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248 Threads found on edaboard.com: Reset Counter
Your reset isn't active when clk is active so counter is never reset to 0. Don't use names that are only different by the case of the name! This is a big no-no and just makes your code confusing. Also if you develop this bad habit, if you ever start using VHDL all your signals that you named with different cases will be s
I am wondering how to draw a state transition diagram for a two bit counter with the same reset capabilities of a register. I am also wondering if this reset signal is asynchronous what does this change about the output function and is it a Mealy Machine?
hi I write this 2 codes for 4 bits counter. main and testbench module counter4 (input reset, clk, output reg count ); //reg count; always @ (negedge clk) begin if (reset) count <= #3 4'b00_00; else count <= #5 count + 1; end endmodule an
You want to change the middle bit to 0 immediately when the readout is '111'. It is sufficient to detect '11' in the MSB's. Send those bits to your logic gate. Put a diode at its output. Point it in one direction or the other, whichever works. Attach to the 'reset' (I think) of the middle bit. You may find you need to add a pullup or pulldown r
First use rising_edge(clk_128meg_i) instead of the 'event and ... = '1' stuff, it handles 'U'/'Z'/'X' => '1' transitions properly. Your counter cnt_s has no logic to reset back to (others => '0') on the terminal count of 21 (0 to 21) assuming that you mean to index into the fsk_data using a counter. That c
Hi, a really basic question.. therefore only a short answer. Details can be found on a lot of "basic microcontroller" documentations and tutorials. * Power up * power up reset --> setting all internal values to default values * the same is done with the program counter --> itīs value points to the program address where the processing of the prog
A common comparator, counter and a register (both with reset) could be used.
Hello Dave, please find my code below: //counter DESIGN //D FLIPFLOP module dff(clk,reset,din,dout); input clk,reset,din; output dout; logic dout; always@(posedge clk,negedge reset) if(!reset) dout <= 0; else dout <= din; endmodule //counter module (...)
Hi all, I will try to explain my problem in a way that makes sense. I'm trying to write a counter in verilog. There will be a non-periodic pulse that triggers the counter to reset to 0 and start counting again. This is all standard stuff I think. The part that's throwing me off is that when the non-periodic pulse comes in, I also (...)
Please consider a VHDL module which must behave according to the following scenario (clk = clock input; rst = assynchronous reset): 1) clk, rst --> module --> n-position vector with m-bits 2) n: I need sizes such as 20, ..., 50; 3) m: something like 4 or 8 bits To reach this I developed the following code for
hello every one:wink: I have serious problems in writting vhdl structural 4 bit up/down binary counter code by 4 t flip flops.... this is my first code Im so confused and havent enough time. please help and guide me to learn and edit it . thank you so much 124342 library ieee; use
128 seconds sounds like a watchdog timeout. It causes the reset circuits to be triggered internally and forces a jump to the reset vector so it may not be possible to determine the program counter address at the time just before the reset. If you have the watchdog enabled, try turning it off to see if it cures the problem. (...)
Hi, I am using vivado 2015.2.1 . I designed up-down counter. I am getting error. (mentioned below) Find my code below: module counter(reset,clk,uphdnl,count,sseg,an); input wire reset,clk, uphdnl,count; //output reg out0,out1; output reg sseg; output reg an; reg out0_temp,out1_temp; reg
4060 is a ripple counter. Use Logic to reset only to determine counter range. Use more logic if you want < x =1and >x=0 then end of count 1=1=reset Use an adder or some PLD.
4GHz binary counters are all asynchronous like this can get synchronous counters up to 1.4 GHz with async reset, but very
Then go the other direction and load the count with the write_high value and decrement if the count is not equal to 0. You only load the write_high value anytime the UART register is written so it won't restart unless you do another UART write. If you make the write_high UART regisiter the counter then you don't even need to detect the UART write t
hello, I need a counter in verilogA that count the number of pulses in a window of 30KHz. So every 30KHz i need to visualize the number of pulses and reset the counter. Thanks for your help.
I want to build a circuit that scans my 4x4 keypad using a binary counter and a '138 to generate the row scan and then read the results with a '374 which is read by the processor. The counter is clocked with a 555 timer. The counter will have to reset after it reaches 3. The resistors are pull-down. What would I use as a (...)
--------------------------------------------------------------------------------- -- Company: -- Engineer: -- -- Create Date: 14:30:01 05/25/2015 -- Design Name: -- Module Name: count - Behavioral -- Project Name: -- Target Devices: -- Tool versions: -- Description: -- -- Dependencies: -- -- Revision: -- R
hi everyone, I was required to build a stop watch that would count up to 60 and then go back to 0 and start counting again. Also i had to make 2 switches one for the start/stop button another for the reset button. I have completed both the mod 60 and the start and stop button and it is working in multisim. I cant seem to get the reset button to wor