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56 Threads found on edaboard.com: Series Nmos
Hi folks, I have four nmos switches connected in series with flying cap to boost input voltage to higher level ( circuit schematic attached). I am driving them using Arduino which has capability of 20mA/pin, my switches need only 5mA/switch, So I think I don't need a gate drive. The problem I am facing now how to shift the signals for upper swit
nmos cap in Nwell will have better series resistance across the voltage range because you don't just have the channel itself as the bottom plate access path.
A series voltage source between gate and the driving signal would suffice for a simple "different VT". But of course VT is not the only thing that changes across technology nodes.
Hello everyone. I am simulating a very easy circuit with CMOS. It has two pMOS power switches. Each connected to two inverters in series. The circuit looks like below: 121569 So, when the Enable is low, the output should follow input and when enable is high, we are cutting off the power so the output should be low (I
Hello, Attached are LDO regulators with nmos and PMOS pass device . What is the type of feedback used in each case ? Kindly explain this. Is it voltage series, voltage shunt , current series, current shunt type feedback ? Thanks.
The right one (nmos with 2 fingers, too) is the better layout: less input gate series resistance, less parasitic output capacitance, and saves real estate area.
The main virtues of MIM caps are low voltage coefficient and low / low variability series resistance. Both of these are poor on MOS capacitors, for example a high-VT nmos capacitor has negligible C and near infinite ESR when Vgs=0 (channel is "off", which is your connection to the bottom plate). MIM tends to have lower C density (consume more area
Hi all, i do layout of 3 nmos transistors (in 65 nm technology, tsmc), which are connected in series. The bulk of each transistor should be connected to the source of the according transistor. How can I isolate each transistor? Is it right, if I use Deep-nmos transistors, which are enclosed by a NWell-rings? Thanks for any help, (...)
i need the answer of below questions.. consider 2 nmos connected in series source of nmos 1 =vdd; source of nmos 2 =ground; and both nmos was in enable condition. output was taken from drain of both nmos 1 & 2 connecting point..... what about the output...
Your input node i.e. the output of V1 has no DC offset to set the input common mode. You need a DC source same as V10 in series with the AC source.
Guys, I sometimes saw a nmos-connected diode in series with a pmos-connected diode. The circuit is somewhat like the one I put in the attachment. The Vg of M1 is regulated through other circuit, so the current through it goes up and down. I don't quite understand the purpose of having two mosfet diodes there. Can anyone explain this to me?
Sorry if this is in the wrong section, it is my first post :) anyways back to the question, actually heres a picture of the problem. 74722 i calculated unCoxW/L for Q1 to be 960uA/V2 and unCoxW/L for Q2 to be 240uA/V2 now im having trouble/forgot how to find the mode of operation for when th
I'm using Cadence with tsmc 130nm technology file ... and it's my first time ... now I'm facing a weird problem i have built a very simple circuit (an nmos with its drain connected to the gate in series with an ideal current source between VDD and GND) I'm trying to apply the famous saturation current formula to get the process parameters (uCox & l
Why n when nmos OR PMOS r divided? Few days back while designing two input NAND cmos schematic , we used PMOS width = 1.12 n nmos width = 0.98 , so as per Nand cmos structure , two PMOS gates were in parallel and two nmos gates were in series. But we were told to split nmos in two (in parallel) with width (...)
I don't see immediately how the nmos series connection should cause other problems than making the device slow.
I saw this question online but not sure about the reasoning.: - We have two nmos transistors in series and two inputs are coming to the gates. Which transistor should have the faster input coming in, why? Can we put a PMOS transistor in between the two nmos transistor? It serves a specific purpose what is it? (This is the entire question. (...)
SO there is another cool nmos question I cant solve :???: There are two nmos connected in series. Both nmos have Vdd connected to their gates and the output is taken in the middle of the two transistors. Vt = 1v. Vdd = 5v. So what will be the output, what is the region of operation, Can you tell me how it works in the region
Try using a NPN transistor such as the 2N3904 as the switch instead of the nmos. The transistor is current controlled unlike the gate of the nmos which is voltage controlled. Make sure to put a resistor on the base and a resistor in series with the LED.
In case of "NAND", two nmoss are series connected and two PMOSs are paralleled. So it is different from simply interver (PMOS has 3x w/l of nmos's w/l)
Anther way to think about it: It might be caused by no dead time for switching. To solve it, a resistor can be series connected at the front stage inverter. And nmos/PMOS gate at the following stage are connected to the different ends of the resistor. It helps to form some dead time. Hi all, I'm designing digital circ