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166 Threads found on Peak Rms
You apparently selected wire gauge for the primary winding based on peak current. That's completely wrong. rms current is the quantity defining the required gauge. It's also not appropriate to calculate wire gauge independent of the core size. You better use a transformer calculator tool, e.g. MDT from EPCOS/TDK, or the values from a trustworthy re
I see nothing wrong with that. The red probe is across the battery so it shows +12V with some ripple due to its ESR. The blue probe shows 10V rms sitting on a +12V platform so I would expect it to peak at around (10 * 1.414) + 12V and dip to 12 - (10 * 1.414) which is exactly what it shows. Brian.
First of all, you're more interested in the average/rms power required by the system, whereas those numbers are likely peak power. There is no way a car system is actually putting out kW of power rms, that much sound would make it a crowd suppression device. Even 500Wrms is very loud for a car system, so you should be fine (...)
Hi friends , I have 100 mV to 3 V Ac signal with 700 Hz frq and i should to measure the rms value with Mirocontroller (Avr -BasCom) then i use this circuit but that is very big error that you can see in attached picture , please help me for find best method to convert peak Voltage to Dc value . Thanks 133425 [ATTAC
Does your current probe measure peak value or rms, or trying to calculate that?
Hi, I'd like to better understand CST default power for WG and for SAR calculation. I've used the default power (peak power 1W, or 0.5 rms), but I got half values compared to a simulation (1W) done with SemCAD. Any suggestions? Many Thanks1
As the unit kVA (in contrast to kW) suggests, transformers have to be dimensioned for apparent power Irms*Vrms. Similarly inductors are designed for Irms (and additionally peak current if there's a risk of core saturation).
It says 140 V peak to peak, this is 50V rms. maximum rating? Frank
For designing and measuring an audio amplifier I use a sinewave to measure its output power at clipping and its distortion. A sinewave has a defined peak to rms relationship (peak V= 1.414 times rms V) and has no harmonics. SPWM has switching artifacts that must be filtered out with a very good filter or the PWM switching (...)
if you have two different signals, the rms power is the addition of them. As their voltage peaks can add or subtract , the peak power can be up to 4 times the addition of the rms power. If you have two signals of the same frequency , but different phases, you have one frequency who's amplitude is the vector sum of each (...)
We wish to heatsink our SMT inductor pads by thermal via?ing them down to bottom-of-PCB layer copper, and then using thermal transfer stickers (or some such thermal conductove transfer medium) to transfer the heat to an under-PCB heatsink. Therefore, we need SMT inductors with large pads. The inductor is 1uH and i(peak) = 20.5A and I(rms) = 17.3A.
I decided to try out this amplifier chip, I want to try the basic schematic, I want to use it to play 3 speakers 2 8 inches and a 10inch speaker and a tweeter. should I modify anything in this circuit for it to play good. all speakers are in one box I am doing this test because I want to see if its good enough to use as a guitar amps because (...)
I looked for a Skytec Speaker Manufacturer but instead of finding one I found millions of ebay ads selling cheap Chinese junk with the name Skytec on them. I found a datasheet for a 6.5" Skytec woofer rated at 125W rms but it had no details. An amplifier with a 48V power supply probably has an output of 45V peak-to-peak (...)
The caps will charge up to the peak of the AC wave (less the diode drop voltages) while your meter on AC will read the rms value. The picture below should explain it all.
Hi all, How do you estimate or calculate the peak output power that a 500 W transformer in a push pull inverter can supply. 126649 Thanks
Two times 100W is 200W. The efficiency is 90% so the battery must supply 221W. Then a 24V battery must supply 221W/24V= 9.2A. 100W into an 8 ohm speaker needs an amplifier output voltage that is 28V rms which is 79V peak-to-peak. But not from a 24V battery. 100W into a 4 ohm speaker needs an amplifier (...)
not sure, but it sounds like "absolute jitter" might mean peak to peak jitter, which is which you would deived by 2 to get peak jitter, and then again by (2)^1/2 to get rms.
The half-bridge applies 12 V peak-to-peak, so 6 V peak. The secondary will receive 6*(220/9.5) = 140 V peak. Since the DVM is calibrated for sine wave the 74 V reading is not unreasonable even if a little lower than expected. If you can't get a true rms meter, half wave rectify and filter the output, this (...)
You are looking to design a Window Comparator which requires two Comparators with wired OR output low for detecting UV or OV. This requires low ripple or noise inputs, hysteresis, supply filtering and a good low noise reference voltage for comparing the scaled inputs. Define your spec first using rms converted to peak. UV detect le
A problem of the SPICE voltage source specification which is setting the sine peak rather than rms. There's a √2 factor in between.
Another option is to rectify the voltage after transformer. You could measure several samples per half-cycle, and calculate the rms value. I'm assuming that you don't want the peak value, but the true rms. Would not work: Drop voltage across diode would affect result.
hi What are the design equations for the calculation of fly back Converter peak Primary Current Primary Average Current Priamry rms Current How it can be ensured that converter is working in discontinuous mode at all conditions of load?
The CR-C multiplier will be expensive and unreliable with Caps that can handle loads of ripple current. The peak current will be inverse to the allowed ripple, such as 10x at 10% ripple even if just at 10% duty factor. The Cap ripple current may be rated at 110'C with the rated rms current * ESR thus require very large Caps($) The other factor
After taking that samples only i need to find peak+ and peak- voltage and rms calculation . Supposing that it is not expected a broad variation of either voltage and load along time, you can integrate an expressive amount of samples and perform a single calculation. There is some benefit doing that, as explain
This inverter probably was designed to operate with a minimal load so that it is expected to drop a few the output voltage. Make a test to check if the 285v decreases with a load of about 10% of the rated value. Is this voltage obtained using a peak or rms scale ?
The surge current when the motor's magnetics have risen to peak current is limited by the V+/Rs for a winding resistance , Rs . Current starts at 0 when V is applied, reaches a peak and when rotational speed picks up speed, the back EMF generated reduces the current drawn. This surge current is typically 8x max rms rating and the time (...)
1) If the input is a sinewave then 20A rms produces a peak current of 28.28A. Then the peak voltage across the 10 ohms current sensing resistor is 282.8V which is ridiculous. 2) The opamp will not work because it has no part number and it is not powered. 3) The opamp also will not work because its (+) input does not have a DC reference (...)
Hi all; Please i need a very good clarification in regards to the maximum input voltage of an osscilloscope. i just bought one the Rigol1074z which came with the Rigol 2200 probe. the datasheet says at 10x maximum input voltage is 300ACV but i am not really cleared about this if it is rms, peak or peak to peak (...)
C dividers are safer at high voltage and lossless. then decide if delta or Y I sensors may be expensive CT or cheap but custom Hall sensors then scale to your ADC range , add filters and decide if you want Vavg or V pk or true rms and convert accordingly Decide on range, accuracy, and metrics 1st eg. mean, std dev, peak , transient pk, V-sec o
If that's 440V down to 5V rms the peak will be (5 * 1.414) - (2 * Vf) or about 5.8V DC assuming you have added a reservoir capacitor. So to drop it to 2.56 you need a resistive divider with a series to parallel ratio of 1:1.264 You could use a series resistor of 13K and a parallel resistor across the ADC input of 10K. It would be wise to add prote
1) No such thing exists as a Perpetual Motion transformer, power supply or anything over unity in energy ( except in fairy tales and bad measurements by Test Engineering standards) 2) Nowhere is it stated the output is Sinusoidal or even constant rms voltage under load. In fact the peak to rms ( open circuit) voltage is a clue it is n
I wish to know how to setup 230v source from proteus "Generators " - SINE. I worked with dc well. now when I click SINE there are three fields to fill. (I need 230 v ac, 50 hz and also to work with PIC I need 2.30v , 50hz source) 1.offset ? 2. amplitude/peak/rms ? 3. Frequency (I think this is 50hz); VSINE also works the same way w
No, the diode will fail. The parameter you need to observe is 'PIV' or peak Inverse Voltage. The 220V rms will be swinging between about +250V and -250V at it's peaks. If the rectifier is driving a load that does not store any voltage you need diodes rated at a minimum of 250V. If the rectifier has storage after it, for example a (...)
An "Ideal" sawtooth of amplitude A peak-peak has an rms value Vrms= 2A√3 But your waveform is zero for ~10% of the time, so it will be 10% less.
If this ripple is not periodic, you can use a modern oscilloscope that has a recording capability.The oscilloscope will record this non-periodic waveform in a long term time slot and you will able to measure peak-to-peak ( or avarage,rms etc).
My motor rated current is 3a found in name plate it is rms current are peak current regards kalyan This is thermally rated for rms, whereas peak current will depend on load, acceleration and Coil resistance, Rs. *Added 5x .. Depends on winding resistance Often this is 5x-8x steady rated current
Its a bandwidth thing, with CW you have a DC level, with a pulse, you have not, so if its a proper rms detector then the output is down by the mark/space ratio. If its peak measuring (rms calibrated) then it should be OK, providing the circuits have a wide enough bandwidth to handle the narrow pulse width. Frank
A phase angle meter has a Total button and a In-Phase Button The Total Button measures in rms and is the same AC measurement as a DVM meter in AC mode? The In-Phase measures in rms or peak? The In-Phase measures the input voltage in phase with a reference input voltage of the same frequency The Polarity and Magnitude is (...)
hi, Most AC meters are scaled in rms, which is 0.707 * Vpeak. E
2A peak into 8 ohms is 1.414A rms which produces an output of 16W into 8 ohms. The voltage swing is 11.3V rms or 16V peak. Phase delay might be a problem at 20kHz if the frequency of the LC lowpass filter at the output has a cutoff close to 20kHz and you use negative feedback from the speaker to the input.
The voltage rating for a capacitor is its maximum allowed peak DC, which is 1.414 times higher than its sinewave rms maximum voltage rating. So if the voltage to a capacitor is 25VAC then the capacitor must have a voltage rating of at least 35V and a 100V capacitor can be used for good reliability. Note that some types of capacitors are polarized a
Unless there you don't mind measuring Signal + Noise, the appropriate method is to convert peak to rms assuming Sine wave and rms=peak/Root(2) or 0.707 x Vp as Audioguru stated. If you want to eliminate noise, then a tracking filter is needed.
If crest factor depends by modulation (peak and removed modulation) how can people spent time defining crest factor for un-modulated signals as: sine, square, triangle? Above is mentioned that: Crest factor is the peak amplitude of the waveform divided by the rms value of the waveform. You mentioned 6d
To deliver 100mA into 100Kohm you need 10000volts and an output power of 1000 watts. That is rms so for a sinusoidal signal you need 14000volts peak, positive and negative. Even 100mA into 1Kohm needs 100volts rms, 140v peak Give a realistic specification for output current and load impedance. Lower maximum current, (...)
If you connect one leg of the transformer secondary to ground, then you can apply the other leg to the ADC input; BUT you will need to drop the voltage, since the peak voltage will be over 14 volts (5 volts rms is about 14 volts peak-to-peak). You can determine what the peak value of the signal is, and (...)
Hello, I'm building a Fan Control Circuit for controlling the speed of a 380V Fan.(380V rms, ~540V peak-max 150W) using a microcontroller. My main circuit is something similar to this FreeScale Application note : In my circuit, I have a different microcontroller, Op
peak ripple would of course be (Max-min)/2 which is closer to rms noise, but depends on if your interest is thermal noise, clock feedthru or some other noise in the signal. Normally if it is fundamental f or 2f , we call it ripple, otherwise just "noise p-p" covers all types including transient noise.
. It depends on your sampling rate. ADC is linear but your detector is not. Do you want to only track changes in Vac over long term or short term interruptions or do statistics Avearage & deviations ? Choices: quasi rms with peak, P-p or rectified average I would use LPF Noise filter and rectified average with another LPF. 200Hz LPF before br
It doesn't increase - it decreases by the voltage dropped across two of the bridge diodes. The reason you get the apparent increase is because if you fit a reservoir capacitor after the bridge it charges to the peak of the rectified half cycles. If you are using a capacitor, the voltage across it will rise to the rms voltage multiplied by sqrt(2) t
As you know that 220V is basically rms voltage , so in order to get the peak voltage , you have to rectify it (bridge rectifier) followed by a filter stage , which incorporates a inductor and capacitor , or simply a capacitor the output voltage would be 220*root2 = 311v, if you use a large capacitor , the DC waveform would be more smoothen.