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21 Threads found on Miller Zero
While driver designs try to minimize crossover / shoot-through current, these are never zero and there's a component from the predriver chain that just won't go away. So expect some internal CVf current (which ought to be rated, you'd think). Your MOSFET / IGBT Qgg should contain some miller term which varies with working voltage. This may differ
hi,everyone! I recently learnt root locus method, but there was a problem when I applied this method to analysis the basic two stage miller compensation amplifier without zero nulling. I used two port method neglecting the compensation capacitor feedforward signal to calculate the loop gain transfer function 2. There were two LHP poles and one z
I've an opamp where the first stage is a folded-cascode and second stage is class-A stage. It is miller compensated with the feedback path of the cap connected at the cascode of the first stage instead of the output of the first stage to avoid the RHP zero. The open loop phase margin is some 60 degrees but when connected in unity-gain buffer mode,
Do you mean swapping the Rc and Cc - Cc first and Rc second (from left to right) in the series combination? If so, it shouldn't have any effect on the miller effect. When we see the miller effect usually the impedance of the Cc is higher than the Rc. At the frequency of the zero Rc~Zc. In integrated amplifiers if Rc is implemented with a mos (...)
Hi everyone I got some interesting question for you all. In the OPAMP Open Loop Gain Frequency Response graph, Pole & zero are decided by the compensation (miller) capacitor and resistor inside. I would appreciate if some someone explains how the slope of this gain plot is decided. This slope is always at -20dB/dec Which device make
Hi, I am running a pole zero analysis via cadence spectre on a two stage opamp which consists of the classical diff pair with current mirror load and as second stage the classical common source/inverter problem is that i cannot see the RHP zero that is created via the feedforward path of the miller compensation capacitor...All t
why not calculate the pole of output in two step amp use miller effect. They get it for the dominant pole from miller effect.But for the output pole ,they just set it short and get the result. Why can't using miller . It seems cannot get the same results
Hi, I have a question about miller compensation. I design a amplifier with first stage differential input, differential output, second stage differential input, single output. I put a miller cap between second stage output and one first stage output. From the AC simulation, I find a strange zero in the loop whose frequency is less (...)
my question is that how rigth half and left half zero is produced like in two stage amp signal goes to output from two path one from miller cal and one from mosfet then at some frequency these signal cut to each other hence a right half zero is produced. now my question ? why this zero is on right half plane why not in (...)
what is the effect of miller capacitance on stability? if the miller effect dominates, does it mean that the positive zero is at very high frequency?
structure is built follow the Rincon-Mora Enhanced miller Compensation method In his paper, the structure can pull two poles as far as possible
Just add a miller cap as in a two stage opamp, this will introduce a zero since you now create another path for the signal to reach the output.Then try moving this zero to the right half if needed to improve your phase margin. amarnath
what is miller, lead and Lag compensation ? Thanks
I'd say that the poles can be divided into two groups: -Poles in the opamp: miller pole and mirror pole (that should be the non-dominant one) -poles of the LDO: there are those cause by the opamp, the loading of the pass device on the opamp will create another pole, and output capacitance (C0) will add another pole as well.
A very interesting problem, for compensation of a 2-stage opamp, we normlly use miller capacitor to do pole splitting, and a nulling resistor is ususlly used to cancel the RHP zero, and sometimes even to cancel the non-dominant pole. How large the resistor should be ? The book by Johns Martin mentioned that, normally it can be selected such that t
1) RHzero is appear when miller compensation technique is used. For example, we have 2 stage amp with 2th inverting CS stage with miller capacitor, capacitor provide direct path for high frequencies which have opposite phase relative to SC output. That affect on phase margin and can be a badnwidth limiting factor especially for MOS circuit (...)
can you upload IEEE paper robust frequency compensation scheme for LDO regulators or A capacitor-free cmos low-dropout regulator with damping-factor .. or Single miller Capacitor Frequency Compensation Technique for Low ... by the way , you make LDO by BJT or CMOS process Added after 2 minutes:
I see in many 1980s and 1990s 's op-amps used nested miller compensation . A capicitance is connected between the one output of input differential stage and the output of the opamp , and one other capicitanc is connected between the output of the one output of the second stage . What confused me is there always another capicitance w
In the differential pair in the picture, the second pole is equal to gm3/Cx where Cx is the total capacitance in node X to ground. It is approximated to be Cgs3+Cgs4. Why do we not consider Cgd4? For small lengths, wont the miller effect from the gate to drain of M4 cause this capacitance to be on the order of the gate-source capacitances?
Do you use the R&C miller way to compensation your opamp? If you use only C- miller way, i think a Resistor has to be add to cancell or shift the location of zero which lies on the right half plane. If you use them like above, i think you have to regulate the value of resistor and capacitor to get a match to shift the loaction of (...)
There is a classical op with miller compensate, but because the load capacitor is very large (15p), so I think it is not suitable to compenate the second stage, I connect the Cc to output node. So there is a problem that a right half-plane zero comes out, why, I only can find a left half-plane zero generated by the compensate R, and how to (...)