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verilog concatenation
53 Threads found on Concatenation
Hi, I have: localparam mem_x_size = 240; localparam mem_y_size = 128; reg Y_waveform; reg rx_ds1a_reg=10'b0; reg x_index= 9'b0; reg y_index=8'b0; and I want to cancatenate always(@clk) begin rx_ds1a_reg <= {Y_waveform, 9'b100000000}
There is still an error, because m never gets reset back to 0. because when m is 63 it means that we write the whole matrix in ram and we want stop writting in RAM. Why not just have a single addr counter that increaments from 0 to 4095? as i said before i write one image 64*64 in ram,i wanted to extend each pixel o
Dear all I've been playing around with simulated equivalent input current noise in LTSpice and I found out that, in the same way it works when you have two DC current sources in series, the maximum current noise you get is the one set by the lowest contributor. For example: In a simple circuit based on a DC current source attached to a 10K
You can't do this as an array assignment pattern because assignment patterns expect the groupings of {}'s to match that array dimension. i.e. either a single replication of 29 elements, or a comma separated list of 29 elements. And you can't do this as an unpacked array concatenation, because it does not allow replication. But you can get around
HELLO ALL, I've been able to mitigate an error I received when assigning an inout port. I would like to know "WHY" my new code works, and why the old code is at fault. The concatenation that you're doing on the port map for 'D' in 'Old Code' cannot be applied to an inout pin because when 'D' is driving the o
In VHDL 2008, this rule is relaxed, so concatenations are allowed.
concatenation is just bundling of signals (hence think wires) and should not increase or decrease the amount of logic required by the rest of the circuit.
The purpose of c_dummy is mysterious as well as the mising assignment to the entity output signal. Why not simply write decompress_full of the concatenation's left-hand-side? The code has however other issues that aren't related to concatenations. You have e.g. a "multiple driver error" for output signals a and b, because they are assigned i
Verilog has a concatenation operation. assign abc = {a,b,c};
wire sigZ_wire; assign sigZ_wire = sig1; assign sigZ_wire = sig2; assign sigZ_wire = sig3; assign sigZ_wire = sig4; module_A module_A ( .... .sigZ (sigZ_wire), .... ); If you are not using the concatenation operator, then it will be somewhat like this.
You might be better off with a veriloga source that reads tabular data (or has it embedded in the code). I've built these using a concatenation of header, "core" and tail using shell scripts to massage plain text, time voltage pairs at one per line, to make very long "digital" vectors. Since the header and tail don't change the veriloga "source" c
Hi, this is range definition. Previously defined parameter NUM_CLK_DOMAIN equals to width of VALID_CLK_DOMAIN parameter. If range is not defined, it would be 32 bits. {NUM_CLK_DOMAIN{1'b1}} here replication of concatenation is used. Let's say NUM_CLK_DOMAIN is 8, then VALID_CLK_DOMAIN parameter will be 8 bits wide, and will g
hai, Your assumption is correct. Here, UxBRG is equivalent to U2BRG. ## is the token pasting or token concatenation operator. When the macro is expanded, the tokens on the sides of the operator combines together to form a single token Regards
You'll want to review concatenation and replication statement syntax. As far as I'm aware of, there's no similar repeat (replication) operator in VHDL, so you'll write b1 <= error(8) & error(8) & error(8) & error;
You need to import std_logic_1164 to make it work. The concatenation is effectively changing the input numbers to unsigned, it this what you want? For regular signed addition, you'll use resize() instead. It's sufficient to resize one operand, the other will be resized automatically.
Hi, Define your input and output seperately, thenn define a new variable using inputs by concatenation (the operator &) here is one
was concatenation in verilog synthesis or not synthisis and if it is not how can i replace it? thank you - - - Updated - - - another question was function synthesis ? if yes why i cant see what inside it as number of regs,ram,rom ....etc
hello all, i am a new vhdl user please help me find a link on how to concatenate two different files in vhdl into one new file thank you.
I presume you don't expect anybody to explain the meaning of this arbitrary code snippet. '0' & cycle_wait(cycle_wait'high downto 1) is a concatenation operation, a usual way to combine bits and bit vector selections to a new bit vector. In this case it's setting the leftmost bit to zero and copying all except the rightmost bit of cyccle_wai
Your commented out line is what you would use if pixel1_pipe were standard vector, but you made it a two dimensional array. IIRC the concatenation operator can not be used with arrays. Assign is only used for wires. SystemVerilog does away with the concept of reg and wire. r.b.