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109 Threads found on edaboard.com: Clock Testbench
You don't show your testbench. What's the relationship between readReq and the clock? Is it synchronous? If readReq is coincident with the clock edge, what do think will happen?
I think you are seeing clock and data switching at the same time, causing hold violations Yeah, you have nothing in the testbench that would emulate the delays that occur on the ASIC inputs/outputs to match what was used for constraining the design. So I can easily believe you would have problems simulating the
Shift before? The statement is of course delaying the input data by a half clock cycle, related to a sampling clock working on rising_edge.
How about using a counter with a 10 Hz clock (1 ms period) or use whatever system clock you have, e.g. 100 MHz clock and create a counter that counts from 0-9,999,999-0 and increment a second counter when you reach 9,999,999 (or at 0,000,001 for a starting increment). Instead of giving the simulator lots of work to do
I see at least two problems, each of it might cause failure in gate level simulation. - zero duration of reset pulse - 500 MHz clock is probably too fast for the simulated hardware
Write a very simple C code that will write data to the DDR3 module (assuming that it is connected via an AXI interface). You will need SDK and eventually there will be an ELF file generated for the uBlaze. You need to associate this ELF with the uBlaze. For the test-bench you just need to provide clock and reset signals to the top-module. The abov
LIBRARY IEEE; USE ieee.std_logic_1164.all; --USE ieee.std_logic_arith.all; USE ieee.numeric_std.all; library ieee_proposed; use ieee_proposed.fixed_pkg.all; ENTITY dwt IS PORT ( clk : IN STD_LOGIC; vid_in: IN STD_LOGIC_VECTOR(7 DOWNTO 0); -- Pixels from main memory hor_sync: IN STD_LOGIC;
Add initial values of '0' to your clock and enable signal in your testbench.
I am trying to write a code in vhdl with a given time period of clock in testbench .When i execute it i get proper output , but if i modify the code slightly i.e including more functions (more operations) then although am not changing anything in the test bench , but still i the clock in the test bench waveform appears to have got spreaded (...)
Hi, I have a vector and a matrix of hexadecimal values stored in .mem files. I need to subtract this vector from each row of a matrix in each clock cycle. I have read my files to my testbench file using $readmemh in verilog. How can I subtract them now? I have used xilinx ip floating ip core for subtraction as well. Here is my code but this c
Why my clock is not toggling in the driver class ? thanks in advance // Code your testbench here // or browse Example parameter data_width =8; parameter addr_width =32; parameter seq =2'b00; parameter non_seq =2'b01; parameter hsize =4; interface ahb_inter(); bit hclk=0; bit hreset; bit htrans; modpor
Dear all, I'm trying to excercise with some systemverilog example on of swith example. But I'm confused in here. output_interface output_intf(clock); testcase TC(mem_intf, input_intf, output_intf); program testcase (..., output_interface.OP output_intf); Versus output_interf
What exactly is the problem? have you got a testbench to simulate the code? One point : the enable signal should be inside the clock. Your current code could be implemented as a gated clock enable, which is not a good idea in FPGA.
Just wondering if using always @(posedge clk) and nonblocking assignment for stimuli is at risk of any racing? dut sensitive on the same clock edge, tb:always block is the same as any part of synchronous design. An example from Doulos shows using clock block with specified skew.
if you use d1 and d2 as variables instead of signals it will instead of signals, it will be on the same clock cycle.
However, I noticed that in the testbench of traffic gen (the example provided by Xilinx), the app_rdy is not exactly synchronized with the clock. There's a noticeable delay in the app_rdy signal. This is also what's keep given me problems, at the end I came out with a hack to deal with this problem. Do you happend to have any
100 ps clock period? I'd like to know how the OP expects this design to run at 10GHz in an FPGA.
You dont generate the clock in your testbench
Hi. As I know, the clock skew is that clock signal arrives at different flip-flop at different time. Also When I synthesis, I use ideal clock not real clock to synthesis. The when do I use real clock to synthesis? Is this same thing clock skew and clock uncertainty?. (...)
I don't get why you generate your clocks with this code. It's a lot simpler to use a clock module that generates the clock. Then it represents a clock oscillator on a board (the testbench). I use a generic clock generator module that accepts parameters for either period/frequency, (...)