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# Exponential Distribution

10 Threads found on edaboard.com: Exponential Distribution

Rayleigh channels are almost worst case scenario. In Nakagami-m channel modeling the worst channel has a parameter m = 0.5, while Rayleigh has a parameter m = 1. Also, Rayleigh channel is mathematically more convenient; the SNR distribution is exponential.

## What's name of this distribution?

Hi, if we create a sequence and call these w1...wN with exponential distribution with parameter lambda then we create: 118444 what's name of this distribution? Thanks

## random generator with exponential distribution with verilog

Hi all, I want to generate random signal with exponential distribution (exp(T/tau) tau is my constant) in verilog. Could you please advice me how I should do it? Sincerely, Albert

## Decode and Forward or Amplify and Forward Matlab code

Basically, if the underlying fading channels are Rayleigh, then SNR follows exponential distribution. That is y0, y1, and y2 are all exponentials, where y0, y1, and y2 are the instantaneous SNR of the direct path, the first hop of the relay path, and the second hop of the relay path, respectively. After generating them, calculate the (...)

## MATLAB exprnd function

Here is the source file of exprnd function function r = exprnd(mu,varargin) %EXPRND Random arrays from exponential distribution. % R = EXPRND(MU) returns an array of random numbers chosen from the % exponential distribution with mean parameter MU. The size of R is % the size of MU. % % R = (...)

## kindly explain this solution to me

IF X and Y are statistically independent (or orthogonal) then the RMS of the combined signal (sum) will be sqrt(X^2 + Y^2) and the distribution will be exponential

## Are there any advantages in doing OFDM in a flat fading Rayleigh environment?

Hi all! I would like to ask if there's any advantage in doing OFDM in a flat fading Rayleigh environment? Also can anyone tell me if there would be any difference in the BERvsSNR results , when we simulate a flat Rayleigh channel and a frequency selctive exponential channel, where each tap follows Rayleigh distribution... Any answer will be he

## CDF of two exponential random variables

I want to find out the cdf Fx(x)=Pr(X ≤ k) where "X" is a Rayleigh distribution and "k" is some other Rayleigh distribution with may be different mean and variance. How can I find it out, somebody help me please.