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45 Threads found on edaboard.com: Wait Statement
i_read_en <='1'; i_data <= mem(to_integer(r_reg)); wait for 6000 ns; These are not concurrently running statements they are sequential (a program) so it executes i_data <= mem(to_integer(r_reg)); once then sits there at the wait for 6000 ns; statement for 6000 ns of time before executing the next (...)
@(posedge ticker) is not synthesizable, it's only used in simulation testbenches as an event control to wait until the rising edge of a signal. For edge triggered logic that is synthesizable you have to use always @ (posedge ticker) if you want to synthesize the module. This is a bad design as ticker is used as a clock when
Hi there, i am a new engineer who is trying to learn FPGA programming. As a project i am trying to implement a digital thermometer using a spartan3e FPGA board and DS1822 chip which uses 1-wire protocol. For starters i am just trying to implement the preset and present pulses between the devices but when i try to test my code simulation gets stu
"wait" statement cannot be synthesis ...
VHDL for loops are unrolled, they are not software for loops. You should be using a counter and a while loop until the count reaches terminal count. Not exactly sure how the for loop would deal with the wait for 10 ns; statement, I suspect it's ignored, but would have to actually try a test case to be sure. Act
with flip-flops and the the clock used to drive the signals shown? i.e. wait (delay) isn't synthesizable. Based on your question I think you are attempting to write software (the wrong way) instead of hardware (the right way).
Do you hear at all? Timing statements, e.g. wait with timeout are not synthesizeable. Please review post #17.
That is testbench code, and the error indicates you are trying to synthesise it (which you cant) or there is no wait statement in the process. I cant see all the code - is there a wait statement?
@(posedge a) is just a timing statement. Ie. wait until the next rising edge of a. always @(posedge a) means the code here will be executed for every rising edge of a. Hence why you cannot put an always in a task, as a task is meant to be called externally, not have code looping forever.
I assume you know this code is not synthesisable as a single wait statement is no use for synthesis, it is for simulation only. So is the real type. This code looks far to much like software code, and hence will never work. I suggest finding a good text book on digital logic design. Working through the exercises and starting your code again. Befor
A terminating wait statement should stop further process schedule.
Yes, a netlist is just a list of nodes and what is connected to each of them. It is only a connection list, it holds no representation of the schematic or logic diagram layout. Back annotation is the process of automatically going through a netlist and updating it when a change has been made to the schematic. For example, if you renumbered gates/c
c) and d) are both guaranteed to pass because each event executes in a separate active queue. a) and b) are both race conditions because all three events are generated in the same active queue. There's no guaranteed ordering how those events will show up in the separate thread containing wait_order statement. However, I'm guessing most imple
for the solution of this u can use goto statement and let the arduino wait for command check this out i have rewritten the code with ur requirement void int() { val=digitalRead(pinB); // read data one: if(pinB == HIGH) { Serial.println("PINA ON"); //write serially goto two;} else {goto one; two: if(pinB == LOW) {
Hi, I saw your replies in the forum and felt encouraged to post this question. Thanks for providing your expertise. I have a VHDL test bench that is associated with both implementation and simulation (as I would like to run P&R simulation). I just want to define my clock with a certain time period. Say clock = '1', wait for 2.5ns.....clock
#20 means "wait 20 time units before proceeding to execute the immediately following statement". #20; means "wait 20 time units before proceeding to execute the immediately following statement, and oh BTW the immediately following statement is the empty statement". "Empty (...)
wait statement is not possible in synthesizable RTL/
Have you considered using wait statement instead of the assignment delay? wait (expression) statement
Hi All, I am just stumbled with one of the process that i need to execute for my current assignment? I tried above method what is mentioned in question but didn't worked out. Can anyone provide me an easiest way out for following function: I have to write testcases in verilog for my VHDL based DUT.. This testcases should generate rand
hi I wrote a program counter on that counter program is running in between i have to stop by pressing a switch for this i wrote this code void main() { // for(p0=0x00;p0<=0xf0;p0++) { wait(500); if(c1=0) //<---------------c=0 is a an assignment statement break; } } Here c1 act as