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6 Threads found on edaboard.com: Fast Integrator
you do not show whole circuit so it is difficult to help you. But your connection to comp pin is wrong, it should be as an integrator, you are just using the internal error amp as an amplifier.... Also, your vin is a pulsed voltage? Also, you use 1n4007 in RCD clamp, this not good, you must use ultra fast diode there. Do you know uc3844 is 50%
10 pF Cap will integrate and saturate in microseconds. Remember dv/dt=I/C so with C=1e-11 the slewrate is far too fast. Try 1 nF. or calculate what you need.
I think the most important spec for your opamp and comparator will be offset voltage. There's not really a 'gain' for the integrator, there's a volts/sec constant, and that's going to depend on your requirements. How fast do you need to do the conversion? How fast is your clock? It's going to take 2*2^14 (32786) clock cycles to do a conversion.
upper circuit (opa1) is an integrator. That means that output voltage changes over time. How fast it change depends of voltage input, and it is inverted. The lower circuit (opa2) is an schmitt-trigger. This o
joker12, I believe the problem is that the LM124 is not nearly fast enough to respond to such a fast pulse. Your input current pulse is 10^-2 Amperes. This current must be matched by the current through the feedback (integrating) capacitor. The current through the capcitor is i = C dv/dt. Or dv/dt = 10^-2/10^-12 = 10^10 volts/second. I dont be
You have a differential integrator. For a perfect differential input signal (where V+ is exactly equal and fazed to V-) C has nonsense. But if V+ and V- (input signals) are fast pulses slighty unfazed (imagine spikes for example) C is acting as an input filter. Without C, the output integrated voltage will swing inequal for Vout+ and Vout- The