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62 Threads found on Zero Ohm
Hi all, I am working on an instrumental device with a single supply. I need an OPAMP with zero output when it is in the low state. I mean VOUT-VSS=0V or at least below 5mv at 1mA. Is there any chip providing this? if not, is there any method to compensate deviation? Thanks
Arcol has published inductance specifications for their similar HS power resistor series. You'll see that resistor values below 100 ohm have usually an ESL/R zero below 1 MHZ. I didn't yet see a specification for low-inductance series.
An off state, more accurately called recessive state, is zero volts across the differential pair CANH and CANL, as long as there is a 120 ohm termination resistor.
if output is collector, Zout is very high only due to leakage // Rc of the current sink. (NPN) so Zout on CB and CE is the same but ends being just the load resistor only. Base Input Zin=hFE*(Rbe + Re) where the latter is chosen to be larger than Rbe. So it can be high with a Darlington or low with Re= zero ohm Emitter impedance, Ze is the
Obviously there can't be a percent tolerance for a zero ohm resistor. Which entry do you expect to see in this place? You may find an absolute resistance tolerance (maximum jumper resistance) in detailed data sheets.
Aye, it *is* 'grounded'... at DC ;) Whilst certainly not universal, it isn't uncommon for RF components to have DC input/output resistances that appear to be near zero ohms. The key thing is at the intended operating frequency the input/output impedance is a specified value, with 50 and 75 ohms being typical. The scenario you observed
Oscillator output connected through 4 resistors with the rest of schematic: first resistor is "510" (can understand that as matching with 50 ohm), then three "000" resistors. Why putting three zero ohm resistors? Some voodoo impedance matching of unperfect 50 ohm resistor? Here is the image: 110462 From right to left
Start with 1 port, then 2 port then 3 port. It;s all based on KIrchhoff's Laws but zeroing the terms that are excluded.
How do we calculate the wattage of a zero ohm resistor.? My purpose is to use them in 230V AC lines which may carry maximum 600mA. How should i choose the resistor?
You can plot the current through every device. Or you could insert a 0Ω resistor and plot the current through it. Zorro, I suppose you mean a zero voltage source, correct? My simulator doesn´t accept a 0 ohm resistor.
Brad gave an excellent response ( pun intended) to the question not asked, What RC and RL equivalent circuits give the same frequency response , assuming a zero ohm source impedance and open circuit load.
Logic tells me a 11W load @ 220V would draw 50 mA , which is pretty close to 47 point zero. You would need 5% tolerance of gold with 10% tolerance on voltage and low line would increase the chances of blowing the fuse if on full brightness. Normally the CFL draws more current near end of life , so the fuse is the protection for the switcher and a
i tested the attached circuit again but i forgot to connect pin3 ( red circle ) the chip got hot and burnt up for the second time . i don't know why . also i measured the signal on zero ohm resistor it was 8.3 mv the output was .83 volt which mean that the gain is 101 not 51 however gain=1+1000/20 = 51 , i also tried another resistor and i got t
You have no node zero, probably because you have used the wrong GND symbol. Change your GND symbol for the correct one or add a zero voltage source or zero ohm resistor from GND to node zero. Keith
If you short a current source you still get the current source current. So a perfect 1A current source will deliver 1A whatever the load - zero or 1M ohm. A real current source will not be quite as good. Keith
You are confused because, in the real world, there is NO power supply that can deliver a constant voltage and a constant current to ANY load. Let us take two clear examples: (1) Let us suppose the load is a short circuit (almost zero ohm). What do you expect the voltage of the power supply output would be? (2) And if the load is an open circ
1. The left bottom wire is labelled 'gnd', even though there is no symbol for ground evident. Is that wire definitely connected to ground? 2. Sometimes you need to put resistors (low ohm or zero ohm) in series with a capacitor or coil, to prevent the simulator from generating an error.
Avalanche operation with zero bias is like mountaineering on the sea. Good luck! :smile: Besides specified bias, a suitable load, e.g. 50 ohm resistor (passive) or TIA (active), is required.
In order to evercome this problem put a zero ohm resistor between two.. Spectre doesn't love something floating,shorted,open circuited etc.
well, it has 5 ports. so if you replace the 2 50 ohm loads with 2 power sensors, then any imbalance will show up as non-zero power at one of the detectors.