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The peak gain is the point in 3D space where the antenna gain has maximum value, while the average gain is averaging all the points in that 3D space.
difference between input and output is 7 volt maximum. but I need to sense the voltage in the range of 1 Volt. Don't understand this statement. How do you observe it? AMC1100 is specified with maximum gain error of +/- 0.5% at 25 °C. Means the measurement must be adjusted if you need higher accuracy. I suggest a different circ
In your block diagram, use have used the classical symbol for an opamp (voltage-in and voltage-out). Hence, in my previous answer I have assumed that you are using such an amplifier (off-the shelf). However, in case you are designing another amplifier by yourself (which - as it seems - has no low-resistive voltage output) you cannot use the gain ex
Hi, Currently I am analyzing Tx part and given one Driver amp. and one two stage or three stage Power amp. Can some one help to understand what is the difference to using of two stage or three stage PA except gain if it is possible to get power with 2 stage. And for example given OP1dB =33 dBm and what will be Pavg in this case?
The opamp has an extremely high gain but the negative feedback reduces the circuit gain to a useable amount. Therefore the difference voltage between the inputs is extremely low. Use Ohm's Law to calculate the output voltage since an opamp has an extremely low input current: 1) Input resistor to inverting opamp= 10k, feedback resistor= (...)
The main difference is the antenna pattern. Patch antenna pattern looks like this: and inverted-F antenna pattern looks like this:
In a mixer usually the RF input port and IF output port, are on different frequencies, so you cannot use S21. But you can use a specific RF input level (in dBm) and measure the output power (in dBm) at the IF port. The difference in dB between RF input and IF output powers would be the mixer gain (or loss if is passive). In this way you can see al
Hi What is difference between radiation gain and antenna gain? Thanks alot
... You have also unbalanced output stage and first stage which can produce additional offset. I think this shouldn't matter at gain=1 feedback (and no gate input current, of course).
Hi, My circuit has a gain phase detector that generates two output voltages, VMAG and VPHS which is related to the magnitude ratio and phase difference of the input signals (VA1 and VA2 ) by the transfer function: 126313 The magnitude ratio, |Z| and phase difference, _
Hi, For a planar structure, the MoM (ADS momentum) method is a good one. You gain in time because the matrix to solve is reduce. With FEM, you solve the problem in three dimensions the matrix is more complex. For 3D structure FEM is preferable. I already designed some filters with ADS momentum and the simulation was quite good and fast. Good work
when i entered AC 2 or AC 3 the shown gain and ugb is doubled and tripled , how ? You are confusing output voltage with gain. gain is Vout/Vin, so if Vin is unequal 1V, you need to calculate a ratio.
Between source and gate you don't have a phase reversal. So I think you shouldn't reverse the phase at the output of the gain-boosting opamp.
Hello, I have two antenna and i would like to visualize the gain of this antenna, so i m find that in HFSS, it have two curves: the gain phi and gain theta in hfss, Can someone explain me the difference betwenn the two angles Thanks in advance
please explain more on what software you using to simulate and what difference in results you seen. is it S-parameter difference or gain and efficiency difference?
For a good understanding of the feedback principle it is necessary, I think, to realize that the voltages at both inputs are NOT equal (due to negative feedback). This is because the opamp always needs an input voltage difference to produce an output voltage. However, due to the large open-loop gain Aol of the opamp this differential input vol
Hi all, Can anyone suggest what will be the conversion gain of a N-path mixer (say, 4-path) as compared to the conversion gain of a single-path current driven mixer? What will be difference in the two conversion gains? Thanks in advance. Indrajit
Yes, that means the op amp will be unstable if used as a +1 follower. A minimum closed-loop gain of +2 for a non-inverting amp or a gain of -1 for an inverting amp is the same from a loop-gain point of view since in each case you have two equal value resistors going to the op amp (-) input. The only difference between the (...)
Hi, IIP3 and OIP3 are different where the first one refers to the "input 3rd order intercept point" and the latter one refers to the "output 3rd order intercept point". Relationship between them is as you noted (OIP3 = IIP3 + gain (in dB)), however I think IPIP3 is just another notation for IIP3. They should refer to the same phenomenon.
This is a well known difference between similar instruments from various manufacturers. R&S consider a negative value for external gain, and positive value for an external attenuation. The similar Agilent/Keysight test instruments consider in the other way, negative value for loss and positive for external gain, which makes more sense for me.
but value of e^1=2.71 and is that gain is acceptable.You are simply misunderstanding the scientific number format. e+001 means 10^1, take at look at the Windows calculator display or a spread sheet calculator.
The vertical difference in Rx EVM differs by as much as 4dB for the two gain settings over the entire range of Pin. This occurs around -70dB in. A rise in Error Vector Magnitude at low signal levels means a loss in sensitivity.
Normally all values are equal for a unity gain differential amp ( 10K) to minimize offset from input bias current. inverting gain= -R7/R8 *7V = (-1) * 7V Non Inv gain = 1+ |inverting gain| * V+in= (1+1) * 5V*R5/(R5+R6)= (1+1) 5v * 1/2= 5v Using superposition rules the output-7+5 =2 the difference. As a (...)
Hi guys, Can anyone explain to me what is the difference between this two transconductance formula? gm =UnCox + (Vdd/2 -Vtn) gm =2pi x gain-bandwidth x Cc
I would think that "device variability" is the difference of one transistor part number (no variation of the process) producing some transistors with a high current gain and others with a low current gain. Process variation would be making a transistor part number with a process that creates high frequency but low current transistors and (...)
same gain, difference is input impedance and output drive current Iout for rail-rail OP Amps is small ( due to high RdsON of internal CMOS output stage) so 10k may not reach 100% both rails if reference is Vbat/2, so >> 10k feedback R is preferred for low Iout. But if R values are too high, then input bias current offset may cause a Vin of
Opamp: One differential input pair, one single ended output, very high open loop gain (practically infinite at DC) Differential amps: In a technical sense, Opamps are differential amplifiers. But when an amplifier is referred to as "differential" it's usually referring to differential outputs, which typical opamps don't have. Sometimes these have
I suggest you get some gain before the probes, like a fast enough instrumentation amplifier (if there is one that you deem fast enough). Since you are limited in full scale resolution, get to full scale early.
Hi, I am using Analog Devices's ADL5380 Demodulator for my down-convert mixer. In the datasheet, it promised a conversion gain of 5.8dB gain at 5.8GHz. However, I tried for many times but I got a conversion loss of 9dB. Is there anyone has the same problem? Can I have some idea for this?
It is the same , that is until the gain * f product (GBW) is reached. If OA has GBW of 1MHz then gain of 10 is 100kHZ BW. If usingg +/-10V supply (and has Rail to Rail saturating outputs) , then with a gain of 10, then the max. linear input range is <1V input MAX for either AC or DC or AC+DC
It is obvious that the gain is 1 like a piece of wire.
INA118 isn't particularly suited for this application because it has a minimal gain of 1. Use a different instrumentation amplifier or a differential voltage divider in front of INA118.
The cascoding is for PSRR particularly, although the higher gain (from higher Rout) may make a small difference in the setpoint voltage and tempco (not much, since Rout is dominated by the diodes' operating point conductance). Cascoding kills the lambda current-match errors you'd get in a simple mirror.
I'm not sure if this source follower architecture works well in a 180nm process - this depends very much on the Vsupply/Vth0 ratio and Vth0_n/Vth0_p symmetry. Instead of the simple source follower I'd prefer a real gain stage with appropriate resistive current feedBack, something like this: 114877 For simulation I've used 180nm
I simply noticed that with 1V in the output is about 2.2V. For 2V in the output is about 4.4V. For 3V in the output is about 6.6V. Then simple arithmetic calculates the gain to be about 2.2 times.
How do you measure gain in volts? Bias point and DC analysis are essentially the same, results are node voltages and current rather than gain values.
I=CdV/dt, no way around it. The "I" of interest being your output stage maximum current-throw, if C is the external load. That input difference matters so much, indicates a gain shortfall. Back end current must not be fully steered by 250mV simulus' applied input difference. Although there could be input/feedback network related problems (...)
making slots in the patch can have many many purpose. slots can be used be for getting Notch band, slots can be used for getting High gain and slots can be used for getting High Bandwidth also. Different alphabetical shapes of slots can give you different enhancement in parameters. I dont think there is any such formula to calculate the length and
I explained already.. take the difference between the detected level and desired level and control the gain by hunting or integrating towards target until there is zero error difference. Do you need to refresh your memory on integrators? With a fixed offset there will be a ramp out to control until offset is null, then the
Show what you have , schematic, parts, layout, signals, pulse bandwidth. Do U mean crossover distortion range, common mode input range (which you say is Rail-Rail input) or differential input range, which is dependant on gain and output signal?
I always use a vcvs to take the input difference voltage and create a single ended ground referred value. Also use that voltage in my own gain/phase plots, having found the iprobe / stb to be unreliable (not often, but often enough to ruin a MC run consistently, no idea why and no way to tell whether - except when you get whacked outliers).
difference between electrons and holes mobility causes different current gain factor in pmos and nmos so to obtain the same rise/fall time in cmos inverter the W/L ration of pmos should be ~3 times higher.
Do you have no idea how to start? Do you know the meaning of all terms? What is R (FET circuit)? Do you know the meaning of 0.6V (BJT circuit) and the difference between beta and "current gain"?
Hello, I'm a fresher about analog and RF design, i want to design a VGA, the noise figure below 10dB, and the bandwidth is 40MHz~90MHz, the gain range is 32dB(-32dB to 0dB or 32dB to 0dB, is there any difference) with the gain step is about 0.5dB, and also with good linearity. which structure of the VGA can be used to reach the spec, how can (...)
kf is a constant and is expressed in Hz/V (or rad/V in case of phase modulation, kp). It is very similar with the VCO gain which also is expressed in Hz/V, with the difference that kf is the instantaneous value of the frequency that is linearly modulated by the voice or by the baseband signal. To find its value have to know the frequency deviation
You say "offset can be ignored". What led you to that conclusion? What opamp are you using? If you are using something like, say, an LM324, that has an offset of several millivolts (maybe 9), which will give you an output of several VOLTS. Don't forget that your offset is being multiplied by your gain, just like your signal.
Hi Can anyone please tell me if there is a difference between DC small signal gain and AC small signal gain ? Thank you
no that is not true, i have one example of cb amplifier, where Input voltage is 0.5mV and utput voltage is 50mV That is a voltage gain of 100. Its current gain is 1. Don't you know what the difference is between voltage and current?
How to check the theoretical value and practical value for gain in cs stage ? theoretical value ----> As per our calculation from formula practical value ---->As per our simulation from the tools Is there any impact occur for these two values?
i would like to construct collinear antenna with phasing coils then stacking for higher gain I've searched on many website but i don't find the formula for designing . anybody can guide me about these formulas , i am very new for antenna and I have some questions. 1st : What is difference between 1/2 lambda and 5/8 lambda of monopole ? Jus