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11 Threads found on Pll Instruction
pll feed sequence is always 0xaa followed by 0x55. why is it so. what is the format of pllfeed register in lpc2148. how to configure it. There is No format for feed register when toggling all its bits it starts pll.. 0xAA 10101010 0x55 01010101 sample code void pll_init(void) { pllCF
Hi all, I designed a pll,How can i calculate PM with matlab?what is the instruction?
That isn't strictly true and wouldn't make sense if it was. The CPU clock depends on the settings in the oscillator control register, the pll and configuration fuses. Brian.
It's not always, just for some processor families, e.g. PIC that have fcy = fclk/2 (unless using a pll). It's a matter of processor core design.
Hi, instruction cycle period (TCY) equals four times the input oscillator time base period for all configurations except pll. So what that table is basically saying is do not supply Timer0/1 with a clock pulse faster than the PICs main oscillator / TCY can handle.
you are comparing clock speeds, not instruction speeds. Essentially PIC instruction speed is CLOCK/4 whereas AVR is CLOCK/1. Its easy to favour AVR with its more uniform register usage, makes it easier to optimise compiled code to. PIC18 improves things a bit, and you will notice many have onboard pll to 4x the clock, but because the price (...)
Yes, the macro will setup the FOSC fuses to Fast RC Oscillator with 16x pll, resulting in 120 MHz speed.
Hello guys,,, Could you help me please,,, I want to design pll for mobile wimax application,,, could u give me step by step instruction how to design this. tutorial and/ or papers would be preferable. And i've searching for logic gate and D fli-flop component in ADS, but i've found nothing. can't we simulate dpll in ADs? coz i (...)
If you are not using the pll, the instruction cycle time will be 10MHz / 4. So the timer will increment at 1/2,500,000 times the timer prescaler value. Divide 5mS by this value and you have the count for 5mS. If its a 16 bit timer, subtract this value from 65535 and this is the value you should preload the timer with in the interrupt routine.
The maximum oscillator frequency is 20MHz. Some parts have an internal pll, which allows them to work at up to 40MHz internally. However, one instruction cycle takes 4 oscillator periods, so if the part is running at 20MHz clock, the actual instructions execute at 5MHz (except goto's). That gives you the 200ns/ (...)
Hi some fabless design a "turbo 8051" said 1 clock do 1 instruction , but how to do 1 inst in 1 machine cycle ?(it siad 8051 have 66MIPS clock=66M ) , if 8051 use mov inst must need much more clock .. even use rise/fall edge (but RTL design suggest use only 1 edge for design) .. or then use pll 66M --> high freq for internal 8051 timing