pkg.all; ENTITY dwt IS PORT ( clk : IN STD_LOGIC; vid_in: IN STD_LOGIC_VECTOR(7 DOWNTO 0); -- Pixels from main memory hor_sync: IN STD_LOGIC;
I am trying to write a code in vhdl with a given time period of clock in testbench .When i execute it i get proper output , but if i modify the code slightly i.e including more functions (more operations) then although am not changing anything in the test bench , but still i the clock in the test bench waveform appears to have g
What exactly is the problem? have you got a testbench to simulate the code? One point : the enable signal should be inside the clock. Your current code could be implemented as a gated clock enable, which is not a good idea in FPGA.
if you use d1 and d2 as variables instead of signals it will instead of signals, it will be on the same clock cycle.
Sounds like a "My first testbench - part 2" problem, because every testbench for sequential logic involves clock generation, and incrementing an integer or real signal together with clock generation would be the next step.
Hi friends I have the Test Enable signal(TE) 111680 which should be write in vhdl, clkperiod : integer := 4; -- system clock period signal clk : std_logic := '0'; signal te : std_logic := '0'; constant ct : integer := clkperiod/2; clk is already written Can I k
ISE is a synthesis tool and ignores any simulation timing statements. To generate timing in hardware, you need an input clock and sequential statements referring to it.
I am trying to convert this vhdl testbench code to verilog testbench, kindly help me to convert this part of code slave_clkedge <= '1' when SLAVE_CPHA = SLAVE_CPOL else '0'; -- Define a 3-bit counter to count SCK edges and data into register so that parallel -- register is loaded. Use same clock (...)
thank you for your comments, this is very helpful. about the process and asynchronous rst_n, my professor did mention that in hes comments. ill keep that in mind. the falling_edge is a mistake, i tried to change my testbench clock to be falling edge and accidentally changed all my clocks. now i know that i shouldn't put conditions with (...)
in simulation a code for QAM mapping used in OFDM .. the code is working great but i have a problem the output is shifted by one clock the output that should appear in clk 1 with input11 appears in clk 2 with input 2 and so on the code is this is not clearly my code :) library IEEE; use IEEE.STD_LOGIC_1164.all; use IEEE.STD_LOG
Hi, I saw your replies in the forum and felt encouraged to post this question. Thanks for providing your expertise. I have a vhdl test bench that is associated with both implementation and simulation (as I would like to run P&R simulation). I just want to define my clock with a certain time period. Say clock = '1', wait for (...)
1. Yes 2. Its a lot easier to do these checks inside your HDL testbench. For vhdl, the quickest and dirtiest way to stop a testbench is: assert (not end_of_sim) report "Simulation finished!" severity failure; Although the cleanest way is to stop all stimulus - ie. halt input processes and turn the clock off. 3. You cant (...)
Then in your testbench you need to create a clock and reset.
What is the clock rate?
Hi all, one of my vhdl modules produces "X" values even with the slowest clock; there were no problems with its behavioral simulation though. Here's the code; basically it's an adder (it sums its single data input A2 to a constant FO1 after reshaping A2 into the variable A1) whose output is forced to 0 if the result is negative ent
I guess, the problem is missing knowledge of the vhdl textio package. Generally ASCII formatted data files are a straightforward way to read in stimulation data. You'll read e.g. one line for each clock cycle in your testbench, and decode one or multiple values and assign it to the stimulus vector. The testbench scans (...)
If you are using normal clock frequencies it will take a very long time to simulate one second. Use a shorter time for simulation and debugging. When you have it working you can build it for 1 second and test it in a real FPGA.
Basic answer: dont create a clock in logic. Use clock enables instead.
the problem is that at that point, rw_in (which is a 1 clock delayed version of rw) is set to '0', so the data_lcd is not driven to 'Z'.
Dear All. Is there any idea to use both clock rising and falling edge when we run synthesis? I got an error message when I use both the rising and falling edge in synthesis. Please let me know if you have ideas or experiences. Thank you.
Hi, everyone! I'm a beginner at vhdl coding. Recently in a project, we need to transfer data between two clock domains. These two clocks probably at the same frequency but with asynchronous phase. So I use async FIFO. The attachments include the vhdl codes and the testbench (not perfect). I don't know if (...)
Hi, In C-based verification environment (Assume testbench, Testcases and all environment components like Monitor, Checker, Score-boards all are written in C, DUT is written either Verilog/vhdl) how to create clock Source? In such a verification environment is there any other difficulties to be faced? Please answer this question, since I'm (...)
Your stimulus are not exactly the same. When you simulate the stand alone component your stimulus which are probably synchronous with the clock are applied a little before the active edge of your clock (depending on your testbench setup). When you simulate the component in a system your "stimulus" to the component are generated by the (...)
Hi, Can anyone tell me how to write testbench for clock with offset. Here is my test bench process begin clk1 <= '1'; wait for 10ns; clk1 <= '0';wait for 10ns; end process; process begin clk2 <= '0';(other signal);wait for 5ns; clk2 <= '1';(others signal);wait for 10ns; clk2 <= '0';(others signal);wait for 10ns; ...u
Hi! When you have Sw1,Sw2 and Sw3 to 0, the led goes with the clock? Why you do not make a testbench and post its results? Regards,
Hi , I have a problem ... I must generate a time diagram to control a ADC... But it have a difficult time diagram, can somebody help me to understand, what's the best metod in vhdl to create a time diagram (NO testbench)... How can I start from a clock and generate a time diagram with fix delay ? thanks
In the testbench the frequency is not the problem. In one data pipeline the clock frequency have to be a single one. When 2 pipelines with different frequencies are connected together 2 situations occur. When one frequency is equal to multiplied second frequency, or the frequencies have small common divident then both pipelines must have a
Salam Johnson, I'm a beginner too. For example i use Spartan-3 XC3S200, it contains 4 DCMs (Digital clock Manager) Can you explain how to generate the clock using DCM? My main clock source is 50Mhz (attached at T9 pin) Thanks
you should use the counter to deviding your clock core. The devided clock will be used to enable the latch of your signal