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11 Threads found on edaboard.com: Startup Ptat
You could start with just what "didn't work" means. A result you didn't like, or failure to produce a result at all? bandgap / ptat loops without explicit startup mechanisms, can easily converge in one testbench and fail in another, because when they start up they're doing so on "numerical noise" which depends on the circuit matrix and algorithm
whether the circuit needn't start-up circuit? It will start up a 1000 times correctly from its own, but it could fail next time, because obviously Vgs of M1 & M2 resp. of M3, M4 & M5 could stay @ 0V , which is a stable condition (you could try with an analysis and such Initial Conditions set). So, y
mastericke is right, you need a loop gain of less than 1. The loop gain is given by gm2/(gm1)(1+gm2*Rs) As you can see, loop gain is guaranteed to be less than 1 in the stable state. You can verify this in simulation by running a transient, making sure that you include a startup circuit to bring the circuit to its stable operating point, c
... If all the nodes are zero, it will never startup Surely it will: When VDD is switched on (even if it rises slowly), C initially provides the necessary startup current. The limiting R isn't necessary, IMHO, because the pmos limits the current anyway. Could you explain it in detail? Why C provides
A ptat current reference circuit is based on the concept of adding (subtracting) vbe voltages. Typically you would use two vbe voltages with different areas and a resistor closing the loop to put the ptat voltage across it. Such a circuit has two stable Operating Points, one of them is with every voltage equal to zero, the other one is the desired
Hi For 1.5V supply I would not use the classical bandgap approach The classical approach will show some serious problems in the low-temp/slow corners, especially during startup ... Look out for some papers about low voltage bandgaps. The basic idea there is, that you add a ptat and an iptat current. THis current is injected into a (...)
Hi, Are you having the issue in simulation(pre tapeout) or in Silicon ?I think bandgap is a self biased circuit and hence the circuit will either operate as desired (with required current mirroring + bg voltage generation etc) or will not startup. So in general , a startup circuit is added in bandgap so that it does start up. Now assuming you h
Transient is the only way to do startup sims. You should ramp Vdd very slowly (1 second for 0-3.3v for example) and watch to make sure your circuit starts. Cold is usually worse if your circuit uses ptat currents since they are smaller at cold. Slower ramps are always worst case, because some circuits get "knocked into startup" by (...)
Increase your startup helper current injection and switch it off after the bandgap reach near its full voltage.
If the A or B is used as bias for gate of ptat current, i think the circuit will not work. Generally , the statup circuit generates the current for core circuit, once the core circuit work normally , the startup circuit is isolated from the core circuit. AS you draw , the A or B will effect the core circuit when the core circuit work normall
The main circuit is the ptat core. It is enclosed into a regulation loop which try to equalize the currents I1 and I2. The resulting current Iptat=I1=I2 is the ptat current. The equations for the ptat circuit is I1*R+VT*ln(I1/(a*IS))=VT*ln(I2/IS), "a" emitter area ratio the solution for I1=I2 is (...)