Search Engine

Vhdl Testbench Clock

Add Question

31 Threads found on Vhdl Testbench Clock
Hallo, I have simulated the following code using ModelSim. library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity fifo_SCnt is generic( RAMsize: integer := 256; DataWidth: integer := 8 ); port( clk: in std_logic; rst: in std_logic; data_in: in std_logi
How about using a counter with a 10 Hz clock (1 ms period) or use whatever system clock you have, e.g. 100 MHz clock and create a counter that counts from 0-9,999,999-0 and increment a second counter when you reach 9,999,999 (or at 0,000,001 for a starting increment). Instead of giving the simulator lots of work to do
LIBRARY IEEE; USE ieee.std_logic_1164.all; --USE ieee.std_logic_arith.all; USE ieee.numeric_std.all; library ieee_proposed; use ieee_proposed.fixed_pkg.all; ENTITY dwt IS PORT ( clk : IN STD_LOGIC; vid_in: IN STD_LOGIC_VECTOR(7 DOWNTO 0); -- Pixels from main memory hor_sync: IN STD_LOGIC;
I am trying to write a code in vhdl with a given time period of clock in testbench .When i execute it i get proper output , but if i modify the code slightly i.e including more functions (more operations) then although am not changing anything in the test bench , but still i the clock in the test bench waveform appears to (...)
Hello All, I am engineering student i want write a code in vhdl go get the simulations as per the picture attached and tried doing that but not getting please help me with the code. thankyou, 123503 123504 library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_UNSIG
hello, Why the following testbench code in the first clock d1, d2 are value And the second clock a, b library IEEE; use ieee.std_logic_1164.all; use IEEE.STD_LOGIC_UNSIGNED.ALL; use ieee.numeric_std.all; use IEEE.MATH_REAL.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; use IEEE.STD_LOGIC_TEXTIO.ALL; library std; use std.textio.all; --in
Hello, x is defined as: signal x: std_logic_vector ( 7 downto 0 ) ; I want 'x' to be incremented by 1 with relation to the simulation time - for example: "00000000" at time: 10 ns "00000001" at time: 20 ns "00000010" at time: 30 ns The obvious will be: x <= "00000000" after 10 ns , "00000001" after 20 ns , "
Hi friends I have the Test Enable signal(TE) 111680 which should be write in vhdl, clkperiod : integer := 4; -- system clock period signal clk : std_logic := '0'; signal te : std_logic := '0'; constant ct : integer := clkperiod/2; clk is already written Can I k
It looks like you are missing a text book like "vhdl for hardware design" or similar. As previously stated, none of the testbench/simulation timing statements works for hardware synthesis. You need to think your design in terms of synthesizable elements, flip-flops and combinational logic. Use a synchronous scheme with a single input (...)
I am trying to convert this vhdl testbench code to verilog testbench, kindly help me to convert this part of code slave_clkedge <= '1' when SLAVE_CPHA = SLAVE_CPOL else '0'; -- Define a 3-bit counter to count SCK edges and data into register so that parallel -- register is loaded. Use same clock (...)
yeah, i did. the code works fine, i just wanted to know if the way i did it is OK. im interesting to know what is my professor's problem with this particular way of solution and why does he think that using function vs components is such a big deal. maybe i just can't see it but my code is awful, hoped someone could tell m
in simulation a code for QAM mapping used in OFDM .. the code is working great but i have a problem the output is shifted by one clock the output that should appear in clk 1 with input11 appears in clk 2 with input 2 and so on the code is this is not clearly my code :) library IEEE; use IEEE.STD_LOGIC_1164.all; use IEEE.STD_LOG
Hi, I saw your replies in the forum and felt encouraged to post this question. Thanks for providing your expertise. I have a vhdl test bench that is associated with both implementation and simulation (as I would like to run P&R simulation). I just want to define my clock with a certain time period. Say clock = '1', wait for (...)
1. Yes 2. Its a lot easier to do these checks inside your HDL testbench. For vhdl, the quickest and dirtiest way to stop a testbench is: assert (not end_of_sim) report "Simulation finished!" severity failure; Although the cleanest way is to stop all stimulus - ie. halt input processes and turn the clock off. 3. You cant (...)
hello, I'm trying to creaet a test bench for my program which I wrote in vhdl all my inputs are stored in an array, so I don't have any input declared in the entity that makes me wonder how I can change the value in my test bensh, note that in my module I have a FOR LOOP, and some IF condition, how can I integrate it in the test bench??
im trying to display a red box on a 640 by 480 screen however nothing is displayed on my vga screen im using nexys 3 and these were the port used clk v10 ns-n6 vs -p7 red1 -u7 green2 - p8 blue2 -r7 here under is my code which i made thanks i appriate any help library IEEE; use IEEE.std_logic_1164.all; use IEEE.std_logic_arith.all;
Hi all, one of my vhdl modules produces "X" values even with the slowest clock; there were no problems with its behavioral simulation though. Here's the code; basically it's an adder (it sums its single data input A2 to a constant FO1 after reshaping A2 into the variable A1) whose output is forced to 0 if the result is negative ent
I guess, the problem is missing knowledge of the vhdl textio package. Generally ASCII formatted data files are a straightforward way to read in stimulation data. You'll read e.g. one line for each clock cycle in your testbench, and decode one or multiple values and assign it to the stimulus vector. The testbench scans (...)
Hello, I have designed that code. you can find it on
My vhdl program seems to work when I remove the external clock, but when I add the clock to the RS 232 Reciever Code, It doesn't work anymore in the testbench. I'm trying to make a UART application, PC to Spartan 3E, my PC (hyperterminal is set to 9600 baud rate) so I have to supply the clock RX DCE from (...)