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15 Threads found on edaboard.com: Venable
I found the circuit for Type2 compensator in the following link I would like to know the relationship of OUT with IN and Vref (Fig.7)
There's no one general solution to this, because the system you're trying to compensate may have any sort of transfer function. The method I prefer is the K factor method described here. Basically you pick a desired crossover f
Having a crossover frequency lower than the input filter resonance frequency can help ensure that the system is stable, but it also means that there will be greater feedthrough from input to output in the band between the crossover frequency and the input filter cutoff frequency. A well-designed supply will have the input filter resonant frequency
"The problem with a conditionally stable system is that something may cause a gain decrease, for example increased load or decreased line voltage, and this could cause the system to go unstable. This is why conditionally stable systems are testing Power Sources For Stability generally to be avoided, although there are advantages to
First I recommend reading the following appnotes from venable tech: For loop compensation, you need to decide on what loop bandwidth and phase margin you need. For a given supply circuit, there are practical limitations on what can be achieved.
I kind of doubt that there are companies that specialize in that, but there are companies like venable Industries that make instruments for that purpose, or you could probably contract it out to a general engineering firm. It's really not hard to do yourself. venable has tech notes that pretty much describe exactly how it's done.
see pg. 3 at the bottom : A negative inductor is a capacitor whose impedance increases with increasing frequency. This is potentially a useful element for modeling bizarre impedances. Also see an article about a Hartley oscillator:
It looks like a forward converter without reset wiring. Please check your schematic. For your question, the voltage loop may need compensation; at mean while, your current loop may or may not need a compensation slope for current loop stability. Look up the current mode control material or text book. Couple links for your reference ece-w
Why UC384X need to this compensation if duty greater than %50? see this link: stefano
Go
It looks pretty normal (see data sheet, electrical characterisctics: ) .. Try to set venable=L (0V) and the quiescent current consumption should drop below 20mA .. Regards, IanP
Try this paper: "Current Mode Control" Regards, IanP BTW, VVV has done great job !!!
another agood:
pls.. check .. It may be useful to some extent Why not just post a link? You can get that book here the eda upload book section "switching" find several books on SMPS. Also check here. www.venab
HOPE INTERESTIN'