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116 Threads found on Low Power Opamp
hi, 1-why ADC op-amp use -5v 0v +5v supply power why not use single supply?? 2-the -5v 0v +5v connected to low voltage 3v ADC that's mean more op-amp gain can damage the high cost ADC ? The fact that it takes 5V in doesn't mean it can put 5V out unless it's rail-to-rail out. Similarly if its not rail-to-rail in th
I think that the crossover distortion in the LM324 will cause the signal level to abruptly jump up or down a little when the DC control passes through the crossover voltage. I think the LM324 "low power" opamp is the only opamp ever made that has crossover distortion, so why use it? There are many other cheap (...)
the amplifier is protected against ESD strikes up to 3kV on all pins by a pair of protection diodes on each pin that are connected to the power supplies as shown in Figure 1. This would imply low ESR and higher current rating. power dissipation is negligble. So you are OK.
Most single power supply opamp circuits DO NOT NEED a precision complicated circuit for a low resistance high current "virtual ground". Instead they use two resistors and a capacitor to make a "half the supply voltage" reference voltage for the opamp's high resistance very low current (+) input voltage (...)
The power darlington transistors need heatsinks. If the output voltage swing is as high as 8V RMS then the output power is 8W into 8 ohms and each darlington heats with almost 2W. The 741 opamp was designed 48 years ago! It is noisy and its slew rate cuts its high level frequencies above only 9kHz. A modern low noise audio (...)
Greetings to everyone. I am currently designing a folded cascode amplifier, but my concern is if it would be suitable for ultra low power application? like more or less, 50uW without sacrificing it's speed? Here is my reference for this design. I like this paper since the hand calculations are provided but it's not complete. www
One can use an opamp to amplify circuit as well as a BJT or FET. They all have difference frequency responses, voltage range, power limit and requirements and circuit complexity. Anyway, for making an audio amplifier should one merely use discrete transistors perhaps a voltage follower (common collector) for current gain preceded by a common (...)
127111 This circuit realize the output current: IR=Vs/R, but it needs two opamps to achieve. In my design, I can't use opamp, anyone has idea to get IR=(Vref-Vin)/R=Vs/R? Thanks
You can use bulk modulation applying voltage between source and bulk and trying to control it There are many papers about bulk modulation and designing low power opamp using these techniques.
1/RoCo is not the op amp bandwidth unless the load is dominant. Not a good way to bet. Often the BW is set by internal compensation in unity-gain stable or "gain of X stable" op amps. Because voltage mode op amps want high stage gain and low power, Ro is made high and current made low (Ro is maximized at low current, (...)
Hi, So does the amplifier not output millivolts but anything within its supply rail and specs range (e.g. ~0 - ~4.7V for rail-to-rail) to balance the inputs, if you say it's a high gain amplifier? This is what I'm annoyed (at self) about: from the simplified schematics I've seen it looks like a difference amplifier that is a voltage follower, so
Suppose if I have a Vdd of 1.4V and I want to generate 1.2V and 1V constant voltages irrespective of the load from it, is there any possible way of achieving this? Well I tried doing this by using current mirrors, but I couldnt achieve constant voltages from it because the load was changing. Is there any other method or solution for this? [COLO
You gave us NO DESCRIPTION of your 'scope photo and what are the problems you have. Your 'scope shows four traces: Channel 1 (yellow) is a high frequency waveform. We do not know if it is an input or an output. Channel 2 (blue) is a low frequency distorted sinewave. We do not know if it is an input or an output. Channel 3 is not listed but m
Do you know how to build a low power linear voltage to current converter? The voltage to current conversion needs to to very high precision, like 10bit resolution. This opamp based V/I is good, but the opamp will consume large power consumption. Since I need a fast response Voltage to Current, the (...)
You need to create a ground in between the 12V supply leads. The simplest method is a 2-resistor divider, or a resistor and zener diode. This is wasteful of power, however. If power needs are low then you may not mind. Also take a look at the list of related threads at the bottom of this column.
Hi all, i am trying to measure AC mains using the DL-PT202D, witch doesn't have a useful datasheet. From the figures with op-amp below i can understand that that is a current to voltage converter. Using lm741 op-amp i can't make it work.. on the output of the op-amp i am taking only noise.. Has someone used it to drive me..? the topology with the
I want to amplify a signal which lies in the frequency range between 0 -5 Hz. And I want a non inverting output with a gain of 33. So basically to amplify this signal , I am using a non inverting amplifier as shown in fig below : 116933 The opamp I am using is MCP6002. But using above configuration, I am not getting
This question is about op-amps and may look strange at first. Basically my question is that since, operational amplifier is a device which has 2 inputs and one output. One of the two inputs is inverting while the other is non-inverting. The output is equal to the difference between the inputs multiply by open loop gain that may be like a million.
What does a low power application exactly mean?does it mean that current is low or is it voltage?am a newbie..please help me:smile:
The integrator method will produce a triangular waveform, not a sawtooth...which one do you really need? The easiest way to produce a sawtooth is with an UJT (unijunction transistor) oscillator, which consists of exactly three components: the UJT itself, a resistor and a capacitor. The circuit can be further enhanced with another resistor on base